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Concept explainers
(a)
Interpretation:The curved arrows for acid-base reaction below should be added.
Concept introduction:According to Bronsted-Lowry concept, substance that donates proton is termed as acid while that accepts or gains protons is called base. Species formed after loss of protons from acids are known as their respective conjugate bases whereas conjugate acid is produced by addition of protons to base.
(b)
Interpretation: The alcohol that is stronger acid from below alcoholson the basis of
Concept introduction:The dissociation constant of acid represents strength of acid in solution. It is denoted by
(c)
Interpretation: The conjugate base that has lower potential energy in below reactionshould be determined.
Concept introduction:When one single structure is unable to describe all the properties of single molecule, a phenomenon called resonance comes into play. This arises when two or more than two Lewis structures are possible for one molecule. All such structures are called resonating structures and have same placement of atoms in them but these have different locations of bond pairs and lone pairs. The resonating structures are inter-convertible with each other. The resultant of all the resonating or contributing structures is called the resonance hybrid.
(d)
Interpretation: The relation between below exampleand story should be explained.
Concept introduction:When one single structure is unable to describe all the properties of single molecule, a phenomenon called resonance comes into play. This arises when two or more than two Lewis structures are possible for one molecule. All such structures are called resonating structures and have same placement of atoms in them but these have different locations of bond pairs and lone pairs. The resonating structures are inter-convertible with each other. The resultant of all the resonating or contributing structures is called the resonance hybrid.
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Chapter 5 Solutions
Organic Chemistry: A Guided Inquiry
- For each molecule below, draw the conjugate acid or conjugate base or both if the molecule hasboth a conjugate acid and a conjugate base (e.g., water).arrow_forwardDraw the structure of the conjugate base of water. (Note that it does not appear in Figure 4.11).arrow_forwardPhenol (shown below) has a pKa10 . a. Based on pKa data, is phenol a stronger or weaker acid than an ordinaryalcohol (e.g.. CH3OH ) or water? b. Draw the conjugate base of phenol (called phenoxide) including allimportant resonance structures. c. Construct an explanation for why phenol is a stronger acid than anordinary alcohol. (You may want to consider first why phenoxide is lowerin PE than methoxide (RO) or hydroxide (HO) .arrow_forward
- Complete the equation for the reaction between each Lewis acid-base pair. In each equation, label which starting material is the Lewis acid and which is the Lewis base; use curved arrows to show the flow of electrons in each reaction. In doing this problem, it is essential that you show valence electrons for all atoms participating in each reaction. (a) (b) (c) (d)arrow_forwardDraw the mechanism showing the Brønsted acid/base reaction between propanoic acid and methylamine. Label the acid, base, conjugate base, and conjugate acid. Show all curved arrows, lone pairs and nonzero formal charges. HO. CH;NH2 methylamine propanoic acid pKa = 4.9 Mechanism: uerm lo noits adi ol maie Using the pKa information provided/pKa tables (table appended to the end of this document), determine whether the starting reagents (propanoic acid and methyl amine) or products would be favored at equilibrium (no math needed!).arrow_forwardSolve all parts otherwise I will downvotearrow_forward
- Please help me with these. The blank at the bottom could possibly be no reaction.arrow_forwardFor the reaction given below, draw a mechanism (curved arrows) and then predict which side of the reaction is favoured under equilibrium conditions. Include lone pairs and formal charges. Predict which side of the reaction is favored under equilibrium conditions, and explain your choice. a. the reactants are favored, because the negative charge on the electronegative oxygen atom is more stable (making it the stronger base). b. the products are favored, because the negative charge on the electronegative oxygen atom is more stable (making it the weaker base). c. the products are favored, because the negative charge on the large sulfur atom is more stable (making it the weaker base). d. the reactants are favored, because the negative charge on the large sulfur atom is more stable (making it the stronger base).arrow_forward5.) curved arrows to demonstrate the flow of electrons pairs in each potential reaction. b.) Indicate if the reaction lie to the right or the left (circle the correct arrow direction). c.) Calculate an approximate Keq for each reaction. d.) Writ the pka values under each acid, so we can evaluate your progress better and award partial credit. d.) Finally, label th acid (A), base (B), conjugate acid (CA) and base (CB) correctly based on the direction you decided. For each reaction, perform the following tasks: a.) Complete the following reactions using the appropriat Keg %3D Direction: OH LiO он Keq %3D Direction: CH3LI HOT Но Keg = Direction: O:arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
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