(a)
Interpretation: The name of the given compound needs to be stated.
Concept Introduction: While naming a molecular compound the name of the first element is named first followed by that of the second element. The number of atoms of each element present in the compound is added as a prefix.
(a)
Answer to Problem 72A
The name of the given compound is diphosphorus pentoxide.
Explanation of Solution
Given compound contains two phosphorous atoms and five oxygen atoms, the name of the first element phosphorous with the prefix ‘di’ is written followed by the name of the second compound oxide with the prefix ‘penta’.
(b)
Interpretation: The name of the given compound needs to be stated.
Concept Introduction: While naming a molecular compound the name of the first element is named first followed by that of the second element. The number of atoms of each element present in the compound is added as a prefix.
(b)
Answer to Problem 72A
The name of the given compound is carbon tetrachloride.
Explanation of Solution
Given compound contains a carbon atom and four chlorine atoms, hence the name carbon tetrachloride. The prefix ‘tetra’ is used to denote four.
(c)
Interpretation: The formula of the given compound needs to be stated.
Concept Introduction: While naming a molecular compound the name of the first element is named first followed by that of the second element. The number of atoms of each element present in the compound is added as a prefix.
(c)
Answer to Problem 72A
The formula of boron trichloride is
Explanation of Solution
The symbol of the first element is written followed by the second element. Since there are three chlorine atoms, subscript 3 is written.
(d)
Interpretation: The formula of the given compound needs to be stated.
Concept Introduction: While naming a molecular compound the name of the first element is named first followed by that of the second element. The number of atoms of each element present in the compound is added as a prefix.
(d)
Answer to Problem 72A
The compound dinitrogen tetrahydride can be represented by the chemical formula
Explanation of Solution
In the given compound, there are two nitrogen atoms and four hydrogen atoms. It is represented by writing their symbols with corresponding subscripts.
Chapter 9 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- In the normal hydrogen electrode, the current flows through the electrode when the power difference of the interface is +5 mV. Calculate the overvoltage n at pH = 2, if the equilibrium potential is -0.118 V.arrow_forwardIn the normal hydrogen electrode, the balance potential difference in the interface is 0 and the current flow across the electrode when the interface potential difference is +5 mV. Explain briefly. Is the overvoltage 5 mV?arrow_forwardIn the normal hydrogen electrode, the balance potential difference in the interface is 0 mV, the maximum potential is 5 mV. Explain briefly.arrow_forward
- utron eutro cle TH tro (Na (b) Atoms are said to be electrically neutral. Explain. (c) Distinguish between the following: (i) Atomic number and mass number. (ii) Mass number and relative atomic mass. 2. An isotope Q, has 18 neutrons a mass number of 34. (a) (i) Draw the atomic structure of Q. (ii) Write its electron arrangement (b) To which period and group does Q belong? Explain your answer. (c) How does Q form its ion? Explain. 3. (a) Determine the relative atomic mass of the following elements = compositions occur in the proportions given. (i) Neon 20 21 22. Ne (90.92%), 10Ne (0.26%), and 10Ne (8.82%) (ii) Argon 36 38 40 18 Ar (0.34%), 18 Ar (0.06%) and 18 Ar (99.6%)arrow_forwardIn the normal hydrogen electrode, the balance potential difference in the interface is this, the maximum potential is 5 mV. Explain briefly.arrow_forwardThe electrode balance potential is -0.118 V and the interface potential difference is +5 mV. The overvoltage n will be 0.005 - (-0.118) = 0.123 V. Is it correct?arrow_forward
- In the electrode Pt, H2(1 atm) | H+(a=1), if the electrode balance potential is -0.118 V and the interface potential difference is +5 mV. The current voltage will be 0.005 - (-0.118) = 0.123 V ¿Correcto?arrow_forwardIn the electrode Pt, H2(1 atm) | H+(a=1) at 298K is 0.79 mA cm-2. If the balance potential of the electrode is -0.118 V and the potential difference of the interface is +5 mV. Determine its potential.arrow_forwardIn one electrode: Pt, H2(1 atm) | H+(a=1), the interchange current density at 298K is 0.79 mA·cm-2. If the voltage difference of the interface is +5 mV. What will be the correct intensity at pH = 2?. Maximum transfer voltage and beta = 0.5.arrow_forward
- In a Pt electrode, H2(1 atm) | H+(a=1), the interchange current density of an electrode is 0.79 mA cm-2. ¿Qué corriente flow across the electrode of área 5 cm2 when the difference in potential of the interface is +5 mV?.arrow_forwardIf the current voltage is n = 0.14 V, indicate which of the 2 voltage formulas of the ley of Tafel must be applied i a a) == exp (1-B). xp[(1 - ß³): Fn Fn a b) == exp B RT RTarrow_forwardIf the current voltage is n = 0.14 V. Indicate which of the 2 formulas must be applied a) = a T = i exp[(1 - p) F Fn Fn b) i==exp B RTarrow_forward
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY