Chapter 10.5, Problem 80SSC

Interpretation Introduction

Interpretation: The mass of the water of hydration if a hydrate loses $0.025\text{ mol}$ of water on heating needs to be determined.

Concept introduction:

The mass of a substance can be calculated from number of moles as follows:

$m=n\times M$

Here, m is mass, n is number of moles and M is molar mass.

Answer to Problem 80SSC

The mass of water lost is $0.45\text{ g}\text{.}$

Explanation of Solution

Given information:

Moles of water loss $=0.025\text{ mol}$

The mass of water of hydration is equal to the mass of water lost on heating. The mass can be calculated using number of moles and molar mass.

The molar mass of water is 18.01 g/mol thus, mass of water of hydration will be:

$\text{Mass of water of hydration = Moles }\times \text{ Molar Mass}$

$\begin{array}{l}=0.025\text{ mol}\times 18.01\text{ g/mol}\\ =0.45\text{ g}\end{array}$

Conclusion

Therefore, the mass of water lost is 0.45 g.