Interpretation:
The mass of NaOH in grams required to completely neutralize 50.0 mL of 0.100 M HCl needs to be determined.
Concept introduction:
The reaction between HCl and NaOH can be given as,
NaOH reacts with HCl to give NaCl and
Answer to Problem 4STP
0.200 g of NaOH is required to completely neutralize 50.0 mL of 0.100 M HCl.
Explanation of Solution
The reaction between HCl and NaOH can be given as,
So, we can calculate the amount of NaOH in grams required to completely neutralize 50.0 mL of 0.100 M HCl by using the following method.
The amount of NaOH in grams required to completely neutralize 50.0 mL of 0.100 M HCl is 0.200 g.
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