Chapter 10, Problem 110A

Determine the mass in grams of each element.

1. $1.33\times {\text{ 10}}^{22}\text{ mol of Sb}$

$\text{4}\text{.75 }\times {\text{ 10}}^{14}\text{ mol of Pt }$

$\text{1}\text{.22 }\times {\text{ 10}}^{23}\text{ mol of Ag}$

$\text{9}\text{.85 }\times {\text{ 10}}^{24}\text{ mol of Cr}$

Interpretation Introduction

Interpretation:

The mass of $\text{1}\text{.33}\times {\text{10}}^{22}\text{ mole}$ $\text{Sb}$ in grams should be calculated.

Concept Introduction:

The number of moles of a compound is defined as the ratio of the given mass of the compound to the molar or molecular mass of the compound.

The mathematical expression is given by:

Number of moles = $\frac{\text{mass of the compound}}{\text{molar mass of the compound}}$

The one mole of any substance is equal to the Avogadro number, i.e., $6.022\times {10}^{23}$ atoms.

Answer to Problem 110A

Mass of $\text{1}\text{.33}\times {\text{10}}^{22}\text{ mole}$ $\text{Sb}$ = $\text{161}\text{.94}\times {\text{10}}^{22}\text{ g}$

Explanation of Solution

The mathematical expression for the calculation of the number of moles is given by:

Number of moles = $\frac{\text{mass of the compound}}{\text{molar mass of the compound}}$

The above expression is rearranged as:

  $\text{Mass = Number of moles×molar mass}$

Molar mass of antimony = 121.76 g/mole

Number of moles of antimony = $\text{1}\text{.33}\times {\text{10}}^{22}\text{ mole}$

Put the values,

  $\text{Mass = Number of moles×molar mass of the compound}$

  $\begin{array}{l}\text{Mass of antimony = 1}\text{.33}\times {\text{10}}^{22}\text{ mole ×121}\text{.76 g/mole}\end{array}$

  $\begin{array}{c}\text{ = 161}\text{.94}\times {\text{10}}^{22}\text{ g}\end{array}$

Interpretation Introduction

Interpretation:

The mass of $\text{4}\text{.75}\times {\text{10}}^{14}\text{ mole}$ $\text{Pt}$ in grams should be calculated.

Concept Introduction:

The number of moles of a compound is defined as the ratio of the given mass of the compound to the molar or molecular mass of the compound.

The mathematical expression is given by:

Number of moles = $\frac{\text{mass of the compound}}{\text{molar mass of the compound}}$

The one mole of any substance is equal to the Avogadro number, i.e., $6.022\times {10}^{23}$ atoms.

Answer to Problem 110A

Mass of platinum = $\text{926}\text{.25}\times {\text{10}}^{14}\text{ g}$

Explanation of Solution

The mathematical expression for the calculation of the number of moles is given by:

Number of moles = $\frac{\text{mass of the compound}}{\text{molar mass of the compound}}$

The above expression is rearranged as:

  $\text{Mass = Number of moles×molar mass}$

Molar mass of platinum = 195.0 g/mole

Number of moles of platinum= $\text{4}\text{.75}\times {\text{10}}^{14}\text{ mole}$

Put the values,

  $\text{Mass = Number of moles×molar mass of the compound}$

  $\begin{array}{l}\text{Mass of platinum = 4}\text{.75}\times {\text{10}}^{14}\text{ mole ×195}\text{.0 g/mole}\end{array}$

  $\begin{array}{c}\text{ = 926}\text{.25}\times {\text{10}}^{14}\text{ g}\end{array}$

Interpretation Introduction

Interpretation:

The mass of $1.22\times {10}^{23}\text{ mole}$ $\text{Ag}$ in grams should be calculated.

Concept Introduction:

The number of moles of a compound is defined as the ratio of the given mass of the compound to the molar or molecular mass of the compound.

The mathematical expression is given by:

Number of moles = $\frac{\text{mass of the compound}}{\text{molar mass of the compound}}$

The one mole of any substance is equal to the Avogadro number, i.e., $6.022\times {10}^{23}$ atoms.

Answer to Problem 110A

Mass of silver = $\text{131}\text{.6}\times {\text{10}}^{23}\text{ g}$

Explanation of Solution

The mathematical expression for the calculation of the number of moles is given by:

Number of moles = $\frac{\text{mass of the compound}}{\text{molar mass of the compound}}$

The above expression is rearranged as:

  $\text{Mass = Number of moles×molar mass}$

Molar mass of silver = 107.86 g/mole

Number of moles of silver = $1.22\times {10}^{23}\text{ mole}$

Put the values,

  $\text{Mass = Number of moles×molar mass of the compound}$

  $\begin{array}{l}\text{Mass of silver = }1.22\times {10}^{23}\text{ mole ×107}\text{.86 g/mole}\end{array}$

  $\begin{array}{c}\text{ = 131}\text{.6}\times {\text{10}}^{23}\text{ g}\end{array}$

Interpretation Introduction

Interpretation:

The mass of $9.85\times {10}^{24}\text{ mole}$ $\text{Cr}$ in grams should be calculated.

Concept Introduction:

The number of moles of a compound is defined as the ratio of the given mass of the compound to the molar or molecular mass of the compound.

The mathematical expression is given by:

Number of moles = $\frac{\text{mass of the compound}}{\text{molar mass of the compound}}$

The one mole of any substance is equal to the Avogadro number, i.e., $6.022\times {10}^{23}$ atoms.

Answer to Problem 110A

Mass of $9.85\times {10}^{24}\text{ mole}$ $\text{Cr}$ = $\text{ 512}\text{.1}\times {\text{10}}^{24}\text{ g}$ .

Explanation of Solution

The mathematical expression for the calculation of the number of moles is given by:

Number of moles = $\frac{\text{mass of the compound}}{\text{molar mass of the compound}}$

The above expression is rearranged as:

  $\text{Mass = Number of moles×molar mass}$

Molar mass of chromium = 51.99 g/mole

Number of moles of chromium = $9.85\times {10}^{24}\text{ mole}$

Put the values,

  $\text{Mass = Number of moles×molar mass of the compound}$

  $\begin{array}{l}\text{Mass of chromium = }9.85\times {10}^{24}\text{ mole ×51}\text{.99 g/mole}\end{array}$

  $\begin{array}{c}\text{ = 512}\text{.1}\times {\text{10}}^{24}\text{ g}\end{array}$