Concept explainers
Interpretation: The most likely hydride shift that will occur for each of the below carbocations should be depicted with curved arrow and reason behind lowered potential energy for thus newly formed carbocation should be explained.
Concept introduction: Carbocation is a general term employed for a postively charged carbon irrespective of valency of carbon. In carbocation, carbon is bonded to 3 atoms or groups and has only sextet of electrons so it behaves as an electron-deficient species. It is
The order of relative stability of various possible carbocation species is as follows:
Whenever possibility to attain lower energy by rearrangement is there then hydride or alkyl shift may occur and results in more stable carbocation. This type of rearrangement is highly favorable in polar solvents.
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Organic Chemistry: A Guided Inquiry
- CO2 Follow the curved arrows and draw the product of this reaction. You do not have to consider stereochemistry.arrow_forwardDraw an arrow on the carbocation in the box on the left to show how it rearranges to the carbocation in the box on the right.arrow_forwardAny help is greatly appreciated!arrow_forward
- Cl₂ H₂O Draw the curved arrow step in this column... example: 1 H H OH CH3 CH3 + enantiomer CI: this mechanism requires. three mechanistic steps And complete sentence in this column In this mechanistic step, the nucleophilic alkene is attacking the chlorine which can be slightly electrophilic due to Cl₂'s polarizability, however, the extra lone pair on chlorine can attack one of the sp2 C resulting in the cationic complexarrow_forwardPlease help me with the organic chemistry problem below: Consider the reaction below: (Check the attached image) (it is between Furan and maleic anhydride, a DIels-Alder reaction) a) Will this reaction for an endo product (with a melting point of 80-81 degrees) or the exo product (with a melitng point of 114 degrees)? b) Carefully explain why the product must have been formed the way it did (exo or endo). c) Provide a mechanism for this reaction.arrow_forwardMy question is about part C of the question shown. The answer is shown and then I drew an alternative with a red arrow. The question asks to draw a halogen that will ONLY form the alkene shown, not most of the time or sometimes, as many of our questions ask us to draw all the possible alkenese, even unlikely ones. This one has to be ONLY that one. My question is why the structure on the far right does NOT lead to a double bond between the two rings. There is a hydrogen on the opposite side of the Cl, isn't there? If there's not a hydrogen there, why not? What am I not seeing? Or if there is a hydrogen but that bond can't be made, why not?arrow_forward
- In (e), please note that the heterocyclic oxygen atoms contains two lone pairs that could contribute to the resonance stabilization of any proposed intermediate.arrow_forwardAns?arrow_forwardDraw a resonance structure, complete with all formal charges and lone (unshared) electron pairs, that shows the resonance interaction of the nitro with the para position in nitrobenzene.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning