Chapter 9, Problem 115A

(a)

Interpretation Introduction

Interpretation: The given conversions are to be stated.

Concept Introduction : The number of digits that contributes to the degree of accuracy of the measurement is known as significant figures. It shows the precision of the measurement.

Answer to Problem 115A

The $\text{775}\text{mL}$ is equal to $7.75\times {10}^5\text{μL}$ .

Explanation of Solution

The conversion of mL to microliters:

  $\begin{array}{c}\text{775}\text{mL}\times \frac{\text{1000}\text{μL}}{\text{1}\text{mL}}=\text{775000}\text{μL}\\ =7.75\times {10}^5\text{μL}\end{array}$

Therefore, the $\text{775}\text{mL}$ is equal to $7.75\times {10}^5\text{μL}$ .

(b)

Interpretation Introduction

Interpretation: The given conversions are to be stated.

Concept Introduction : The number of digits that contributes to the degree of accuracy of the measurement is known as significant figures. It shows the precision of the measurement.

Answer to Problem 115A

The $65°\text{C}$ is equal to $338.15\text{K}$ .

Explanation of Solution

The conversion of degree Celsius to Kelvin:

  $\begin{array}{c}\text{K}=°\text{C}+273.15\\ =65+273.15\\ =338.15\text{K}\end{array}$

Therefore, the $65°\text{C}$ is equal to $338.15\text{K}$ .

(c)

Interpretation Introduction

Interpretation: The given conversions are to be stated.

Concept Introduction : The number of digits that contributes to the degree of accuracy of the measurement is known as significant figures. It shows the precision of the measurement.

Answer to Problem 115A

The $\text{8}\text{.32}\text{mg Ag}$ is equal to $\text{83}\text{.2}\text{cg Ag}$ .

Explanation of Solution

The conversion of mg Ag to cg Ag:

  $\text{8}\text{.32}\text{mg Ag}\times \frac{\text{10}\text{cg Ag}}{\text{1}\text{mg Ag}}=\text{83}\text{.2}\text{cg Ag}$

Therefore, the $\text{8}\text{.32}\text{mg Ag}$ is equal to $\text{83}\text{.2}\text{cg Ag}$ .