Chapter 9.2, Problem 15SP

(a)

Interpretation Introduction

Interpretation: The formula of the given compound is to be stated.

Concept Introduction : Molecular compounds are formed by the sharing of electrons between non-metals. The naming of the compound is $\text{Name}\text{of}\text{first}\text{element}+\text{Stem}\text{of}\text{second}\text{element}+\text{'}ide\text{'}$

Ionic compounds are formed by the transfer of electrons between metal and non-metal. They are named as $\text{Name}\text{of}\text{metal}+\text{Stem}\text{of}\text{non-metal}+\text{'}ide\text{'}$

Answer to Problem 15SP

The formula of the compound is ${\text{LiHSO}}_{\text{4}}$ .

Explanation of Solution

The given compound is lithium hydrogen sulfate. The lithium ion is ${\text{Li}}^{+}$ , hydrogen ion is ${\text{H}}^{+}$ and sulfate ion is ${\text{SO}}_4{}^{2-}$ . By Criss-cross method, the formula of the compound is ${\text{LiHSO}}_{\text{4}}$ .

(b)

Interpretation Introduction

Interpretation: The formula of the given compound is to be stated.

Concept Introduction : Molecular compounds are formed by the sharing of electrons between non-metals. The naming of the compound is $\text{Name}\text{of}\text{first}\text{element}+\text{Stem}\text{of}\text{second}\text{element}+\text{'}ide\text{'}$

Ionic compounds are formed by the transfer of electrons between metal and non-metal. They are named as $\text{Name}\text{of}\text{metal}+\text{Stem}\text{of}\text{non-metal}+\text{'}ide\text{'}$

Answer to Problem 15SP

The formula of the compound is $\text{Cr}{\left({\text{NO}}_2\right)}_3$ .

Explanation of Solution

The given compound is chromium (III) nitrite. The ions are ${\text{Cr}}^{3+}$ and ${\text{NO}}_2{}^{-}$ . By Criss-cross method, the formula of the compound is $\text{Cr}{\left({\text{NO}}_2\right)}_3$ .