Concept explainers
Interpretation:
The molar mass of allyl sulfide (
Concept introduction:
Number of moles of a compound is defined as the ratio of given mass of the compound to the molar or molecular mass of the compound.
The mathematical expression is given by:
Number of moles =
The one mole of any substance is equal to the

Answer to Problem 132A
Molar mass of
Explanation of Solution
The given compound is allyl sulfide having molecular formula
The molar mass of the compound is equal to the sum of
To find the molar mass of the compound, multiply the molecular weight of the atom by the corresponding subscript number.
Allyl sulfide contains: 6 atoms of carbon, one atom of sulfur, 10 atoms of hydrogen.
Molar mass of carbon = 12.0107 g/mole
Molar mass of hydrogen = 1.00784 g/mole
Molar mass of sulfur = 32.07 g/mole
Molar mass of
=
=
Chapter 10 Solutions
Chemistry: Matter and Change
Additional Science Textbook Solutions
Campbell Essential Biology (7th Edition)
Introductory Chemistry (6th Edition)
Campbell Biology (11th Edition)
Anatomy & Physiology (6th Edition)
Microbiology: An Introduction
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
- > You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: 1. ☑ CI 2. H3O+ O Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. Explanation Check ? DO 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibilityarrow_forwardDon't use ai to answer I will report you answerarrow_forwardConsider a solution of 0.00304 moles of 4-nitrobenzoic acid (pKa = 3.442) dissolved in 25 mL water and titrated with 0.0991 M NaOH. Calculate the pH at the equivalence pointarrow_forward
- What is the name of the following compound? SiMe3arrow_forwardK Draw the starting structure that would lead to the major product shown under the provided conditions. Drawing 1. NaNH2 2. PhCH2Br 4 57°F Sunny Q Searcharrow_forward7 Draw the starting alkyl bromide that would produce this alkyne under these conditions. F Drawing 1. NaNH2, A 2. H3O+ £ 4 Temps to rise Tomorrow Q Search H2arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





