Chapter 9, Problem 66A

(a)

Interpretation Introduction

Interpretation: The correct formula of the compound formed by combining the positive and negative ions given in the table is to be determined.

Concept Introduction: Ions containing more than two different types of elements are called polyatomic ions. While writing the formula of ionic compounds, cations are written first followed by the anions.

Answer to Problem 66A

The ionic compound formed by the combination of ammonium ion and nitrate ion is ${\text{NH}}_{\text{4}}{\text{NO}}_{\text{3}}$ , and named ammonium nitrate.

Explanation of Solution

The formula is written by placing the cation first followed by the anion. Since both are monovalent ions, there is no need for subscripts. Thus, the ionic compound formed by the combination of ammonium ion and nitrate ion is ${\text{NH}}_{\text{4}}{\text{NO}}_{\text{3}}$ , and named ammonium nitrate.

(b)

Interpretation Introduction

Interpretation: The correct formula of the compound formed by combining the positive and negative ions given in the table is to be determined.

Concept Introduction: Ions containing more than two different types of elements are called polyatomic ions. While writing the formula of ionic compounds, cations are written first followed by the anions.

Answer to Problem 66A

The ionic formula of the compound tin (IV) nitrate, $\text{Sn}{\left({\text{NO}}_{\text{3}}\right)}_{\text{4}}$ .

Explanation of Solution

The formula is written by placing the cation first followed by the anion. The magnitude of charges of the ions is interchanged and written as a subscript to neutralize the charge.

Thus, the ionic formula of the compound tin (IV) nitrate, $\text{Sn}{\left({\text{NO}}_{\text{3}}\right)}_{\text{4}}$ .

(c)

Interpretation Introduction

Interpretation: The correct formula of the compound formed by combining the positive and negative ions given in the table is to be determined.

Concept Introduction: Ions containing more than two different types of elements are called polyatomic ions. While writing the formula of ionic compounds, cations are written first followed by the anions.

Answer to Problem 66A

The ionic formula of the compound is $\text{Fe}{\left({\text{NO}}_{\text{3}}\right)}_{\text{3}}$ and its name is ferric nitrate.

Explanation of Solution

The formula is written by placing the cation first followed by the anion. The magnitude of charges of the ions is interchanged and written as a subscript to neutralize the charge. The charge of Fe, 3 is written as the subscript of the anion.

(d)

Interpretation Introduction

Interpretation: The correct formula of the compound formed by combining the positive and negative ions given in the table is to be determined.

Concept Introduction: Ions containing more than two different types of elements are

called polyatomic ions. While writing the formula of ionic compounds, cations are written first followed by the anions.

Answer to Problem 66A

The ionic formula of the compound is $\text{Mg}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}$ and is named magnesium nitrate.

Explanation of Solution

The formula is written by placing the cation first followed by the anion. The magnitude of charges of the ions is interchanged and written as a subscript to neutralize the charge. Here magnesium carries a +2 charge, hence 2 is written as the subscript of the nitrate ion.

(e)

Interpretation Introduction

Interpretation: The correct formula of the compound formed by combining the positive and negative ions given in the table is to be determined.

Concept Introduction: Ions containing more than two different types of elements are called polyatomic ions. While writing the formula of ionic compounds, cations are written first followed by the anions.

Answer to Problem 66A

The ionic compound formed is ammonium carbonate with the chemical formula ${\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}{\text{CO}}_{\text{3}}$ .

Explanation of Solution

The formula is written by placing the cation first followed by the anion. The compound is neutralized by combining two cations with one anion, thus two is written as a subscript for cation. Thus, the ionic compound formed is ammonium carbonate with the chemical formula ${\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}{\text{CO}}_{\text{3}}$ .

(f)

Interpretation Introduction

Interpretation: The correct formula of the compound formed by combining the positive and negative ions given in the table are to be determined.

Concept Introduction: Ions containing more than two different types of elements are called polyatomic ions. While writing the formula of ionic compounds, cations are written first followed by the anions.

Answer to Problem 66A

The ionic formula of the compound tin (IV) carbonate is $\text{Sn}{\left({\text{CO}}_{\text{3}}\right)}_{\text{2}}$ .

Explanation of Solution

The formula is written by placing the cation first followed by the anion. The magnitude of charges of the ions is interchanged and written as a subscript to neutralize the charge. The charge of tin, 4 is written as a subscript of the carbonate ion, and the charge of carbonate, 2 is written as a subscript of Sn. Canceling common factors gives $\text{Sn}{\left({\text{CO}}_{\text{3}}\right)}_{\text{2}}$ .

(g)

Interpretation Introduction

Interpretation: The correct formula of the compound formed by combining the positive and negative ions given in the table is to be determined.

Concept Introduction: Ions containing more than two different types of elements are called polyatomic ions. While writing the formula of ionic compounds, cations are written first followed by the anions.

Answer to Problem 66A

The ionic formula of the compound is ${\text{Fe}}_2{\left({\text{CO}}_{\text{3}}\right)}_{\text{3}}$ and is named ferric carbonate.

Explanation of Solution

The formula is written by placing the cation first followed by the anion. The magnitude of charges of the ions is interchanged and written as a subscript to neutralize the charge. Thus, the ionic formula of the compound is ${\text{Fe}}_2{\left({\text{CO}}_{\text{3}}\right)}_{\text{3}}$ and is named ferric carbonate.

(h)

Interpretation Introduction

Interpretation: The correct formula of the compound formed by combining the positive and negative ions given in the table is to be determined.

Concept Introduction: Ions containing more than two different types of elements are called polyatomic ions. While writing the formula of ionic compounds, cations are written first followed by the anions.

Answer to Problem 66A

The ionic formula of the compound is ${\text{MgCO}}_3$ and the name of the compound is magnesium carbonate.

Explanation of Solution

The formula is written by placing the cation first followed by the anion. The magnitude of charges of the ions is interchanged and written as a subscript to neutralize the charge. Since both Mg and carbonate ions have the same magnitude of charge, they cancel out each other giving the formula ${\text{MgCO}}_3$ .

(i)

Interpretation Introduction

Interpretation: The correct formula of the compound formed by combining the positive and negative ions given in the table is to be determined.

Concept Introduction: Ions containing more than two different types of elements are called polyatomic ions. While writing the formula of ionic compounds, cations are written first followed by the anions.

Answer to Problem 66A

The ionic formula of the compound is ${\text{NH}}_{\text{4}}\text{CN}$ and the name of the compound is ammonium cyanide.

Explanation of Solution

The formula is written by placing the cation first followed by the anion. The magnitude of charges of the ions is interchanged and written as a subscript to neutralize the charge. Thus, the ionic formula of the compound is ${\text{NH}}_{\text{4}}\text{CN}$ and the name of the compound is ammonium cyanide.

(j)

Interpretation Introduction

Interpretation: The correct formula of the compound formed by combining the positive and negative ions given in the table is to be determined.

Concept Introduction: Ions containing more than two different types of elements are called polyatomic ions. While writing the formula of ionic compounds, cations are written first followed by the anions.

Answer to Problem 66A

The ionic formula of the compound is $\text{Sn}{\left(\text{CN}\right)}_{\text{4}}$ and is named tin (IV) cyanide.

Explanation of Solution

The formula is written by placing the cation first followed by the anion. The magnitude of charges of the ions is interchanged and written as a subscript to neutralize the charge. the charge of Sn, 4 is written as the subscript of cyanide ion.

(k)

Interpretation Introduction

Interpretation: The correct formula of the compound formed by combining the positive and negative ions given in the table is to be determined.

Concept Introduction: Ions containing more than two different types of elements are called polyatomic ions. While writing the formula of ionic compounds, cations are written first followed by the anions.

Answer to Problem 66A

The ionic formula of the compound is ${\text{Fe(CN)}}_{\text{3}}$ and the name of the compound is ferric cyanide.

Explanation of Solution

The formula is written by placing the cation first followed by the anion. The magnitude of charges of the ions is interchanged and written as a subscript to neutralize the charge. Thus, the ionic formula of the compound is ${\text{Fe(CN)}}_{\text{3}}$ and the name of the compound is ferric cyanide.

(l)

Interpretation Introduction

Interpretation: The correct formula of the compound formed by combining the positive and negative ions given in the table is to be determined.

Concept Introduction: Ions containing more than two different types of elements are called polyatomic ions. While writing the formula of ionic compounds, cations are written first followed by the anions.

Answer to Problem 66A

The ionic formula of the compound is $\text{Mg}{\left(\text{CN}\right)}_{\text{2}}$ and the name of the compound is magnesium cyanide.

Explanation of Solution

The formula is written by placing the cation first followed by the anion. The magnitude of charges of the ions is interchanged and written as a subscript to neutralize the charge. The charge on Mg is written as the subscript of ${\text{CN}}^{-}$ .

(m)

Interpretation Introduction

Interpretation: The correct formula of the compound formed by combining the positive and negative ions given in the table is to be determined.

Concept Introduction: Ions containing more than two different types of elements are called polyatomic ions. While writing the formula of ionic compounds, cations are written first followed by the anions.

Answer to Problem 66A

The ionic formula of the compound is ${\left({\text{NH}}_{\text{4}}\right)}_{\text{3}}{\text{PO}}_{\text{4}}$ and the name of the compound is ammonium phosphate.

Explanation of Solution

The formula is written by placing the cation first followed by the anion. The magnitude of charges of the ions is interchanged and written as a subscript to neutralize the charge. Thus, the ionic formula of the compound is ${\left({\text{NH}}_{\text{4}}\right)}_{\text{3}}{\text{PO}}_{\text{4}}$ and the name of the compound is ammonium phosphate.

(n)

Interpretation Introduction

Interpretation: The correct formula of the compound formed by combining the positive and negative ions given in the table is to be determined.

Concept Introduction: Ions containing more than two different types of elements are called polyatomic ions. While writing the formula of ionic compounds, cations are written first followed by the anions.

Answer to Problem 66A

The ionic formula of the compound is ${\text{Sn}}_{\text{3}}{\left({\text{PO}}_{\text{4}}\right)}_{\text{4}}$ and is named tin (IV) phosphate.

Explanation of Solution

The formula is written by placing the cation first followed by the anion. The magnitude of charges of the ions is interchanged and written as a subscript to neutralize the charge. Thus, the ionic formula of the compound is ${\text{Sn}}_{\text{3}}{\left({\text{PO}}_{\text{4}}\right)}_{\text{4}}$ and is named tin (IV) phosphate.

(o)

Interpretation Introduction

Interpretation: The correct formula of the compound formed by combining the positive and negative ions given in the table is to be determined.

Concept Introduction: Ions containing more than two different types of elements are called polyatomic ions. While writing the formula of ionic compounds, cations are written first followed by the anions.

Answer to Problem 66A

The ionic formula of the compound is ${\text{FePO}}_{\text{4}}$ and the name of the compound is ferric phosphate.

Explanation of Solution

The formula is written by placing the cation first followed by the anion. The magnitude of charges of the ions is interchanged and written as a subscript to neutralize the charge. Since both Fe and phosphate ions have the same magnitude of charge, they cancel out each other giving the formula ${\text{FePO}}_{\text{4}}$ .

(p)

Interpretation Introduction

Interpretation: The correct formula of the compound formed by combining the positive and negative ions given in the table is to be determined.

Concept Introduction: Ions containing more than two different types of elements are called polyatomic ions. While writing the formula of ionic compounds, cations are written first followed by the anions.

Answer to Problem 66A

The ionic formula of the compound is ${\text{Mg}}_{\text{3}}{\left({\text{PO}}_{\text{4}}\right)}_{\text{2}}$ and the name of the compound is magnesium phosphate.

Explanation of Solution

The formula is written by placing the cation first followed by the anion. The magnitude of charges of the ions is interchanged and written as a subscript to neutralize the charge. Thus, the ionic formula of the compound is ${\text{Mg}}_{\text{3}}{\left({\text{PO}}_{\text{4}}\right)}_{\text{2}}$ and the name of the compound is magnesium phosphate.