An array of electronic chips is mounted within a sealed rectangular enclosure, and cooling isimplemented by attaching an aluminum heat sink ( k = 180 W/m ⋅ K ) . The base of the heat sink has dimensions of w 1 = w 2 = 100 mm, while the 6 fins are of thickness t = 10 mm and pitch S = 18 mm . The fin length is L f = 50 mm, and the base of the heat sink has a thickness of L b = 10 mm . If cooling is implemented by water flow through the heat sink, with u ∞ = 3 m/s and T ∞ = 17 ° C, what is the base temperature T b of the heat sink when power dissipation by the chips is P elec = 1800 W? The average convection coefficient for surfaces of the fins and the exposed base may be estimated by assuming parallel flow over a flat plate. Properties of the water may be approximated as k = 0.62 W/m ⋅ K, ρ = 995 kg/m 3 , c p = 4178 J/kg ⋅ K, v = 7.73 × 10 − 7 m 2 /s, and Pr = 5.2.
An array of electronic chips is mounted within a sealed rectangular enclosure, and cooling isimplemented by attaching an aluminum heat sink ( k = 180 W/m ⋅ K ) . The base of the heat sink has dimensions of w 1 = w 2 = 100 mm, while the 6 fins are of thickness t = 10 mm and pitch S = 18 mm . The fin length is L f = 50 mm, and the base of the heat sink has a thickness of L b = 10 mm . If cooling is implemented by water flow through the heat sink, with u ∞ = 3 m/s and T ∞ = 17 ° C, what is the base temperature T b of the heat sink when power dissipation by the chips is P elec = 1800 W? The average convection coefficient for surfaces of the fins and the exposed base may be estimated by assuming parallel flow over a flat plate. Properties of the water may be approximated as k = 0.62 W/m ⋅ K, ρ = 995 kg/m 3 , c p = 4178 J/kg ⋅ K, v = 7.73 × 10 − 7 m 2 /s, and Pr = 5.2.
Solution Summary: The author explains the base temperature of the heat sink and the power dissipation by the chip.
An array of electronic chips is mounted within a sealed rectangular enclosure, and cooling isimplemented by attaching an aluminum heat sink
(
k
=
180
W/m
⋅
K
)
.
The base of the heat sink has dimensions of
w
1
=
w
2
=
100
mm,
while the 6 fins are of thickness
t
=
10
mm
and pitch
S
=
18
mm
.
The fin length is
L
f
=
50
mm,
and the base of the heat sink has a thickness of
L
b
=
10
mm
.
If cooling is implemented by water flow through the heat sink, with
u
∞
=
3
m/s
and
T
∞
=
17
°
C,
what is the base temperature
T
b
of the heat sink when power dissipation by the chips is
P
elec
=
1800
W?
The average convection coefficient for surfaces of the fins and the exposed base may be estimated by assuming parallel flow over a flat plate. Properties of the water may be approximated as
k
=
0.62
W/m
⋅
K,
ρ
=
995
kg/m
3
,
c
p
=
4178
J/kg
⋅
K,
v
=
7.73
×
10
−
7
m
2
/s,
and
Pr
=
5.2.
This is an old practice exam. Fce = 110lb and FBCD = 62 lb but why
Quiz/An eccentrically loaded bracket is welded to the support as shown in Figure below. The load is static. The weld size
for weld w1 is h1 = 4mm, for w2 h2 = 6mm, and for w3 is h3 =6.5 mm. Determine the safety factor (S.f) for the welds.
F=29 kN. Use an AWS Electrode type (E100xx).
163 mm
S
133 mm
140 mm
Please solve the question above
I solved the question but I'm sure the answer is wrong
the link :
https://drive.google.com/file/d/1w5UD2EPDiaKSx3W33aj
Rv0olChuXtrQx/view?usp=sharing
Q2: (15 Marks)
A water-LiBr vapor absorption system incorporates a heat exchanger as shown in
the figure. The temperatures of the evaporator, the absorber, the condenser, and the
generator are 10°C, 25°C, 40°C, and 100°C respectively. The strong liquid leaving
the pump is heated to 50°C in the heat exchanger. The refrigerant flow rate through
the condenser is 0.12 kg/s. Calculate (i) the heat rejected in the absorber, and (ii) the
COP of the cycle.
Yo 8
XE-V
lo
9
Pc
7
condenser
5
Qgen
PG
100
Qabs
Pe
evaporator
PRV
6
PA
10
3
generator
heat exchanger
2
pump
185
absorber
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