(a)
Interpretation: The type of ion and symbol for the ion formed by the given element is to be identified.
Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of electron/s whereas a cation is formed by losing electron/s.
(a)
Answer to Problem 6LC
The ion formed by the given element is
Explanation of Solution
The given element is potassium. It belongs to group 1 which is alkali metals. It has 1 valence electron. In order to complete the octet, it can lose 1 electron to form a cation with a +1 charge. The symbol of the ion is
(b)
Interpretation: The type of ion and symbol for the ion formed by the given element is to be identified.
Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of electron/s whereas a cation is formed by losing electron/s.
(b)
Answer to Problem 6LC
The ion formed by the given element is
Explanation of Solution
The given element is oxygen. It belongs to group 16 and has 6 valence electrons. In order to complete the octet, it can gain 2 electrons to form an anion with a -2 charge. The symbol of the ion is
(c)
Interpretation: The type of ion and symbol for the ion formed by the given element is to be identified.
Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of electron/s whereas a cation is formed by losing electron/s.
(c)
Answer to Problem 6LC
The ion formed by the given element is
Explanation of Solution
The given element is bromine. It belongs to group 17 in the periodic table. It has 7 valence electrons. Thus, in order to complete the octet, it can gain 1 electron to form an anion with a -1 charge. The symbol is
(d)
Interpretation: The type of ion and symbol for the ion formed by the given element is to be identified.
Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of electron/s whereas a cation is formed by losing electron/s.
(d)
Answer to Problem 6LC
The ion formed by the given element is
Explanation of Solution
The given element is tin. It can lose 2 electrons to form a cation with a +2 charge. The symbol is
(e)
Interpretation: The type of ion and symbol for the ion formed by the given element is to be identified.
Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of electron/s whereas a cation is formed by losing electron/s.
(e)
Answer to Problem 6LC
The ion formed by the given element is
Explanation of Solution
The given element is beryllium. It belongs to group 2 which is alkaline earth metal. It has 2 valence electrons. In order to complete the octet, it can lose 2 electrons to form a cation with a +2 charge. The symbol is
(f)
Interpretation: The type of ion and symbol for the ion formed by the given element is to be identified.
Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of electron/s whereas a cation is formed by losing electron/s.
(f)
Answer to Problem 6LC
The ion formed by the given element is
Explanation of Solution
The given element is cobalt. It can lose 3 electrons to form a cation with a +3 charge. The symbol is
Chapter 9 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- Deducing the reactants of a Diels-Alder reaction vn the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ O If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Click and drag to start drawing a structure. Product can't be made in one step. Explanation Checkarrow_forwardPredict the major products of the following organic reaction: Δ ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. Larrow_forward> Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ • If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. If your answer is no, check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. Х © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accesarrow_forward
- Predict the major products of the following organic reaction: O O + A ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. eserved. Terms of Use | Privacy Center >arrow_forward(EXM 2, PRBLM 3) Here is this problem, can you explain it to me and show how its done. Thank you I need to see the work for like prbl solving.arrow_forwardcan someone draw out the reaction mechanism for this reaction showing all bonds, intermediates and side products Comment on the general features of the 1H-NMR spectrum of isoamyl ester provided belowarrow_forward
- What would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 3 2. n-BuLi • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Click and drag to start drawing a structure.arrow_forwardIdentify the missing organic reactants in the following reaction: X + Y H+ two steps Note: This chemical equation only focuses on the important organic molecules in the reaction. Additional inorganic or small-molecule reactants or products (like H2O) are not shown. In the drawing area below, draw the skeletal ("line") structures of the missing organic reactants X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Click and drag to start drawing a structure. Х :arrow_forwardDraw the mechanism of friedel-crafts acylation using acetyl chloride of m-Xylenearrow_forward
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