Concept explainers
Interpretation:
An experiment must be designed to determine the amount of water in alum.
Concept introduction:
Alums are mixed salt of aluminium and other metals which contains few molecules of water as water of crystallization.

Answer to Problem 202A
Some amount of alum (KAl (SO4)2.xH2O) is weighed in a pre-weighed crucible and the total mass of the crucible and alum is noted.
Now the crucible is strongly heated to remove the water of crystallization completely.
Then dry alum salt and crucible is weighed.
Explanation of Solution
Let’s consider mass of crucible is x g and mass of hydrated salt y g.
Total mass before heating is (x+y) g.
After heating the mass of crucible and salt is z g.
Then mass of water
Mass of anhydrous alum
From the mole ratio of anhydrous salt and water the value of x in KAl (SO4)2.xH2O can be found.
Amount of water is found by calculating weight loss in heating experiment.
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