Chapter 10.3, Problem 34PP

Interpretation Introduction

(a)

Interpretation:

The molar mass of $\text{NaOH}$ needs to be determined.

Concept introduction:

A molecule is composed of more than one type of atoms of different elements. On the basis of bonding with atoms, they can be ionic and covalent compounds. The molecular mass of compound is the sum of atomic mass of all the atoms present in the given chemical compound.

Answer to Problem 34PP

$\text{Molar mass of NaOH= 39}\text{.99 g/mol}$

Explanation of Solution

Given compound = $\text{NaOH}$

Molar mass of Na = 23.0 g/mol

Molar mass of O = 15.99 g/mol

Molar mass of H = 1.0 g/mol

Calculate the molar mass of $\text{NaOH}$ = $\text{23}\text{.0 g/mol + 15}\text{.99 g/mol + 1}\text{.0 g/mol = 39}\text{.99 g/mol }$

Interpretation Introduction

(b)

Interpretation:

The molar mass of ${\text{CaCl}}_{\text{2}}$ needs to be determined.

Concept introduction:

A molecule is composed of more than type of atoms of different elements. On the basis of bonding with atoms, they can be ionic and covalent compounds. The molecular mass of compound is the sum of atomic mass of all the atoms present in the given chemical compound.

Answer to Problem 34PP

${\text{Molar mass of CaCl}}_{\text{2}}\text{= 111}\text{.0 g/mol}$

Explanation of Solution

Given compound = ${\text{CaCl}}_{\text{2}}$

Molar mass of Ca = 40.1 g/mol

Molar mass of Cl = 35.5 g/mol

Calculate the molar mass of ${\text{CaCl}}_{\text{2}}$ = $\text{40}\text{.1 + }\left(\text{2×35}\text{.5}\right)\text{ = 111}\text{.0 g/mol}$

Interpretation Introduction

(c)

Interpretation:

The molar mass of ${\text{KC}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}$ needs to be determined.

Concept introduction:

A molecule is composed of more than type of atoms of different elements. On the basis of bonding with atoms, they can be ionic and covalent compounds. The molecular mass of compound is the sum of atomic mass of all the atoms present in the given chemical compound.

Answer to Problem 34PP

${\text{Molar mass of KC}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{= 98}\text{.1 g/mol}$

Explanation of Solution

Given compound = ${\text{KC}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}$

Molar mass of C = 12.01 g/mol

Molar mass of O = 15.99 g/mol

Molar mass of K = 39.1 g/mol

Molar mass of H = 1.0 g/mol

Calculate the molar mass of ${\text{KC}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}$ = $\text{39}\text{.1 + }\left(\text{2×12}\text{.01}\right)\text{+}\left(\text{3×1}\text{.0}\right)\text{+}\left(\text{2×15}\text{.99}\right)\text{ = 98}\text{.1 g/mol}$