Chapter 10.3, Problem 33PP

Interpretation Introduction

Interpretation:

The number of moles of hydrogen atom present in $1.15\times {10}^1$ mol of water $\left(H_{2}O\right)$ needs to be determined.

Concept introduction:

Mole concept to be used here,

$1$ mol of substance contains $6.023\times {10}^{23}$ particles/atoms/molecules.

$\text{ 1 mole}=\frac{\text{given mass}}{\text{molar mass/atomic/molecular mass}}$

Answer to Problem 33PP

$1.15\times {10}^1$ moles of oxygen atoms.

Explanation of Solution

Given information : $11.5$ moles of water or $1.15\times {10}^1$ moles of water.

$1$ mole of $AxBy$ when dislocated:

$AxBy\to x\text{ mole of }A+y\text{ moles of }B.$

When $t\text{ moles of }AxBy\text{ breaks,}$

$tAxBy\to xt\text{ moles of }A+yt\text{ mols of }B.$

This concept needs to be applied here.

Calculation:

$1$ mol of water $\left(H_{2}O\right)\to 1$ mol of oxygen atom.

When $1.15\times {10}^1$ mol of $H_{2}O\to 1.15\times {10}^1$ mole of oxygen atoms are formed.

$1.15\times {10}^1$ mol of water gives $1.15\times {10}^1$ moles of oxygen atoms.