Please use the values in the resources listed below instead of the textbook values.Calculate the values of E°, A„G°, and K for the following reactions at 25.00°C. (Assume R = 8.3144621 J/mol·K. For each K, enter an unrounded value. Due to the nature of this problem, do not use rouintermediate values in your calculations-including answers submitted in WebAssign.)(a)Cu2+ + Pb - Cu + Pb2+E° =4.0 .467VA,G°4.0 -90.1kJ•mol-1K =7.901e15(b)Br2 + 2 I- → 2 Br¯ + I2E° =4.0 .550VA,G°4.0-106kJ•mol-1K = 4.01e18(c)5 Cu+ + 8 H+ + MnO4¯5 Cu2+ + 4 H20 + Mn2+E° = 4.0 1.36VA,G°4.0 -656kJ•mol-1K =1.011e115 Standard State Thermodynamic DataAH º (kJ/mol)s° J/mol·K)AG° (kJ/mol)AHº (kJ/mol)s° U/mol·K)AG ° (kJ/mol)formulaformulaCrCl3(s)-556.5-593.2HC2H;02(1)HCl(g)123.0-484.2159.8-389.9Cr,03(s)-1139.781.2-1058.1-92.3186.5-95.3Cs(g)175.6HF(g)HI(g)HNO3(g)HNO3(1)H2(g)H20(g)H20(1)H202(g)76.524.1-273.3173.5-275.4Cs(s)85.2-25.426.48206.31.7-405.8CsBr(s)CsCl(s)CsF(s)CsI(s)Cs,0(s)Cu(g)Cu(s)CuBr(s)113.1-439.5-133.9266.9-213.5-443.0101.2-473.2-174.1155.6-80.7-553.392.8-581.0130.6-346.6123.1-383.3-241.8188.7-228.6-345.8146.9-389.6-285.869.9-237.2337.4166.4287.8-136.3232.7-205.733.15H2O2(1)-187.8109.6-120.4H,S(g)H,SO,(1)H,Se(g)H3PO3(s)H3PO4(1)He(g)Hg(g)Hg(1)-104.696.1-133.3-20.63205.8-33.56CuCI(s)CuCl2(s)CuO(s)CuS(s)Cu,0(s)-137.286.2-162.9-814.0156.9-690.0-220.1108.1-252.329.7219.0-35.6-157.342.63-129.7-964.4-53.166.53-53.6-1271.7150.8-1316.7-168.693.14-146.0126.1F(g)79.4158.862.360.78175.031.8F2(g)202.875.9Fe(g)416.3362.5HgBr2(s)HgCl>(s)HgO(s)Hg,(g)180.5-170.7172.0-222.0Fe(s)27.2-224.3146.0-267.8FeBr,(s)FeCl2(s)FeCl3(s)-249.8140.6-291.7-90.870.29-58.5-341.8118.0-377.0108.8288.122.9142.3-441.9Hg,Br2(s)Hg,Cl2(s)I(g)-399.5-206.9218.0-271.9FeO(s)-272.060.75-251.4-265.4191.6-322.5106.8FeS(s)FeS2(s)Fe,03(s)Fe;04(s)-100.060.3-118.0180.852.9-178.252.9-194.062.4260.719.3-824.290.0-742.22(s)116.13-1118.4146.4-1162.0K(g)89.2160.260.7H(g)218.2114.7203.364.18K(s)KBr(s)KBrO3(s)HBr(g)-36.4198.7-53.4-393.895.9-422.4HCN(g)135.1201.8124.7-360.2149.2-404.7HC,H;O2(g)-432.2283.5-516.7KCI(s)-436.882.6-409.1

Answered: Image /qna-images/answer/98f3586e-9646-4234-86b7-87663acf908d.jpg

ase use the values in the resources listed below instead of the textbook values. culate the values of E°, A-G°, and K for the following reactions at 25.00°C. (Assume R = 8.3144621 J/mol-K. For each K, enter an unrounded value. Due to the nature of this problem, do not use rou ermediate values in your calculations-including answers submitted in WebAssign.) Cu2+ + Pb - Cu + Pb2+ 40 467 (a) A,G° = 0 -90.1 kJ-mol-1 K = 7.901e15 (b) Brz + 21- - 2 Br + I2 4.0 550 A,G° 4.0 v kJ-mol-1 -106 K = 4.01e18 (c) 5 Cu+ + 8 H+ + Mn04- - 5 Cu2+ + 4 H20 + Mn2+ 1.36 A,G° = 40 -656 x kJ-mol-1 K = 1.011e115

ase use the values in the resources listed below instead of the textbook values. culate the values of E°, A-G°, and K for the following reactions at 25.00°C. (Assume R = 8.3144621 J/mol-K. For each K, enter an unrounded value. Due to the nature of this problem, do not use rou ermediate values in your calculations-including answers submitted in WebAssign.) Cu2+ + Pb - Cu + Pb2+ 40 467 (a) A,G° = 0 -90.1 kJ-mol-1 K = 7.901e15 (b) Brz + 21- - 2 Br + I2 4.0 550 A,G° 4.0 v kJ-mol-1 -106 K = 4.01e18 (c) 5 Cu+ + 8 H+ + Mn04- - 5 Cu2+ + 4 H20 + Mn2+ 1.36 A,G° = 40 -656 x kJ-mol-1 K = 1.011e115

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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