Concept explainers
(a)
Interpretation:
The structure of organic compound with 4 carbon atoms and an ester group needs to be drawn.
Concept introduction:
The organic compounds generally contain carbon atoms. The naming of organic compounds is done by considering three main terms which are prefix, suffix and the root name. The longest chain in the compound is first identified and named that will be the root name for the compound. For example, if there are 3 carbon atoms in the longest chain, the root name will be “prop”. To determine the suffix,
Explanation of Solution
According to the question, there are 4 carbon atoms in the main chain. Also, there is an ester group. The general formula of an ester is
Now, if there are 4 carbon atoms in the main chain, the structure of compound will be:
(b)
Interpretation:
The structure of organic compound with 4 carbon atoms and an aldehyde group needs to be drawn.
Concept introduction:
The organic compounds generally contain carbon atoms. The naming of organic compounds is done by considering three main terms which are prefix, suffix and the root name. The longest chain in the compound is first identified and named that will be the root name for the compound. For example, if there are 3 carbon atoms in the longest chain, the root name will be “prop”. To determine the suffix, functional group should be identified. For example, alcohol group will have suffix −ol, aldehyde will have suffix −al. If there is no functional group the suffix will be −ane. In the last step, side groups are identified and named. Prefix is used to give number of side groups and substituent’s present on the main carbon chain.
Explanation of Solution
According to the question, there are 4 carbon atoms in the main chain. Also, there is an aldehyde group. The general formula of an aldehyde is
Now, if there are 4 carbon atoms in the main chain, the structure of compound will be:
(c)
Interpretation:
The structure of organic compound with 4 carbon atoms and an ether group needs to be drawn.
Concept introduction:
The organic compounds generally contain carbon atoms. The naming of organic compounds is done by considering three main terms which are prefix, suffix and the root name. The longest chain in the compound is first identified and named that will be the root name for the compound. For example, if there are 3 carbon atoms in the longest chain, the root name will be “prop”. To determine the suffix, functional group should be identified. For example, alcohol group will have suffix −ol, aldehyde will have suffix −al. If there is no functional group the suffix will be −ane. In the last step, side groups are identified and named. Prefix is used to give number of side groups and substituent’s present on the main carbon chain.
Explanation of Solution
According to the question, there are 4 carbon atoms in the main chain. Also, there is an ether group. The general formula of ether is
Now, if there are 4 carbon atoms in the main chain, the structure of compound will be:
The other possible structure is as follows:
(d)
Interpretation:
The structure of organic compound with 4 carbon atoms and an alcohol group needs to be drawn.
Concept introduction:
The organic compounds generally contain carbon atoms. The naming of organic compounds is done by considering three main terms which are prefix, suffix and the root name. The longest chain in the compound is first identified and named that will be the root name for the compound. For example, if there are 3 carbon atoms in the longest chain, the root name will be “prop”. To determine the suffix, functional group should be identified. For example, alcohol group will have suffix −ol, aldehyde will have suffix −al. If there is no functional group the suffix will be −ane. In the last step, side groups are identified and named. Prefix is used to give number of side groups and substituent’s present on the main carbon chain.
Explanation of Solution
According to the question, there are 4 carbon atoms in the main chain. Also, there is an alcohol group. The general formula of alcohol is
Now, if there are 4 carbon atoms in the main chain, the structure of compound will be:
or
The other possible structure is as follows:
Chapter 22 Solutions
Chemistry: Matter and Change
Additional Science Textbook Solutions
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
Anatomy & Physiology (6th Edition)
Organic Chemistry (8th Edition)
College Physics: A Strategic Approach (3rd Edition)
Campbell Biology in Focus (2nd Edition)
Microbiology: An Introduction
- achieve.macmillanlearning.com Canvas EA eac h Hulu YouTube G 3 methyl cyclobutanol - Google Search Ranking Phenol Acidity Course -236 - Organic Chemistry - Mac... ← Assessment Completed 10 of 22 Questions 1 + Netflix paramount plus chem hw Galdehyde reaction with grignard reagent... b My Questions | bartleby M Inbox - chenteislegit@gmail.com - Gmail Due: Fri, Jan 31 Resources Solution Penalized ? Hint Submit Answer Use retrosynthetic analysis to suggest two paths to synthesize 2-methyl-3-hexanol using the Grignard reaction. (Click and drag the appropriate image to the correct position in the reactions.) Route 1 Aldehyde 1 or +98 Aldehyde 2 Route 2 Q6 +100 Solved in 1 attempt Q7 +95 Solved in 2 attempts Q8 +98 Unlimited attempts possible + + Grignard 1 OH H3O+ Grignard 2 Answer Bank Q9 +90 MgBr Unlimited attempts possible CH3CH2CH2MgBr Q10 Unlimited attempts Q11 ? ? +100 in 1 attempt 2-methyl-3-hexanol CH3CH2MgBr H H о H Attempt 3arrow_forward2) (4 pt) After the reaction was completed, the student collected the following data. Crude product data is the data collected after the reaction is finished, but before the product is purified. "Pure" product data is the data collected after attempted purification using recrystallization. Student B's data: Crude product data "Pure" product data after recrystallization Crude mass: 0.93 g grey solid Crude mp: 96-106 °C Crude % yield: Pure mass: 0.39 g white solid Pure mp: 111-113 °C Pure % yield: a) Calculate the crude and pure percent yields for the student's reaction. b) Summarize what is indicated by the crude and pure melting points.arrow_forwardDon't used hand raitingarrow_forward
- A DEPT NMR spectrum is shown for a molecule with the molecular formula of C5H12O. Draw the structure that best fits this data. 200 180 160 140 120 100 一盆 00 40 8- 20 ppm 0 Qarrow_forwardDon't used hand raitingarrow_forwardShown below is the major resonance structure for a molecule. Draw the second best resonance structure of the molecule. Include all non-zero formal charges. H. H. +N=C H H H Cl: Click and drag to start drawing a structure. : ? g B S olo Ar B Karrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY