Chapter 10, Problem 132A

Interpretation Introduction

Interpretation:

The molar mass of allyl sulfide ( ${\left(C_3{H}_5\right)}_{2}S$ ) should be calculated.

Concept introduction:

Number of moles of a compound is defined as the ratio of given mass of the compound to the molar or molecular mass of the compound.

The mathematical expression is given by:

Number of moles = $\frac{\text{given mass of the compound}}{\text{molar mass of the compound}}$

The one mole of any substance is equal to the Avogadro number, i.e., $6.022\times {10}^{23}$ atoms.

Answer to Problem 132A

Molar mass of ${\left(C_3{H}_5\right)}_{2}S$ = $\text{114}\text{.2122 g/mole}$

Explanation of Solution

The given compound is allyl sulfide having molecular formula ${\left(C_3{H}_5\right)}_{2}S$.

The molar mass of the compound is equal to the sum of atomic masses of all atoms present in the compound in gram/mole.

To find the molar mass of the compound, multiply the molecular weight of the atom by the corresponding subscript number.

Allyl sulfide contains: 6 atoms of carbon, one atom of sulfur, 10 atoms of hydrogen.

Molar mass of carbon = 12.0107 g/mole

Molar mass of hydrogen = 1.00784 g/mole

Molar mass of sulfur = 32.07 g/mole

Molar mass of ${\left(C_3{H}_5\right)}_{2}S$

= $6\left(\text{12}\text{.0107 g/mole}\right)\text{ +1}\left(32.07\text{ g/mole}\right)+10\left(1.0078\text{ g/mole}\right)$

= $\text{114}\text{.2122 g/mole}$