6. In an experiment the following replicate set of volumemeasurements (cm3) was recorded:(25.35, 25.80, 25.28, 25.50, 25.45, 25.43)A. Calculate the mean of the raw data.B. Using the rejection quotient (Q-test) reject anyquestionable results.C. Recalculate the mean and compare it with the valueobtained in 2(a).

Given:Replicate set of volume measurements (cm³):25.35, 25.80, 25.28, 25.50, 25.45, 25.43 Part A:…

Answered: 6. In an experiment the following…

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter33: High-performance Liquid Chromatography

Section: Chapter Questions

Problem 33.12QAP

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1. In a gravimetric analysis of a chloride salt, the following data were obtained. Mass of original chloride sample Mass of AgCl formed From the data, find the following: a. Mass of Cl in the original sample b. Percent CI in the sample c. Average % chloride d. Average deviation from the mean Trial 1 0.2674 0.4862 Trial 2 0.4219 0.8015 Trial 3 0.3612 0.6133
Which matches the data?
4. (14 points) A soil sample (4.00 g) is digested and analyzed for Cd by atomic absorption analysis. The digestion results in 25.0 mL of extract. Because there is concern of matrix effects, standard addition is used. A portion of the extract is analyzed directly by AA and gives an absorbance of 0.211. Another 10.0 mL portion of the extract is spiked with 50.0 ug of Cd (ignore any added volume from Cd spiking) and gives an absorbance of 0.539. a) Calculate the Cd concentration in the (unspiked) extract (in ug/mL). (8 pts) b) Calculate the Cd concentration in the soil in ppm (by mass). (3 pts) c) A Cd standard prepared in dilute nitric acid to a concentration of 1.00 µg/mL is analyzed and gives an absorbance of 0.191. Was the standard addition justified? (3 pts)
(2) ylubäi On the gravimetric determination of CI, if the weight of AgCl ppt. was 1.433 g.; the weight of CI- in the sample will equals to: . (AGCI ..... molecular weight = 143.3 and Cl- =35.5) 143.3/35.5 g. O 3.55 g. O 0.1433 g. O 0.355 g. O
The following data give the recovery of bromide from spiked samples of vegetable matter, measuredusing a gas–liquid chromatographic method. The same amount of bromide was added to each specimen(Roughan, J.A., Roughan, P.A. and Wilkins, J.P.G., 1983, Analyst, 108: 742).Tomato: 777 790 759 790 770 758 764 ug/gCucumber: 782 773 778 765 789 797 782 ug/g(a) Test whether the recoveries from the two vegetables have variances which differ significantly.(b) Test whether the mean recovery rates differ significantly.
What does cross peak X tell you?
1) Study the chromatograph (below) of a mixture of Compounds A and B, run on the GCs in the teaching labs at CU Boulder. Compound A has the shorter retention time. STAAT 61 1.11 227 RT TYPE AREA XXXX XXXX XXXX AREAS 0.009 55874 44.117 ARIHT 0.61 XX XX XX 1.11 2.27 XX XX XX TOTAL AREA=XX MUL FACTOR=XX 1. What is the retention time of compound A? Compound B? 2. Which compound is present in a larger amount? 3. Which compound has the lower boiling point? 4. What would happen to the retention times of compounds A and B if the column temperature were raised? 5. You suspect that compound B is octane. What can you do to provide supporting evidence for this hypothesis?
Replicate water samples are analyzed for water hardness with the following results: 102.2, 102.8, 103.1, and 102.3 ppm CaCO3. What is the (a) the standard deviation, (b) the relative standard deviation, (c) variance.
The following chromatogram is obtained for a mixture of substances X and Y. Calculate the resolution of the two peaks. 10 11 12 13 14 Tim e (min) O A. 0.8 О В. 1.7 O C. 1.2 O D. 3.4 O E. 0.4 Instrum ent response in arbitrary units
(1) A 1.475 g containing NH,CI (FM 53.492), K;CO; (FM 138.21), and other impurities was dissolved to give 100.0 mL solution (Solution A). A 25.0 mL portion from this solution was acidified and treated with excess tetraphenylborate, Na'B(C,Hs);, to precipitate (K) and NH, ions completely: Deactant pect B(C,H), + (K* (FM 358.33) B(C,H3), + \NH,*/→ FM 337.27) KB(C,Hs)4 NH,B(C,Hs)4 The resultant precipitate weighed 0.617 g. A fresh 50.0 mL portion of the original solution (Solution A) was made alkaline and heated to remove NH,"as NH3: to tindt of ko3 NH, + OH → It was then acidified and treated with tetraphenylborate to give 0.554 g precipitate. Find the weight percent NH,Cl and K;CO, in the original solid. NH3
What is the expected molecular formula of the compounds based on the MS data given: m/Z Intensity 84 100% 85 86 a. C6H12 h 5.6% 0.4% b. C5H24 C. C4H602 d. C3H802 e. C5H80
Why does the test for F- often yield false negatives?

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