Interpretation:
The ore of copper that yield the greater quantity of copper must be calculated.
Concept introduction:
Percentage of an element in a compound can be calculated as follows:
Percentage of an element in a compound =Number of atom×Atomic mass of the element×100Molar mass of the compound.

Answer to Problem 198A
Cu2S would yield greater quantity of copper.
Explanation of Solution
Molar mass of Cu2S is 159 g/mol
Molar mass of CuFeS2 is 183.5 g/mol
The percentage of Cu in given compound can be calculated as follows:
% of Cu in Cu2S =2×63.5×100%159=12700159%=79.87%
% of Cu in CuFeS2=1×63.5×100%183.5=6350183.5%=76.05%
Thus, Cu2S would yield greater quantity of copper as it contains higher % of Cu.
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