Chapter 10.3, Problem 51SSC

Interpretation Introduction

Interpretation:

Molar mass of ${\text{MgBr}}_2$ needs to be determined.

Concept introduction:

Molar mass of given compound is equal to the Sum of individual atomic masses of the elements present in the compound.

Answer to Problem 51SSC

Molecular mass of ${\text{MgBr}}_2$ is $=184\text{ g/mol}$

Explanation of Solution

Given information:

Formula of the compound is ${\text{MgBr}}_2$

Formula used:

Molecular weight of compound is = Sum of individual atomic / molecular weights of elements present in the compound.

Calculation:

The individual atomic weights of the elements can be found from the periodic table.

Molar masses of Mg and Br are as follows:

Magnesium $\left(\text{Mg}\right)\text{= 24 g/mol}$

Bronium $\left(\text{Br}\right)=80\text{ g/mol}$

Thus, molar mass of ${\text{MgBr}}_2$ will be:

$\begin{array}{l}={\text{M}}_{\text{Mg}}\text{ + 2}\times {\text{M}}_{\text{Br}}\\ =24+2\times 80\\ =184\text{ g/mol}\end{array}$

Conclusion

The molecular weight of ${\text{MgBr}}_2$ is $=184\text{ g/mol}$