2. Enthalpy and Free Energy calculation Mallarity 2144 42C AIC 17 Inkxp ump (LUKANYA) [-]- Kip 279.15 3.38x30 R. & 10 010 -13.9 294.25 1.39x30 2.67 10 713x104 4L 317x30 477% 10 227 N 107 453 313.15 279.35 3.38 x 30 24x10 615x104 278.83 300x30 9.53 10 9.05% 10. 21C 244.35 K 3.40 x 10-3 5.72 & 104 3.27s 10 14.9 12.0 439 show your calculations a. Find the slope (from the above equation, the slope = -AH/R) Slope (m)=-0.22 b. Using R 8.314J/K-mol, calculate AH Rearrange and solve for AS = -116.3 6. Is the sign of AS consistent with your expectations for the dissolving of a salt in water? InKap (InKsp) vs. (1/T K) y=-0.22x-12.88 R=0.0331 0 2 3 4 S 6 2 4 6 -8 -10 -11.9 -12 -13.9 -14 -16 -18 15.3 1/T(K) -12 -139 -14.9 3. The equation of the plot in terms of entropy, en- thalpy and Ksp is InKsp=-AH/RT + AS/R, you will be using this to calculate the unknowns below 4. The slope of the plot will tell you about the enthalpy (AH) of the dissolution of KHT AH = (-0.22) x (8.314) = 1.829 J/mol = 1.829 J/mol -13.99=-(1829/8.314). 1/294.85+ AS/4-3M -0.00064739 -13.99-03+A5/8.314 +6.47407-64/8.314 45=-13.948.314 -13.99435x 2-114.3 5. The y-intercept value will tell you about the en- tropy of the reaction Write a. Using the slope, plug one point into the equation and calculate the intercept your line equation here and show your calcu- lations: (InKsp = -AH/RT + AS/R) End of document
2. Enthalpy and Free Energy calculation Mallarity 2144 42C AIC 17 Inkxp ump (LUKANYA) [-]- Kip 279.15 3.38x30 R. & 10 010 -13.9 294.25 1.39x30 2.67 10 713x104 4L 317x30 477% 10 227 N 107 453 313.15 279.35 3.38 x 30 24x10 615x104 278.83 300x30 9.53 10 9.05% 10. 21C 244.35 K 3.40 x 10-3 5.72 & 104 3.27s 10 14.9 12.0 439 show your calculations a. Find the slope (from the above equation, the slope = -AH/R) Slope (m)=-0.22 b. Using R 8.314J/K-mol, calculate AH Rearrange and solve for AS = -116.3 6. Is the sign of AS consistent with your expectations for the dissolving of a salt in water? InKap (InKsp) vs. (1/T K) y=-0.22x-12.88 R=0.0331 0 2 3 4 S 6 2 4 6 -8 -10 -11.9 -12 -13.9 -14 -16 -18 15.3 1/T(K) -12 -139 -14.9 3. The equation of the plot in terms of entropy, en- thalpy and Ksp is InKsp=-AH/RT + AS/R, you will be using this to calculate the unknowns below 4. The slope of the plot will tell you about the enthalpy (AH) of the dissolution of KHT AH = (-0.22) x (8.314) = 1.829 J/mol = 1.829 J/mol -13.99=-(1829/8.314). 1/294.85+ AS/4-3M -0.00064739 -13.99-03+A5/8.314 +6.47407-64/8.314 45=-13.948.314 -13.99435x 2-114.3 5. The y-intercept value will tell you about the en- tropy of the reaction Write a. Using the slope, plug one point into the equation and calculate the intercept your line equation here and show your calcu- lations: (InKsp = -AH/RT + AS/R) End of document
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section5.5: Enthalpy Changes For Chemical Reactions
Problem 1RC: 1. For the reaction 2 Hg(l) + O2(g) → 2 HgO(s), ∆rH° = 181.6 kJ/mol-rxn. What is the enthalpy change...
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Please help with number 6 I got a negative number could that be right?
![2. Enthalpy and Free Energy calculation
Mallarity
2144
42C
AIC
17
Inkxp
ump
(LUKANYA)
[-]-
Kip
279.15
3.38x30
R. & 10
010
-13.9
294.25
1.39x30
2.67 10
713x104
4L
317x30
477% 10
227 N 107
453
313.15
279.35
3.38 x 30
24x10
615x104
278.83
300x30
9.53 10
9.05% 10.
21C
244.35 K
3.40 x 10-3
5.72 & 104
3.27s 10
14.9
12.0
439
show your calculations
a. Find the slope (from the above
equation, the slope = -AH/R)
Slope (m)=-0.22
b. Using R 8.314J/K-mol, calculate AH
Rearrange and solve for AS = -116.3
6. Is the sign of AS consistent with your expectations
for the dissolving of a salt in water?
InKap
(InKsp) vs. (1/T K)
y=-0.22x-12.88
R=0.0331
0
2
3
4
S
6
2
4
6
-8
-10
-11.9
-12
-13.9
-14
-16
-18
15.3
1/T(K)
-12
-139
-14.9
3. The equation of the plot in terms of entropy, en-
thalpy and Ksp is
InKsp=-AH/RT + AS/R, you will be using
this to calculate the unknowns below
4. The slope of the plot will tell you about the
enthalpy (AH) of the dissolution of KHT
AH = (-0.22) x (8.314)
= 1.829 J/mol
= 1.829 J/mol
-13.99=-(1829/8.314). 1/294.85+ AS/4-3M
-0.00064739
-13.99-03+A5/8.314
+6.47407-64/8.314
45=-13.948.314
-13.99435x
2-114.3
5. The y-intercept value will tell you about the en-
tropy of the reaction
Write
a. Using the slope, plug one point into the
equation and calculate the intercept
your line equation here and show your calcu-
lations: (InKsp = -AH/RT + AS/R)
End of document](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F98788fff-5d55-4f08-bd33-832b3c76eea7%2Fe9b197d5-9bf2-4205-9f41-5bb1f1199ea9%2F46otu0n_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. Enthalpy and Free Energy calculation
Mallarity
2144
42C
AIC
17
Inkxp
ump
(LUKANYA)
[-]-
Kip
279.15
3.38x30
R. & 10
010
-13.9
294.25
1.39x30
2.67 10
713x104
4L
317x30
477% 10
227 N 107
453
313.15
279.35
3.38 x 30
24x10
615x104
278.83
300x30
9.53 10
9.05% 10.
21C
244.35 K
3.40 x 10-3
5.72 & 104
3.27s 10
14.9
12.0
439
show your calculations
a. Find the slope (from the above
equation, the slope = -AH/R)
Slope (m)=-0.22
b. Using R 8.314J/K-mol, calculate AH
Rearrange and solve for AS = -116.3
6. Is the sign of AS consistent with your expectations
for the dissolving of a salt in water?
InKap
(InKsp) vs. (1/T K)
y=-0.22x-12.88
R=0.0331
0
2
3
4
S
6
2
4
6
-8
-10
-11.9
-12
-13.9
-14
-16
-18
15.3
1/T(K)
-12
-139
-14.9
3. The equation of the plot in terms of entropy, en-
thalpy and Ksp is
InKsp=-AH/RT + AS/R, you will be using
this to calculate the unknowns below
4. The slope of the plot will tell you about the
enthalpy (AH) of the dissolution of KHT
AH = (-0.22) x (8.314)
= 1.829 J/mol
= 1.829 J/mol
-13.99=-(1829/8.314). 1/294.85+ AS/4-3M
-0.00064739
-13.99-03+A5/8.314
+6.47407-64/8.314
45=-13.948.314
-13.99435x
2-114.3
5. The y-intercept value will tell you about the en-
tropy of the reaction
Write
a. Using the slope, plug one point into the
equation and calculate the intercept
your line equation here and show your calcu-
lations: (InKsp = -AH/RT + AS/R)
End of document
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