Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
expand_more
expand_more
format_list_bulleted
Question
Chapter 9.1, Problem 4LC
Interpretation Introduction
Interpretation: The similarities and differences between polyatomic ions and monatomic ions are to be stated.
Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of an electron whereas a cation is formed by losing an electron. But there is no change in the protons or, in other words, protons remain the same.
Expert Solution & Answer
Answer to Problem 4LC
Polyatomic ions and monoatomic ions both are charged species, but polyatomic ions are composed of two or more atoms and monoatomic ions are composed of only a single atom.
Explanation of Solution
The similarities between polyatomic ions and monoatomic ions are:
- Both are charged species and formed by gaining or losing electrons.
The differences between polyatomic ions and monoatomic ions are:
- Polyatomic ions are charged species that are composed of two or more atoms, but monoatomic ions are composed of only a single atom.
Chapter 9 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
Ch. 9.1 - Prob. 1SPCh. 9.1 - Prob. 2SPCh. 9.1 - Prob. 3LCCh. 9.1 - Prob. 4LCCh. 9.1 - Prob. 5LCCh. 9.1 - Prob. 6LCCh. 9.1 - Prob. 7LCCh. 9.1 - Prob. 8LCCh. 9.1 - Prob. 9LCCh. 9.2 - Prob. 10SP
Ch. 9.2 - Prob. 11SPCh. 9.2 - Prob. 12SPCh. 9.2 - Prob. 13SPCh. 9.2 - Prob. 14SPCh. 9.2 - Prob. 15SPCh. 9.2 - Prob. 16SPCh. 9.2 - Prob. 17SPCh. 9.2 - Prob. 18LCCh. 9.2 - Prob. 19LCCh. 9.2 - Prob. 20LCCh. 9.2 - Prob. 21LCCh. 9.2 - Prob. 22LCCh. 9.2 - Prob. 23LCCh. 9.2 - Prob. 24LCCh. 9.2 - Prob. 25LCCh. 9.2 - Prob. 26LCCh. 9.3 - Prob. 27SPCh. 9.3 - Prob. 28SPCh. 9.3 - Prob. 29LCCh. 9.3 - Prob. 30LCCh. 9.3 - Prob. 31LCCh. 9.3 - Prob. 32LCCh. 9.3 - Prob. 33LCCh. 9.3 - Prob. 34LCCh. 9.3 - Prob. 35LCCh. 9.3 - Prob. 36LCCh. 9.4 - Prob. 37SPCh. 9.4 - Prob. 38SPCh. 9.4 - Prob. 39SPCh. 9.4 - Prob. 40SPCh. 9.4 - Prob. 41LCCh. 9.4 - Prob. 42LCCh. 9.4 - Prob. 43LCCh. 9.4 - Prob. 44LCCh. 9.4 - Prob. 45LCCh. 9.4 - Prob. 46LCCh. 9.4 - Prob. 47LCCh. 9.5 - Prob. 48SPCh. 9.5 - Prob. 49SPCh. 9.5 - Prob. 50LCCh. 9.5 - Prob. 51LCCh. 9.5 - Prob. 52LCCh. 9.5 - Prob. 53LCCh. 9.5 - Prob. 54LCCh. 9.5 - Prob. 55LCCh. 9.5 - Prob. 56LCCh. 9 - Prob. 57ACh. 9 - Prob. 58ACh. 9 - Prob. 59ACh. 9 - Prob. 60ACh. 9 - Prob. 61ACh. 9 - Prob. 62ACh. 9 - Prob. 63ACh. 9 - Prob. 64ACh. 9 - Prob. 65ACh. 9 - Prob. 66ACh. 9 - Prob. 67ACh. 9 - Prob. 68ACh. 9 - Prob. 69ACh. 9 - Prob. 70ACh. 9 - Prob. 71ACh. 9 - Prob. 72ACh. 9 - Prob. 73ACh. 9 - Prob. 74ACh. 9 - Prob. 75ACh. 9 - Prob. 76ACh. 9 - Prob. 77ACh. 9 - Prob. 78ACh. 9 - Prob. 79ACh. 9 - Prob. 80ACh. 9 - Prob. 81ACh. 9 - Prob. 82ACh. 9 - Prob. 83ACh. 9 - Prob. 84ACh. 9 - Prob. 85ACh. 9 - Prob. 86ACh. 9 - Prob. 87ACh. 9 - Prob. 88ACh. 9 - Prob. 89ACh. 9 - Prob. 90ACh. 9 - Prob. 91ACh. 9 - Prob. 92ACh. 9 - Prob. 93ACh. 9 - Prob. 94ACh. 9 - Prob. 95ACh. 9 - Prob. 96ACh. 9 - Prob. 97ACh. 9 - Prob. 98ACh. 9 - Prob. 99ACh. 9 - Prob. 100ACh. 9 - Prob. 101ACh. 9 - Prob. 102ACh. 9 - Prob. 103ACh. 9 - Prob. 104ACh. 9 - Prob. 105ACh. 9 - Prob. 106ACh. 9 - Prob. 107ACh. 9 - Prob. 108ACh. 9 - Prob. 110ACh. 9 - Prob. 111ACh. 9 - Prob. 112ACh. 9 - Prob. 113ACh. 9 - Prob. 114ACh. 9 - Prob. 115ACh. 9 - Prob. 116ACh. 9 - Prob. 117ACh. 9 - Prob. 118ACh. 9 - Prob. 119ACh. 9 - Prob. 120ACh. 9 - Prob. 121ACh. 9 - Prob. 122ACh. 9 - Prob. 123ACh. 9 - Prob. 124ACh. 9 - Prob. 125ACh. 9 - Prob. 126ACh. 9 - Prob. 127ACh. 9 - Prob. 128ACh. 9 - Prob. 129ACh. 9 - Prob. 130ACh. 9 - Prob. 131ACh. 9 - Prob. 1STPCh. 9 - Prob. 2STPCh. 9 - Prob. 3STPCh. 9 - Prob. 4STPCh. 9 - Prob. 5STPCh. 9 - Prob. 6STPCh. 9 - Prob. 7STPCh. 9 - Prob. 8STPCh. 9 - Prob. 9STPCh. 9 - Prob. 10STPCh. 9 - Prob. 11STPCh. 9 - Prob. 12STPCh. 9 - Prob. 13STP
Knowledge Booster
Similar questions
- A first order reaction is 46.0% complete at the end of 59.0 minutes. What is the value of k? What is the half-life for this reaction? HOW DO WE GET THERE? The integrated rate law will be used to determine the value of k. In [A] [A]。 = = -kt What is the value of [A] [A]。 when the reaction is 46.0% complete?arrow_forward3. Provide the missing compounds or reagents. 1. H,NNH КОН 4 EN MN. 1. HBUCK = 8 хно Panely prowseful kanti-chuprccant fad, winddively, can lead to the crading of deduc din-willed, tica, The that chemooices in redimi Грин. " like (for alongan Ridovi MN نيا . 2. Cl -BuO 1. NUH 2.A A -BuOK THE CF,00,H Ex 5)arrow_forward2. Write a complete mechanism for the reaction shown below. NaOCH LOCH₁ O₂N NO2 CH₂OH, 20 °C O₂N NO2arrow_forward
- 4. Propose a synthesis of the target molecules from the respective starting materials. a) b) LUCH C Br OHarrow_forwardThe following mechanism for the gas phase reaction of H2 and ICI that is consistent with the observed rate law is: step 1 step 2 slow: H2(g) +ICI(g) → HCl(g) + HI(g) fast: ICI(g) + HI(g) → HCl(g) + |2(g) (1) What is the equation for the overall reaction? Use the smallest integer coefficients possible. If a box is not needed, leave it blank. + → + (2) Which species acts as a catalyst? Enter formula. If none, leave box blank: (3) Which species acts as a reaction intermediate? Enter formula. If none, leave box blank: (4) Complete the rate law for the overall reaction that is consistent with this mechanism. (Use the form k[A][B]"..., where '1' is understood (so don't write it) for m, n etc.) Rate =arrow_forwardPlease correct answer and don't use hand rating and don't use Ai solutionarrow_forward
- 1. For each of the following statements, indicate whether they are true of false. ⚫ the terms primary, secondary and tertiary have different meanings when applied to amines than they do when applied to alcohols. • a tertiary amine is one that is bonded to a tertiary carbon atom (one with three C atoms bonded to it). • simple five-membered heteroaromatic compounds (e.g. pyrrole) are typically more electron rich than benzene. ⚫ simple six-membered heteroaromatic compounds (e.g. pyridine) are typically more electron rich than benzene. • pyrrole is very weakly basic because protonation anywhere on the ring disrupts the aromaticity. • thiophene is more reactive than benzene toward electrophilic aromatic substitution. • pyridine is more reactive than nitrobenzene toward electrophilic aromatic substitution. • the lone pair on the nitrogen atom of pyridine is part of the pi system.arrow_forwardThe following reactions are NOT ordered in the way in which they occur. Reaction 1 PhO-OPh Reaction 2 Ph-O -CH₂ heat 2 *OPh Pho -CH2 Reaction 3 Ph-O ⚫OPh + -CH₂ Reaction 4 Pho Pho + H₂C OPh + CHOPh H₂C -CH₂ Reactions 1 and 3 Reaction 2 O Reaction 3 ○ Reactions 3 and 4 ○ Reactions 1 and 2 Reaction 4 ○ Reaction 1arrow_forwardSelect all possible products from the following reaction: NaOH H₂O a) b) ОН HO O HO HO e) ОН f) O HO g) h) + OHarrow_forward
- 3. Draw diagrams to represent the conjugation in these molecules. Draw two types of diagram: a. Show curly arrows linking at least two different ways of representing the molecule b. Indicate with dotted lines and partial charges (where necessary) the partial double bond (and charge) distribution H₂N* H₂N -NH2arrow_forwardQuestion 2 of 25 point Question Attempt 3 of Ulimited Draw the structure for 3-chloro-4-ethylheptane. Part 2 of 3 Click and drag to start drawing a structure. Draw the structure for 1-chloro-4-ethyl-3-lodooctane. Click and drag to start drawing a structure. X G X B c Part 3 of 30 Draw the structure for (R)-2-chlorobutane. Include the stereochemistry at all stereogenic centers. Check Click and drag to start drawing a structure. G X A 。 MacBook Pro G P Save For Later Submit Assignment Privacyarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY