Chapter 9.2, Problem 19PP

Interpretation Introduction

Interpretation:

The chemical equation for the decomposition of Nickel (II) hydroxide needs to be written.

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products.

A chemical equation is balanced by balancing the number of moles of each element on the reactants and on the products.

Answer to Problem 19PP

Chemical equation of the given reaction is as follows:

$\text{Ni}{\left(\text{OH}\right)}_{\text{2}}\left(\text{s}\right)\to \text{NiO}\left(\text{s}\right)\text{+}{\text{H}}_{\text{2}}\text{O}\left(\text{l}\right)$

Explanation of Solution

Chemical equation of the reaction is, $\text{Ni}{\left(\text{OH}\right)}_{\text{2}}\left(\text{s}\right)\to \text{NiO}\left(\text{s}\right)\text{+}{\text{H}}_{\text{2}}\text{O}\left(\text{l}\right)$

The above reaction is balanced.

This reaction is a decomposition type reaction. It is because in a decomposition reaction, a compound breaks down to generate two or more than two new compounds or elements.

Conclusion

The chemical equation of the given reaction is, $\text{Ni}{\left(\text{OH}\right)}_{\text{2}}\left(\text{s}\right)\to \text{NiO}\left(\text{s}\right)\text{+}{\text{H}}_{\text{2}}\text{O}\left(\text{l}\right)$

In this reaction, Nickel (II) hydroxide (s) decomposes to produce nickel (II) oxide (s) and water. So, it is a decomposition reaction.