Chapter 9, Problem 72A

Interpretation Introduction

(a)

Interpretation:

The skeleton equation for the reaction needs to be written.

$\text{lithium}\left(\text{s}\right)\text{+}\text{gold}\left(\text{III}\right)\text{chloride}\left(\text{aq}\right)\to \text{lithium}\text{chloride}\left(\text{aq}\right)\text{+}\text{gold}\left(\text{s}\right)$

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products. There are many ways to show a chemical reaction, skeleton equation, word equation and chemical equation.

Answer to Problem 72A

The skeleton equation for the reaction,

$\text{lithium}\left(\text{s}\right)\text{+}\text{gold}\left(\text{III}\right)\text{chloride}\left(\text{aq}\right)\to \text{lithium}\text{chloride}\left(\text{aq}\right)\text{+}\text{gold}\left(\text{s}\right)$ is,

$\text{Li}\left(\text{s}\right)\text{+}{\text{AuCl}}_{\text{3}}\left(\text{aq}\right)\to \text{LiCl}\left(\text{aq}\right)\text{+}\text{Au}\left(\text{s}\right)$

Explanation of Solution

To determine the skeleton equation for a reaction, one must know the chemical symbols of elements and compounds. A skeleton equation shows the reactants and products using the chemical formula of them and the balancing of the reaction is not required.

The formula of lithium, gold and chlorine is Li, Au and Cl respectively.

So, the skeleton equation is,

$\text{Li}\left(\text{s}\right)\text{+}{\text{AuCl}}_{\text{3}}\left(\text{aq}\right)\to \text{LiCl}\left(\text{aq}\right)\text{+}\text{Au}\left(\text{s}\right)$

(b)

Interpretation Introduction

Interpretation:

The skeleton equation for the reaction needs to determined.

$\text{iron}\left(\text{s}\right)\text{+}\text{tin}\left(\text{IV}\right)\text{nitrate}\left(\text{aq}\right)\to \text{iron}\left(\text{III}\right)\text{nitrate}\left(\text{aq}\right)\text{+}\text{tin}\left(\text{s}\right)$

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products. There are many ways to show a chemical reaction, skeleton equation, word equation and chemical equation.

Answer to Problem 72A

The skeleton equation for the reaction

$\text{iron}\left(\text{s}\right)\text{+}\text{tin}\left(\text{IV}\right)\text{nitrate}\left(\text{aq}\right)\to \text{iron}\left(\text{III}\right)\text{nitrate}\left(\text{aq}\right)\text{+}\text{tin}\left(\text{s}\right)$ is,

$\text{Fe}\left(\text{s}\right)\text{+}{\text{SnNO}}_{\text{3}}\left(\text{aq}\right)\to {\text{FeNO}}_{\text{3}}\left(\text{aq}\right)\text{+}\text{Sn}\left(\text{s}\right)$

Explanation of Solution

To determine the skeleton equation for a reaction, one must know the chemical symbols of elements and compounds. A skeleton equation shows the reactants and products using the chemical formula of them and the balancing of the reaction is not required.

The formula of iron, tin and nitrate is Fe, Sn and ${\text{NO}}_{\text{3}}$ respectively.

So, the skeleton equation is,

$\text{Fe}\left(\text{s}\right)\text{+}{\text{SnNO}}_{\text{3}}\left(\text{aq}\right)\to {\text{FeNO}}_{\text{3}}\left(\text{aq}\right)\text{+}\text{Sn}\left(\text{s}\right)$

(c)

Interpretation Introduction

Interpretation:

The skeleton equation for the reaction needs to be written.

$\text{nickel}\left(\text{III}\right)\text{chloride}\left(\text{s}\right)\text{+}\text{oxygen}\left(\text{g}\right)\to \text{nickel}\left(\text{II}\right)\text{oxide}\left(\text{s}\right)\text{+}\text{dichlorine}\text{pentoxide}\left(\text{g}\right)$

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products. There are many ways to show a chemical reaction, skeleton equation, word equation and chemical equation.

Answer to Problem 72A

The skeleton equation for the reaction,

$\text{nickel}\left(\text{III}\right)\text{chloride}\left(\text{s}\right)\text{+}\text{oxygen}\left(\text{g}\right)\to \text{nickel}\left(\text{II}\right)\text{oxide}\left(\text{s}\right)\text{+}\text{dichlorine}\text{pentoxide}\left(\text{g}\right)$ is,

${\text{NiCl}}_{\text{2}}\left(\text{s}\right)\text{+}{\text{O}}_{\text{2}}\left(\text{g}\right)\to \text{NiO}\left(\text{s}\right)\text{+}{\text{Cl}}_{\text{2}}{\text{O}}_{\text{5}}\left(\text{aq}\right)$

Explanation of Solution

To determine the skeleton equation for a reaction, one must know the chemical symbols of elements and compounds. A skeleton equation shows the reactants and products using the chemical formula of them and the balancing of the reaction is not required.

The formula of nickel, chlorine and oxygen is Ni, Cl and ${\text{O}}_{\text{2}}$ respectively.

So, the skeleton equation is,

${\text{NiCl}}_{\text{2}}\left(\text{s}\right)\text{+}{\text{O}}_{\text{2}}\left(\text{g}\right)\to \text{NiO}\left(\text{s}\right)\text{+}{\text{Cl}}_{\text{2}}{\text{O}}_{\text{5}}\left(\text{aq}\right)$

(d)

Interpretation Introduction

Interpretation:

The skeleton equation for the reaction needs to be determined.

$\text{lithium}\text{chromate}\left(\text{aq}\right)\text{+}\text{barium}\text{chloride}\left(\text{aq}\right)\to \text{lithium}\text{chloride}\left(\text{aq}\right)\text{+}\text{barium}\text{chromate}\left(\text{s}\right)$

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products. There are many ways to show a chemical reaction, skeleton equation, word equation and chemical equation.

Answer to Problem 72A

The skeleton equation for the reaction,

$\text{lithium}\text{chromate}\left(\text{aq}\right)\text{+}\text{barium}\text{chloride}\left(\text{aq}\right)\to \text{lithium}\text{chloride}\left(\text{aq}\right)\text{+}\text{barium}\text{chromate}\left(\text{s}\right)$ is,

${\text{Li}}_{\text{2}}{\text{CrO}}_{\text{4}}\left(\text{aq}\right)\text{+}{\text{BaCl}}_{\text{2}}\left(\text{aq}\right)\to \text{LiCl}\left(\text{aq}\right)\text{+}{\text{BaCrO}}_{\text{4}}\left(\text{s}\right)$

Explanation of Solution

To determine the skeleton equation for a reaction, one must know the chemical symbols of elements and compounds. A skeleton equation shows the reactants and products using the chemical formula of them and the balancing of the reaction is not required.

The formula of lithium, chromium, barium, oxygen and chlorine is Li, Cr, Ba, ${\text{O}}_{\text{2}}$ and Cl respectively.

So, the skeleton equation is,

${\text{Li}}_{\text{2}}{\text{CrO}}_{\text{4}}\left(\text{aq}\right)\text{+}{\text{BaCl}}_{\text{2}}\left(\text{aq}\right)\to \text{LiCl}\left(\text{aq}\right)\text{+}{\text{BaCrO}}_{\text{4}}\left(\text{s}\right)$