Concept explainers
Interpretation:
Percentage composition, empirical formula and molecular formula of the compound must be found for which there are 6 g C and 1 g H with molar mass of 42 g/mol.
Concept introduction:
Empirical formula of a molecule is the smallest unit which is repeated in the molecule.
Molecular formula
Where n is the number of times the empirical formula is present in the molecular formula, n can be 1, 2, 3 etc.
Answer to Problem 194A
There is 85.71 % C and 14.29 % H.
The empirical formula is CH2 and molecular formula is C3H6.
Explanation of Solution
% of C and H are 85.71 and 14.29 respectively.
Considering 100 g of compound, mass of C and H is 85.71 g and 14.29 g respectively.
Also, molar mass of C and H is 12 g/mol and 1 g/mol respectively. Thus, number of moles of C and H will be:
Moles of C
Moles of H
Smallest mole ratio C: H
Thus empirical formula is CH2.
Now,
There is 85.71 % C and 14.29 % H. Empirical formula is CH2 and molecular formula is C3H6.
Chapter 10 Solutions
Chemistry: Matter and Change
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