Chapter 22, Problem 34A

Interpretation Introduction

Interpretation:

The possible structural isomers for the given alkyl halide with no branches needs to be determined.

Concept introduction:

Structural isomers have same number of atoms of element in the compounds but the position of groups is different. An alkyl halide has general formula R-X where X is a halogen atom.

Explanation of Solution

The given molecular formula is ${\text{C}}_{\text{5}}{\text{H}}_{\text{10}}{\text{Br}}_{\text{2}}$.

There are 5 carbon atoms, 10 hydrogen atoms and 2 bromine atoms in the compound.

It is given in the question that there is no branch thus, the main carbon atom must have 5 carbon atoms. The position of Br atoms must be changed to draw the isomers.

The possible structural isomers will be as follows: