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(a)
Interpretation: Choose the more electronegative element from each of the given pairs.
Concept Introduction: The tendency of a covalently bonded atom to attract the bonded pair of electrons towards it is known as electronegativity. It is a unit less quantity.
(a)
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Answer to Problem 122A
Lithium is more electronegative than cesium.
Explanation of Solution
The electronegativity of elements decreases on moving down the group in a periodic table. So when we compare the second element and sixth element of a group, the second element lithium has a higher electronegativity than cesium, the sixth element.
(b)
Interpretation: Choose the more electronegative element from each of the given pairs.
Concept Introduction: The tendency of a covalently bonded atom to attract the bonded pair of electrons towards it is known as electronegativity. It is a unit less quantity.
(b)
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Answer to Problem 122A
Among strontium and iodine, iodine has the higher electronegativity value.
Explanation of Solution
Both strontium and iodine belong to the fifth period of the periodic table. But strontium is an s-block element lying on the left side and iodine is a p-block element lying on the right side. The electronegativity of elements increases on moving left to right across the period. Thus iodine is more electronegative than strontium.
(c)
Interpretation: Choose the more electronegative element from each of the given pairs.
Concept Introduction: The tendency of a covalently bonded atom to attract the bonded pair of electrons towards it is known as electronegativity. It is a unit less quantity.
(c)
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Answer to Problem 122A
On comparing sulfur and magnesium, sulfur has higher electronegativity values than magnesium.
Explanation of Solution
Sulfur and magnesium belong to the third period. Magnesium is a second group element while sulfur is a Group 6A element. On moving from left to right electronegativity increases. Hence, S has a higher electronegativity than Mg.
(d)
Interpretation: Choose the more electronegative element from each of the given pairs.
Concept Introduction: The tendency of a covalently bonded atom to attract the bonded pair of electrons towards it is known as electronegativity. It is a unit less quantity.
(d)
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Answer to Problem 122A
Among oxygen and selenium, oxygen has a higher electronegativity value.
Explanation of Solution
Oxygen and selenium belong to the same group with oxygen being the first member and selenium the third one. The electronegativity value decreases on moving down the group in a periodic table. So oxygen has a higher electronegativity than selenium.
(e)
Interpretation: Choose the more electronegative element from each of the given pairs.
Concept Introduction: The tendency of a covalently bonded atom to attract the bonded pair of electrons towards it is known as electronegativity. It is a unit less quantity.
(e)
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Answer to Problem 122A
The electronegativity value of nitrogen is higher than that of tellurium.
Explanation of Solution
Nitrogen and tellurium belong to adjacent groups. Nitrogen in the precedent group should have lesser electronegativity than tellurium, but the latter belongs to the fifth period where the nuclear attraction is very weak when compared with those of nitrogen in the second period. So, nitrogen attracts electrons more effectively than tellurium and has a greater electronegativity than tellurium.
(f)
Interpretation: Choose the more electronegative element from each of the given pairs.
Concept Introduction: The tendency of a covalently bonded atom to attract the bonded pair of electrons towards it is known as electronegativity. It is a unit less quantity.
(f)
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Answer to Problem 122A
Among carbon and fluorine, fluorine is more electronegative.
Explanation of Solution
Carbon belongs to Group 4A and fluorine belongs to Group 7A. Fluorine is two groups right to carbon in the periodic table and hence has a higher electronegativity than carbon.
Chapter 9 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
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- Predict the major products of the following organic reaction: O O + A ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. eserved. Terms of Use | Privacy Center >arrow_forward(EXM 2, PRBLM 3) Here is this problem, can you explain it to me and show how its done. Thank you I need to see the work for like prbl solving.arrow_forwardcan someone draw out the reaction mechanism for this reaction showing all bonds, intermediates and side products Comment on the general features of the 1H-NMR spectrum of isoamyl ester provided belowarrow_forward
- What would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 3 2. n-BuLi • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Click and drag to start drawing a structure.arrow_forwardIdentify the missing organic reactants in the following reaction: X + Y H+ two steps Note: This chemical equation only focuses on the important organic molecules in the reaction. Additional inorganic or small-molecule reactants or products (like H2O) are not shown. In the drawing area below, draw the skeletal ("line") structures of the missing organic reactants X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Click and drag to start drawing a structure. Х :arrow_forwardDraw the mechanism of friedel-crafts acylation using acetyl chloride of m-Xylenearrow_forward
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