Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Textbook Question
Chapter 5, Problem 17RQ
Other than increasing strength, for what three purposes are nonferrous metals often heat treated?
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QUESTION 4
A method of determining the result of heat treatment as well as the state of a metal prior to heat treatment
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I. Martensitic stainless steels are capable of being heat treated
II. Austenitic Stainless Steels are the most corrosion resistant because of the high chromium contents
III. Ferritic Stainless Steels are hardened and strengthened by cold work
Which statement(s) is/are true given above about stainless steels?
When performing a quench to cool a product, the quench rate affects the outcome of the process. TRUE OR FALSE:
3 principal driving forces for the development of mechanical properties during heat treatment.
Group of answer choices
Microstructure Changes
Formation of Surface Oxide
Cooling Rate
Ambient Temperature
Heating Rate
Diffusion Rate
Heating Method
Chapter 5 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 5 - What is heat treatment?Ch. 5 - What types of properties can be altered through...Ch. 5 - Why should people performing hot forming or...Ch. 5 - What is the broad goal of the processing heat...Ch. 5 - Why might equilibrium phase diagrams be useful...Ch. 5 - What are the A1, A3, and Acm lines?Ch. 5 - What are some possible objectives of annealing...Ch. 5 - Why might it be important to include a preceding...Ch. 5 - Describe the cooling conditions of a full anneal.Ch. 5 - Why are the hypereutectoid steels not...
Ch. 5 - Although full anneals often produce the softest...Ch. 5 - What is the major process difference between full...Ch. 5 - Although normalizing is less expensive than a full...Ch. 5 - Prob. 14RQCh. 5 - What types of steel would be candidates for a...Ch. 5 - How might steel composition influence the...Ch. 5 - Other than increasing strength, for what three...Ch. 5 - What are the six major mechanisms that can be used...Ch. 5 - Prob. 19RQCh. 5 - What is required for a metal to be a candidate for...Ch. 5 - What are the three steps in an age�hardening...Ch. 5 - What is the difference between a coherent...Ch. 5 - What is overaging? Why does strength decrease?Ch. 5 - Describe the various aging responses (maximum...Ch. 5 - What is the difference between natural and...Ch. 5 - Why might naturally aging aluminum rivets be...Ch. 5 - Why is it important not to expose precipitation...Ch. 5 - Why is it more difficult to understand the...Ch. 5 - What types of heating and cooling conditions are...Ch. 5 - What are the stable equilibrium phases for steels...Ch. 5 - What are some nonequilibrium structures that...Ch. 5 - Prob. 32RQCh. 5 - What is the major factor that influences the...Ch. 5 - For a given steel, describe the relative strengths...Ch. 5 - Most structure changes proceed to completion over...Ch. 5 - What is retained austenite, and why is it an...Ch. 5 - What types of steels are more prone to retained...Ch. 5 - Why are martensitic structures usually tempered...Ch. 5 - Why does tempering offer a spectrum of possible...Ch. 5 - In what ways is the quench�and�temper heat...Ch. 5 - What is a C�C�T diagram? Why is it more useful...Ch. 5 - What is the critical cooling rate, and how is it...Ch. 5 - What two features combine to determine the...Ch. 5 - What conditions are used to standardize the quench...Ch. 5 - How do the various locations of a Jominy test...Ch. 5 - How do the data collected from a Jominy test...Ch. 5 - What is the assumption that allows the data from a...Ch. 5 - What is hardenability? How is it different from...Ch. 5 - What capabilities are provided by...Ch. 5 - When selecting a steel for an application, what...Ch. 5 - What are the three stages of liquid quenching?Ch. 5 - What are some of the major advantages and...Ch. 5 - Why does brine provide faster cooling than water?Ch. 5 - Why is an oil quench less likely to produce quench...Ch. 5 - What are some of the attractive qualities of a...Ch. 5 - Prob. 56RQCh. 5 - Prob. 57RQCh. 5 - Prob. 58RQCh. 5 - Prob. 59RQCh. 5 - How might the thermally induced residual stresses...Ch. 5 - Prob. 61RQCh. 5 - Prob. 62RQCh. 5 - Prob. 63RQCh. 5 - What is thermomechanical processing?Ch. 5 - Prob. 65RQCh. 5 - Prob. 66RQCh. 5 - Prob. 67RQCh. 5 - Prob. 68RQCh. 5 - Prob. 69RQCh. 5 - Prob. 70RQCh. 5 - Prob. 71RQCh. 5 - Prob. 72RQCh. 5 - Prob. 73RQCh. 5 - Why does a carburized part have to be further...Ch. 5 - Prob. 75RQCh. 5 - Prob. 76RQCh. 5 - Prob. 77RQCh. 5 - Describe the distinguishing features of a box...Ch. 5 - What are some possible functions of artificial...Ch. 5 - Prob. 80RQCh. 5 - Prob. 81RQCh. 5 - Prob. 82RQCh. 5 - What are some current goals of the heat treatment...Ch. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - What problems might be expected if the material on...Ch. 5 - Describe some heat treatment processes or...Ch. 5 - Prob. 1.3CSCh. 5 - Prob. 1.4CSCh. 5 - Prob. 1.5CSCh. 5 - Prob. 1.6CSCh. 5 - Prob. 1.7CSCh. 5 - Prob. 1.8CSCh. 5 - Prob. 2.1CSCh. 5 - Prob. 2.2CSCh. 5 - How would you alter the procedures or policies of...
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- What physical reasons why reducing grain size is an effective alternative for increasing the strength of a metal?arrow_forwardWhy is the theoretical strength of materials higher than the observed strength?arrow_forwardSelect 3 principal driving forces for the development of mechanical properties during heat treatment. Group of answer choices: Microstructure Changes Formation of Surface Oxide Cooling Rate Ambient Temperature Heating Rate Diffusion Rate Heating Methodarrow_forward
- We wish to produce an 0.3 inch plate of oxygen-free, high-conductivity (OFHC) copper that has a yield strength of at least 45 ksi and elongation of at least 10%. The original thickness of the plate is 3 inches. The width of the plate remains the same during processing. Which of the following procedures would give the correct final properties. More than one answer is possible. Group of answer choices Hot work from 3 to 0.5 inches; cold work from 0.5 to 0.3 inches Cold work from 3 to 1 inch; cold work from 1 to 0.5 inches; hot work from 0.5 to 0.3 inches Cold work from 3 to 1 inch; cold work from 1 to 0.4 inches; cold work from 0.4 to 0.3 inches Cold work from 3 to 1 inch; do full anneal; cold work from 1 to 0.5 inches; do full anneal; cold work from 0.5 to 0.3 inches Hot work from 3 to 0.4 inches; cold work from 0.4 to 0.3 inches None of the above will work Cold work from 3 to 0.3 inches Cold work from 3 to 1 inch; hot work from 1 to 0.4 inches; cold work from 0.4…arrow_forwardName the two carriers of heat conduction through a metal. Provide at least one way you could modify a hypoeutectoid steel product to improve the first carrier, and then provide one way you could modify the same steel to improve the second carrier.arrow_forward3arrow_forward
- Some alloys use a combination of strain hardening and precipitation hardening to achieve particularly high strength levels. The usual order of strengthening is solution treatment, quenching, cold working, and finally precipitation heat treatment. Why not reverse the order of the cold working and precipitation heat treatment steps?arrow_forwardTag question Consider the graph below for 3 metals which have been cold-worked. From the graphs, which of the following statements are true? Stress Select one or more: a. C. Strain & A e. B C b. B and C have similar hardness; C has greater brittleness B is softer than C and has nearly similar ductility A is harder than C and is more ductile d. A and B have similar hardness; A has greater brittleness A is harder than C and is less ductile f. B is harder than C but has nearly similar ductility 5 up i A Carrow_forwardOf the following alloys, pick the one(s) thatmay be strengthened by heat treatment,cold work, or both: R50250 titanium, AZ31Bmagnesium, 6061 aluminum, C51000 phos-phor bronze, lead, 6150 steel, 304 stainlesssteel, and C17200 beryllium copper.arrow_forward
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