Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
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Chapter 9, Problem 9.87QE

(a)

Interpretation Introduction

Interpretation:

The approximate enthalpy change for the reaction of molecular hydrogen and molecular oxygen to produce 2 moles water vapor has to be determined.

  2H2(g)+O2(g)2H2O(g)

Concept Introduction:

The bond dissociation energy or bond energy (D) is defined as energy needed to break one mole of bonds in a gaseous species.

The equation that describes the bond dissociation for H2 is as follows:

  H2(g)H(g)+H(g)

Bond energies are always endothermic and have a positive sign. It takes energy to break a bond.

The enthalpy of reaction can be determined by the sum of the bond dissociation energies of all the reactants minus the sum of the bond dissociation energies of all products present in chemical reaction.

The equation to calculate enthalpy of reaction is as follows:

  ΔHreaction=[(moles of bond broken×bond energies of bond broken)(moles of bond formed×bond energies of bond formed)]

Negative sign in the equation depicts that bonds will form in the products. It is an exothermic process, so the energy charge is the negative of bond energy.

(b)

Interpretation Introduction

Interpretation:

The approximate enthalpy change for the reaction of carbon monoxide and molecular oxygen to form 2 mol of carbon dioxide has to be determined.

Concept Introduction:

Refer to part (a).

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Chapter 9 Solutions

Chemistry: Principles and Practice

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Types of bonds; Author: Edspira;https://www.youtube.com/watch?v=Jj0V01Arebk;License: Standard YouTube License, CC-BY