Interpretation:
The molecular weight of stachyose should be calculated.
Concept introduction:
A biological molecule which consists of carbon, hydrogen and oxygen is known as saccharide or carbohydrate. The general formula of saccharide is
Saccharides (sugar) are classified as: monosaccharides, disaccharides and polysaccharides.
Monosaccharides are defined as a simpler carbohydrate which contains one sugar molecule and can’t hydrolyze into smaller carbohydrate.
Disaccharides are defined as a saccharide which contains two sugar molecules. It is formed when two monosaccharides are linked by glycosidic bonds. It is a double ring structure.
Tetrasaccharides are defined as a saccharide which contains four sugar molecules. It is formed when four monosaccharides are linked by glycosidic bonds.
Polysaccharides are defined as a saccharide which contains many units of sugar molecules that is more than two monosaccharides are linked by glycosidic bonds.
Explanation of Solution
It is given that the Stachyose is a tetrasaccahride which contains two D-galactose units, D-glucose unit and one D-fructose unit.
Molecular weight of each sugar molecule = 180 g/mole
Since, it is given that four sugar molecules are present.
Thus,
Total molecular weight =
=
There are four sugar units implies three linkages are present, thus, there water molecules are released.
Now,
Molar mass of water = 18 g/mole
Total molecular weight =
=
Therefore,
Molecular mass of Stachyose =
=
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