
(a)
Interpretation: The incorrectness in the given formula is to be stated and the correct formula is to be given.
Concept Introduction : Molecular compounds are formed by the sharing of electrons between non-metals. They are known as carbon compounds. The naming of the compound is
Ionic compounds are formed by the transfer of electrons between metal and non-metal. They are named as
(a)

Answer to Problem 98A
The formula is correct, and its name is caesium chloride.
Explanation of Solution
The given compound is
(b)
Interpretation: The incorrectness in the given formula is to be stated and the correct formula is to be given.
Concept Introduction : Molecular compounds are formed by the sharing of electrons between non-metals. They are known as carbon compounds. The naming of the compound is
Ionic compounds are formed by the transfer of electrons between metal and non-metal. They are named as
(b)

Answer to Problem 98A
The formula is wrong as the neon is inert gas and it will to not form compounds with metal (lithium).
Explanation of Solution
The given compound is
(c)
Interpretation: The incorrectness in the given formula is to be stated and the correct formula is to be given.
Concept Introduction : Molecular compounds are formed by the sharing of electrons between non-metals. They are known as carbon compounds. The naming of the compound is
Ionic compounds are formed by the transfer of electrons between metal and non-metal. They are named as
(c)

Answer to Problem 98A
The formula is incorrect as both ions have same charge so it would be
Explanation of Solution
The given compound is
(d)
Interpretation: The incorrectness in the given formula is to be stated and the correct formula is to be given.
Concept Introduction : Molecular compounds are formed by the sharing of electrons between non-metals. They are known as carbon compounds. The naming of the compound is
Ionic compounds are formed by the transfer of electrons between metal and non-metal. They are named as
(d)

Answer to Problem 98A
The formula is incorrect as both ions have same charge so it would be
Explanation of Solution
The given compound is
Chapter 9 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
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- When two solutions, one of 0.1 M KCl (I) and the other of 0.1 M MCl (II), are brought into contact by a membrane. The cation M cannot cross the membrane. At equilibrium, x moles of K+ will have passed from solution (I) to (II). To maintain the neutrality of the two solutions, x moles of Cl- will also have to pass from I to II. Explain this equality: (0.1 - x)/x = (0.1 + x)/(0.1 - x)arrow_forwardCalculate the variation in the potential of the Pt/MnO4-, Mn2+ pair with pH, indicating the value of the standard potential. Data: E0 = 1.12.arrow_forwardGiven the cell: Pt l H2(g) l dis X:KCl (sat) l Hg2Cl2(s) l Hg l Pt. Calculate the emf of the cell as a function of pH.arrow_forward
- The decimolar calomel electrode has a potential of 0.3335 V at 25°C compared to the standard hydrogen electrode. If the standard reduction potential of Hg22+ is 0.7973 V and the solubility product of Hg2Cl2 is 1.2x 10-18, find the activity of the chlorine ion at this electrode.Data: R = 8.314 J K-1 mol-1, F = 96485 C mol-1, T = 298.15 K.arrow_forward2. Add the following group of numbers using the correct number of significant figures for the answer. Show work to earn full credit such as rounding off the answer to the correct number of significant figures. Replace the question marks with the calculated answers or write the calculated answers near the question marks. 10916.345 37.40832 5.4043 3.94 + 0.0426 ? (7 significant figures)arrow_forwardThe emf at 25°C of the cell: Pt l H2(g) l dis X:KCl (sat) l Hg2Cl2(s) l Hg l Pt was 612 mV. When solution X was replaced by normal phosphate buffer solution with a pH of 6.86, the emf was 741 mV. Calculate the pH of solution X.arrow_forward
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