Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
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Chapter 9, Problem 9.7QE
Interpretation Introduction

Interpretation:

The reason for the formula of NaF to not be NaF2 has to be determined.

Concept Introduction:

Lattice energy is used to determine the bond strength in ionic compounds. It is the heat of formation for ions of opposite charge in the gaseous phase combine to form an ionic solid.

Lattice energy is the energy required to separate a mole of an ionic solid into gaseous ions. It cannot be measured empirically but it can be estimated by the Born-Haber cycle.

  MX(s)M+(g)+X(g)

The two main factors responsible for the magnitude of the lattice energy are the charge and radius of the bonded ions. The effect of those factors is as follows:

1. If the charge of the ions increases, the lattice energy increases.

2. If the size of the ions increases, the lattice energy decreases.

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Use the Born-Haber cycle to calculate the lattice energy of KF. [The heat of sublimation of K is 91.6 kJ·mol−1 and  ΔfH(KF) = −567.3 kJ·mol−1.  Bond enthalpy for F2 is  158.8 kJ·mol−1.  Other data may be found in the Ionization Energies Table and the Electron Affinities Table.]
Based on the following information calculate the approximate lattice energy of MgCl2.   The radius of Na+ is 1.5 times as large as Mg2+.  The lattice energy for NaCl is  787 kJ/mole.
Write the steps (reactions) for the Born-Haber cycle for MgCl2(s). Use the Born-Haber cycle to calculate the lattice energy of MgCl2(s). Some useful data to work with: For Mg: ΔΔHsub = 147 kJ/mol, IE1 and IE2 are 738 kJ/mol and 1450 kJ/mol, respectively. For chlorine: Bond energy = 243 kJ/mol, EA1 = -349 kJ/mol, respectively. The enthalpy of formation of magnesium chloride is -748.8 kJ/mol.

Chapter 9 Solutions

Chemistry: Principles and Practice

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