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Concept explainers
Interpretation: The reason that explains bicarbonate is not a strong base should be determined.
Concept introduction: Lewis structure is a representation of molecules in which dots are shown to represent unshared electrons and lines are shown to represent bonds. These lines and dots represent distribution of electrons in the molecule.
When one single structure is unable to describe all the properties of a single-molecule, a phenomenon called resonance comes into play. This arises when two or more than two Lewis structures are possible for one molecule. All such structures are called resonating structures and have same placement of atoms in them but these have different locations of bond pairs and lone pairs. The resonating structures are inter-convertible with each other. The resultant of all the resonating or contributing structures is called the resonance hybrid.
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Chapter 5 Solutions
Organic Chemistry: A Guided Inquiry
- Select the single best answer. For the following molecule, indicate the positive and negative ends of the dipole, using the symbol →→→→. Refer to a table of the Pauling electronegativity scale as needed. HF The arrow points to the left. The arrow points to the right.arrow_forwardDraw a complete lewis structure for the CONJUGATE ACID of Nitromethane (condensed formula CH3NOOH). Draw a complete lewis structure that shows all bonds, unshared electron pairs, and minimized formal charges where appropriate.arrow_forwardThe structure of Vitamin C (ascorbic acid) is shown below. As the name indicates, the molecule is somewhat acidic. Actually, one of the hydrogens on the four OH groups is much more acidic than the other three ones. Which one is the acidic hydrogen? Hints: To find the answer, you will again have to draw some resonance structures of the product formed after loss of H+. Consider the product after the loss of H+ for each of the OH groups. Only two of the OH groups have resonance structures after deprotonation; one of these two groups has a much better resonance structure than the other one (again after deprotonation). Note that the oxygen atom that is part of the five-membered ring has nothing to do with the problem.arrow_forward
- Write an equation for the reaction of CH3 SCH3 with BF3, a Lewis acid, and show by the use of curved arrows how the reaction occurs. • Show all hydrogen atoms that are not attached to a carbon atom. Apply formal charges where appropriate. Assign lone pairs and radical electrons where appropriate. • Use the "starting points" menu to revert to the original molecule(s) shown. • Draw the appropriate electron-flow arrows. • Omit+ signs between structures. ● ● CH3 | :S: | CH3 == starting points == ↑ TAYY : F کر ? ChemDoodleⓇarrow_forwardOne way of naming alcohols is to name the alkyl group that is attached to the −OH and add the word alcohol. Write bond-line formulas for (a.) propyl alcohol and (b.) isopropyl alcohol.arrow_forwardDraw the Lewis structure of the missing reactant. Make sure to include lone pairs and non-zero formal charges. HCl + CI + CH;CH,OH Click and drag to start drawing a structure. toarrow_forward
- Draw the Lewis structure of the missing reactant. Make sure to include lone pairs and non-zero formal charges. NH, + NH + CH,OCH, Click and drag to start drawing a structure.arrow_forwardDraw the conjugate base of C5F5H. Include lone pairs of electrons on all atoms. Add non-zero formal charges where appropriate.arrow_forwardThis is a Brønsted-Lowry acid-base reaction. Draw structures for all the products, showing any non-zero formal charges in each one. Make sure your reaction is balanced.arrow_forward
- Draw the best Lewis structure for the linear C ion, including all lone pair electrons and non-zero formal charges.arrow_forwardChange ethane into 1,2-ethanediol (HOCH2CH2OH) by removing one hydrogen atom from each carbon atom and replacing with a hydroxide (-OH) group. Draw a Lewis structure for 1,2-ethanediol.arrow_forwardShow the delocalization of charges in the following structures. Draw the resonance forms and indicate the movement of electrons with curved arrows.Hint: First draw the Lewis structure for each the compound.(i) CH2=CH─O-(ii) CH2=CH─O+arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
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