Chapter 9.4, Problem 46LC

(a)

Interpretation Introduction

Interpretation: The formula of the given ionic compound is to be stated.

Concept Introduction : Ionic compounds are formed by the transfer of electrons between metal and non-metal. They are named as $\text{Name}\text{of}\text{metal}+\text{Stem}\text{of}\text{non-metal}+\text{'}ide\text{'}$

Answer to Problem 46LC

The formula of the compound is ${\text{H}}_2{\text{CO}}_3$ .

Explanation of Solution

The given compound is carbonic acid. It is composed of ${\text{H}}^{+}$ and ${\text{CO}}_3{}^{2-}$ By Criss-cross method, the formula of the compound is ${\text{H}}_2{\text{CO}}_3$ .

(b)

Interpretation Introduction

Interpretation: The formula of the given ionic compound is to be stated.

Concept Introduction : Ionic compounds are formed by the transfer of electrons between metal and non-metal. They are named as $\text{Name}\text{of}\text{metal}+\text{Stem}\text{of}\text{non-metal}+\text{'}ide\text{'}$

Answer to Problem 46LC

The formula of the compound is ${\text{H}}_2{\text{SO}}_3$ .

Explanation of Solution

The given compound is sulfurous acid. It is composed of ${\text{H}}^{+}$ and ${\text{SO}}_3{}^{2-}$ By Criss-cross method, the formula of the compound is ${\text{H}}_2{\text{SO}}_3$ .

(c)

Interpretation Introduction

Interpretation: The formula of the given ionic compound is to be stated.

Concept Introduction : Ionic compounds are formed by the transfer of electrons between metal and non-metal. They are named as $\text{Name}\text{of}\text{metal}+\text{Stem}\text{of}\text{non-metal}+\text{'}ide\text{'}$

Answer to Problem 46LC

The formula of the compound is $\text{Fe}{\left(\text{OH}\right)}_{\text{3}}$ .

Explanation of Solution

The given compound is iron (III) hydroxide. It is composed of ${\text{Fe}}^{3+}$ and ${\text{OH}}^{-}$ By Criss-cross method, the formula of the compound is $\text{Fe}{\left(\text{OH}\right)}_{\text{3}}$ .

(d)

Interpretation Introduction

Interpretation: The formula of the given ionic compound is to be stated.

Concept Introduction : Ionic compounds are formed by the transfer of electrons between metal and non-metal. They are named as $\text{Name}\text{of}\text{metal}+\text{Stem}\text{of}\text{non-metal}+\text{'}ide\text{'}$

Answer to Problem 46LC

The formula of the compound is $\text{Zn}{\left(\text{OH}\right)}_{\text{2}}$ .

Explanation of Solution

The given compound is zinc hydroxide. It is composed of ${\text{Zn}}^{2+}$ and ${\text{OH}}^{-}$ By Criss-cross method, the formula of the compound is $\text{Zn}{\left(\text{OH}\right)}_{\text{2}}$ .