(a)
Interpretation: The electron dot structure for the substance is to be drawn.
Concept Introduction: If the compound's molecular formula is known, electron dot structures or the Lewis dot formulas can be drawn. The type of bond and the location of the atoms in a molecule that are related to one another are determined by the electron dot structure.
(a)
Answer to Problem 129A
The electron dot structure of 
is given as follows:
Explanation of Solution
The bonding
The given substance is 
The electron dot structure of 
is given as follows:
There is a single bond between 
and 
The valency of 
is seven.
Since one electron is involved in bonding, the remaining six valence electrons form three lone pairs.
(b)
Interpretation: The electron dot structure for the substance is to be drawn.
Concept Introduction: If the compound's molecular formula is known, electron dot structures or the Lewis dot formulas can be drawn. The type of bond and the location of the atoms in a molecule that are related to one another are determined by the electron dot structure.
(b)
Answer to Problem 129A
The electron dot structure of 
is given as follows:
Explanation of Solution
The bonding atoms, the number of bonds in the molecule, and the lone pairs still present in the bonding atoms are all described by an electron dot structure.
The given substance is 
The electron dot structure of 
is given as follows:
There is a triple bond between 
and 
Since three electrons in C is involved in bonding, the remaining valence electrons form one lone pair.
(c)
Interpretation: The electron dot structure for the substance is to be drawn.
Concept Introduction: If the compound's molecular formula is known, electron dot structures or the Lewis dot formulas can be drawn. The type of bond and the location of the atoms in a molecule that are related to one another are determined by the electron dot structure.
(c)
Answer to Problem 129A
The electron dot structure of 
is given as follows:
Explanation of Solution
The bonding atoms, the number of bonds in the molecule, and the lone pairs still present in the bonding atoms are all described by an electron dot structure.
The given substance is 
The electron dot structure of 
is given as follows:
There is a double bond between 
and 
The valency of 
is four
Since four electron is involved in bonding, there is no lone pairs of electrons in carbon.
There are two lone pairs of electrons in oxygen.
(d)
Interpretation: The electron dot structure for the substance is to be drawn.
Concept Introduction: If the compound's molecular formula is known, electron dot structures or the Lewis dot formulas can be drawn. The type of bond and the location of the atoms in a molecule that are related to one another are determined by the electron dot structure.
(d)
Answer to Problem 129A
The electron dot structure of 
is given as follows:
Explanation of Solution
The bonding atoms, the number of bonds in the molecule, and the lone pairs still present in the bonding atoms are all described by an electron dot structure.
The given substance is 
The electron dot structure of 
is given as follows:
There is a single bond between 
and 
The valency of 
is five.
Since three electrons of nitrogen is involved in bonding, the remaining two valence electrons form one lone pair.
(e)
Interpretation: The electron dot structure for the substance is to be drawn.
Concept Introduction: If the compound's molecular formula is known, electron dot structures or the Lewis dot formulas can be drawn. The type of bond and the location of the atoms in a molecule that are related to one another are determined by the electron dot structure.
(e)
Answer to Problem 129A
The electron dot structure of 
is given as follows:
Explanation of Solution
The bonding atoms, the number of bonds in the molecule, and the lone pairs still present in the bonding atoms are all described by an electron dot structure.
The given substance is 
The electron dot structure of 
is given as follows:
There is a single bond between 
and 
The valency of 
is four.
Since four electrons are involved in bonding, there is no lone pair in carbon.
(f)
Interpretation: The electron dot structure for the substance is to be drawn.
Concept Introduction: If the compound's molecular formula is known, electron dot structures or the Lewis dot formulas can be drawn. The type of bond and the location of the atoms in a molecule that are related to one another are determined by the electron dot structure.
(f)
Answer to Problem 129A
The electron dot structure of 
is given as follows:
Explanation of Solution
The bonding atoms, the number of bonds in the molecule, and the lone pairs still present in the bonding atoms are all described by an electron dot structure.
The given substance is 
The electron dot structure of 
is given as follows:
There is a single bond between 
and 
The valency of 
is six
Since two electron is involved in bonding, the remaining four valence electrons form two lone pairs.
(g)
Interpretation: The electron dot structure for the substance is to be drawn.
Concept Introduction: If the compound's molecular formula is known, electron dot structures or the Lewis dot formulas can be drawn. The type of bond and the location of the atoms in a molecule that are related to one another are determined by the electron dot structure.
(g)
Answer to Problem 129A
The electron dot structure of 
is given as follows:
Explanation of Solution
The bonding atoms, the number of bonds in the molecule, and the lone pairs still present in the bonding atoms are all described by an electron dot structure.
The given substance is 
The electron dot structure of 
is given as follows:
There is a single bond between 
and 
The valency of 
is four.
Since four electrons are involved in bonding, there is no lone pairs of electron in carbon.
Chapter 9 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- Deducing the reactants of a Diels-Alder reaction vn the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ O If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Click and drag to start drawing a structure. Product can't be made in one step. Explanation Checkarrow_forwardPredict the major products of the following organic reaction: Δ ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. Larrow_forward> Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ • If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. If your answer is no, check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. Х © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accesarrow_forward
- Predict the major products of the following organic reaction: O O + A ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. eserved. Terms of Use | Privacy Center >arrow_forward(EXM 2, PRBLM 3) Here is this problem, can you explain it to me and show how its done. Thank you I need to see the work for like prbl solving.arrow_forwardcan someone draw out the reaction mechanism for this reaction showing all bonds, intermediates and side products Comment on the general features of the 1H-NMR spectrum of isoamyl ester provided belowarrow_forward
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