Chapter 9.2, Problem 20PP

Interpretation Introduction

Interpretation:

The chemical equation for the given decomposition reaction needs to be written.

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products.

A chemical equation is balanced by balancing the number of moles of each element on the reactants and on the products.

Answer to Problem 20PP

The chemical equation is as follows:

$\text{2}{\text{NaHCO}}_{\text{3}}\left(\text{s}\right)\to {\text{Na}}_{\text{2}}{\text{CO}}_{\text{3}}\left(\text{s}\right)\text{+}{\text{H}}_{\text{2}}\text{O}\left(\text{g}\right)\text{+}{\text{CO}}_{\text{2}}\left(\text{g}\right)$

Explanation of Solution

In the reaction, solid sodium hydrogen carbonate is heated to produce sodium carbonate and water. Carbon dioxide is also produced in the reaction.

The chemical equation for the reaction will be:

${\text{NaHCO}}_{\text{3}}\left(\text{s}\right)\to {\text{Na}}_{\text{2}}{\text{CO}}_{\text{3}}\left(\text{s}\right)\text{+}{\text{H}}_{\text{2}}\text{O}\left(\text{g}\right)\text{+}{\text{CO}}_{\text{2}}\left(\text{g}\right)$

The balanced chemical equation will be:

$\text{2}{\text{NaHCO}}_{\text{3}}\left(\text{s}\right)\to {\text{Na}}_{\text{2}}{\text{CO}}_{\text{3}}\left(\text{s}\right)\text{+}{\text{H}}_{\text{2}}\text{O}\left(\text{g}\right)\text{+}{\text{CO}}_{\text{2}}\left(\text{g}\right)$

This reaction is a decomposition type reaction. It is because in a decomposition reaction, a compound breaks down to generate two or more than two new compounds or elements.

Conclusion

The chemical equation of the reaction is,

$\text{2}{\text{NaHCO}}_{\text{3}}\left(\text{s}\right)\to {\text{Na}}_{\text{2}}{\text{CO}}_{\text{3}}\left(\text{s}\right)\text{+}{\text{H}}_{\text{2}}\text{O}\left(\text{g}\right)\text{+}{\text{CO}}_{\text{2}}\left(\text{g}\right)$

This reaction is a decomposition type reaction.