(a)
Interpretation: Formulas and names of the given compounds are to be stated. Also, it is needed to find out whether they are ionic or molecular compounds.
Concept Introduction: Molecular compounds are formed by the sharing of electrons between non-metals. They are also known as covalent compounds. The naming of these compounds is: Name of first element + Stem of second element + ‘ide’.
(a)
Answer to Problem 104A
The name of the given compound is phosphorous trichloride, with a chemical formula
Explanation of Solution
The given compound contains one phosphorous (P) atom and three chlorine (Cl) atoms. The prefix used for three is ‘tri’ thus the name of the compound is phosphorous trichloride. Since this compound is formed between two non-metals by the sharing of electrons, they are molecular compounds.
(b)
Interpretation: Formulas and names of the given compounds are to be stated. Also, it is needed to find out whether they are ionic or molecular compounds.
Concept Introduction: Molecular compounds are formed by the sharing of electrons between non-metals. They are also known as covalent compounds. The naming of these compounds is: Name of first element + Stem of second element + ‘ide’.
(b)
Answer to Problem 104A
The name of the given compound is disulphur dichloride. It is a molecular compound having a chemical formula
Explanation of Solution
The given compound contains two sulfur (S) atoms and two chlorine(Cl) atoms. The prefix used for two is ‘di’. Thus, the name of the compound is disulphur dichloride. Since this compound is formed between two non-metals by the sharing of electrons, they are molecular compounds.
(c)
Interpretation: Formulas and names of the given compounds are to be stated. Also, it is needed to find out whether they are ionic or molecular compounds.
Concept Introduction: Molecular compounds are formed by the sharing of electrons between non-metals. They are also known as covalent compounds. The naming of these compounds is: Name of first element + Stem of second element + ‘ide’.
(c)
Answer to Problem 104A
The name of the given compound is carbon tetrachloride, and its chemical formula is
Explanation of Solution
The given compound is formed between two non-metals carbon and chlorine. Hence, it is a molecular compound. It contains one carbon(C) atom and four chlorine(Cl) atoms. The prefix used for four is ‘tetra’ and thus, the name carbon tetrachloride.
(d)
Interpretation: Formulas and names of the given compounds are to be stated. Also, it is needed to find out whether they are ionic or molecular compounds.
Concept Introduction: Molecular compounds are formed by the sharing of electrons between non-metals. They are also known as covalent compounds. The naming of these compounds is: Name of first element + Stem of second element + ‘ide’.
(d)
Answer to Problem 104A
The name of the given compound is sulfur dichloride. It is a molecular compound with a chemical formula
Explanation of Solution
The given compound contains two chlorine (Cl) atoms bonded to a sulfur (S) atom. The prefix used to denote two is ‘di’. Thus the name of the compound is sulfur dichloride. Since both sulfur and chlorine are non-metals, the compound is a molecular compound.
Chapter 9 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- A first order reaction is 46.0% complete at the end of 59.0 minutes. What is the value of k? What is the half-life for this reaction? HOW DO WE GET THERE? The integrated rate law will be used to determine the value of k. In [A] [A]。 = = -kt What is the value of [A] [A]。 when the reaction is 46.0% complete?arrow_forward3. Provide the missing compounds or reagents. 1. H,NNH КОН 4 EN MN. 1. HBUCK = 8 хно Panely prowseful kanti-chuprccant fad, winddively, can lead to the crading of deduc din-willed, tica, The that chemooices in redimi Грин. " like (for alongan Ridovi MN نيا . 2. Cl -BuO 1. NUH 2.A A -BuOK THE CF,00,H Ex 5)arrow_forward2. Write a complete mechanism for the reaction shown below. NaOCH LOCH₁ O₂N NO2 CH₂OH, 20 °C O₂N NO2arrow_forward
- 4. Propose a synthesis of the target molecules from the respective starting materials. a) b) LUCH C Br OHarrow_forwardThe following mechanism for the gas phase reaction of H2 and ICI that is consistent with the observed rate law is: step 1 step 2 slow: H2(g) +ICI(g) → HCl(g) + HI(g) fast: ICI(g) + HI(g) → HCl(g) + |2(g) (1) What is the equation for the overall reaction? Use the smallest integer coefficients possible. If a box is not needed, leave it blank. + → + (2) Which species acts as a catalyst? Enter formula. If none, leave box blank: (3) Which species acts as a reaction intermediate? Enter formula. If none, leave box blank: (4) Complete the rate law for the overall reaction that is consistent with this mechanism. (Use the form k[A][B]"..., where '1' is understood (so don't write it) for m, n etc.) Rate =arrow_forwardPlease correct answer and don't use hand rating and don't use Ai solutionarrow_forward
- 1. For each of the following statements, indicate whether they are true of false. ⚫ the terms primary, secondary and tertiary have different meanings when applied to amines than they do when applied to alcohols. • a tertiary amine is one that is bonded to a tertiary carbon atom (one with three C atoms bonded to it). • simple five-membered heteroaromatic compounds (e.g. pyrrole) are typically more electron rich than benzene. ⚫ simple six-membered heteroaromatic compounds (e.g. pyridine) are typically more electron rich than benzene. • pyrrole is very weakly basic because protonation anywhere on the ring disrupts the aromaticity. • thiophene is more reactive than benzene toward electrophilic aromatic substitution. • pyridine is more reactive than nitrobenzene toward electrophilic aromatic substitution. • the lone pair on the nitrogen atom of pyridine is part of the pi system.arrow_forwardThe following reactions are NOT ordered in the way in which they occur. Reaction 1 PhO-OPh Reaction 2 Ph-O -CH₂ heat 2 *OPh Pho -CH2 Reaction 3 Ph-O ⚫OPh + -CH₂ Reaction 4 Pho Pho + H₂C OPh + CHOPh H₂C -CH₂ Reactions 1 and 3 Reaction 2 O Reaction 3 ○ Reactions 3 and 4 ○ Reactions 1 and 2 Reaction 4 ○ Reaction 1arrow_forwardSelect all possible products from the following reaction: NaOH H₂O a) b) ОН HO O HO HO e) ОН f) O HO g) h) + OHarrow_forward
- 3. Draw diagrams to represent the conjugation in these molecules. Draw two types of diagram: a. Show curly arrows linking at least two different ways of representing the molecule b. Indicate with dotted lines and partial charges (where necessary) the partial double bond (and charge) distribution H₂N* H₂N -NH2arrow_forwardQuestion 2 of 25 point Question Attempt 3 of Ulimited Draw the structure for 3-chloro-4-ethylheptane. Part 2 of 3 Click and drag to start drawing a structure. Draw the structure for 1-chloro-4-ethyl-3-lodooctane. Click and drag to start drawing a structure. X G X B c Part 3 of 30 Draw the structure for (R)-2-chlorobutane. Include the stereochemistry at all stereogenic centers. Check Click and drag to start drawing a structure. G X A 。 MacBook Pro G P Save For Later Submit Assignment Privacyarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
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