(a)
Interpretation:
Whether the following structure is classified as fatty acid, triglyceride, phospholipid, sterioid or wax should be determined.
Concept introduction:
The molecules which contains hydrocarbons and not soluble in water but soluble in nonpolar solvents is known as lipid.
Lipids are classified as:
Triglycerides, Phospholipids and, Steroids and Waxes.
The building blocks of fat in our bodies and in food are known as fatty acids. Fatty acid consists of
The given structure is classified as steroid as it contains multiple cyclic rings.
Fatty acid consists of carboxylic acid with long aliphatic chain which can be saturated or unsaturated. Generally, fatty acids exist as: phospholipids, triglycerides and cholesteryl esters. These are important structural components for cells.
Fats and oils consist of molecules known as triglycerides (contain ester bonds).
The given structure is:
The skeleton of given structure is similar to steroid as it contains many cyclic structures. General structure of steroid contains 17 carbon atoms which are linked with each other in four fused rings, three rings contains six carbon atoms that is cyclohexane rings and one is five membered ring that is cyclopentane.
Thus, in the given structure, four cyclohexane rings are fused and one five membered ring that is cyclopentane is present along with a
Hence, the given structure is classified as steroid.
(b)
Interpretation:
Whether the following structure is classified as fatty acid, triglyceride, phospholipid, sterioid or wax should be determined.
Concept introduction:
The molecules which contains hydrocarbons and not soluble in water but soluble in nonpolar solvents is known as lipid.
Lipids are classified as:
Triglycerides, Phospholipids and, Steroids and Waxes
The building blocks of fat in our bodies and in food are known as fatty acids. Fatty acid consists of carboxylic acid with long aliphatic chain which can be saturated or unsaturated.
The given structure is classified as phospholipid as it contains a phosphate group, diglyceride and two straight chains of carbon atoms.
Fatty acid consists of carboxylic acid with long aliphatic chain which can be saturated or unsaturated. Generally, fatty acids exist as: phospholipids, triglycerides and cholesteryl esters. These are important structural components for cells.
Fats and oils consist of molecules known as triglycerides (contain ester bonds).
The given structure is:
The skeleton of given structure is similar to phospholipids. General structure of phospholipids contains a glycerol molecule(s), phosphate group and two fatty acids.
Thus, in the given structure, two fatty acids are present that are two straight chains of carbon atoms along with a phosphate group and two glyceride group that is diglyceride.
Hence, the given structure is classified as phospholipid.
Chapter 23 Solutions
Chemistry: Matter and Change
Additional Science Textbook Solutions
Biology: Life on Earth (11th Edition)
Applications and Investigations in Earth Science (9th Edition)
Cosmic Perspective Fundamentals
Campbell Biology (11th Edition)
Anatomy & Physiology (6th Edition)
Human Physiology: An Integrated Approach (8th Edition)
- Drawing Arrows 1 I I 1 heat 1 51 MO + Drag To Und Settings Done 0 0 Jan 31 3:5arrow_forwardDon't used hand raitingarrow_forwardGramicidin A can adopt more than one structure; NMR spectroscopy has revealed an “end-to-end” dimer form, and x-ray crystallography has revealed an “anti-parallel double- helical” form. Briefly outline and describe an experimentalapproach/strategy to investigate WHICH configuration (“end-to-end dimer” vs “anti-paralleldouble helical”) gramicidin adopts in an actual lipid bilayer.arrow_forward
- Don't used hand raitingarrow_forwardCHEM2323 Problem 2-24 Tt O e: ל Predict the product(s) of the following acid/base reactions. Draw curved arrows to show the formation and breaking of bonds. If the bonds needed are not drawn out, you should redraw them. + BF3 (a) (b) HI + (c) OH -BF Problem 2-25 Use curved arrows and a proton (H+) to draw the protonated form of the following Lewis bases. Before starting, add all missing lone pairs. (a) (b) :0: (c) N 1 CHEM2323 PS CH02 Name:arrow_forwardCHEM2323 Problem 2-26 Tt O PS CH02 Name: Use the curved-arrow formalism to show how the electrons flow in the resonance form on the left to give the one on the right. (Draw all lone pairs first) (a) NH2 NH2 + (b) Problem 2-27 Double bonds can also act like Lewis bases, sharing their electrons with Lewis acids. Use curved arrows to show how each of the following double bonds will react with H-Cl and draw the resulting carbocation. (a) H2C=CH2 (b) (c) Problem 2-28 Identify the most electronegative element in each of the following molecules: (a) CH2FCI F Problem 2-29 (b) FCH2CH2CH2Br (c) HOCH2CH2NH2 (d) CH3OCH2Li F 0 0 Use the electronegativity table in Figure 2.3 to predict which bond in the following pairs is more polar and indicate the direction of bond polarity for each compound. (a) H3C-Cl or Cl-CI (b) H3C-H or H-CI (c) HO-CH3 or (CH3)3Si-CH3 (d) H3C-Li or Li-OHarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY