a.
Interpretation:
The formula of silver chromate needs to be determined.
Concept introduction:
The molecular formula of silver chromate can be determined by using the formula of ions present in it. The number of ratio in which two ions are present should be such that total charge on the compound is zero.
a.

Answer to Problem 46PP
The formula of silver chromate is
Explanation of Solution
In silver chromate, cation and anion are as follows:
Cation:
Anion:
Here, charge on Ag is +1 and that on chromate is -2. Thus, Ag and chromate combines in 2:1 ratio. The formula will be:
(b)
Interpretation:
The number of cations in the sample needs to be determined.
Concept introduction:
In 1 mol of any substance, there are

Answer to Problem 46PP
The number of cations present in the sample is
Explanation of Solution
Given information:
A sample of silver chromate has a mass of
Calculation:
The mass of the silver chromate and molar mass is 25.8 g and 331.73 g/mol respectively.
The number of moles can be calculated as follows:
From the formula 1 mol of compound contains 2 mol of cation or Ag+. Also, in 1 mol there are
c.
Interpretation:
The number of anions in the sample needs to be determined.
Concept introduction:
In 1 mol of any substance, there are
c.

Answer to Problem 46PP
The number of anions present in the sample is
Explanation of Solution
Given information:
A sample of silver chromate has a mass of
Calculation:
The mass of the silver chromate and molar mass is 25.8 g and 331.73 g/mol respectively.
The number of moles can be calculated as follows:
From the formula 1 mol of compound contains 1 mol of anion or
d.
Interpretation:
The mass of 1 formula unit of silver chromate needs to be determined.
Concept introduction:
In 1 mol of any substance, there are
d.

Answer to Problem 46PP
The mass in grams of one formula unit of silver chromate is
Explanation of Solution
The molar mass of silver chromate is 332 g/mol thus, mass of 1 mol is 332 g. In 1 mol there are
Now, mass of 1 molecule will be:
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