no Ai walkthroughs +Add substituents to draw the conformer below (sighting downthe indicated bond), then rotate the back carbon to provide thestructure in the conformation that will be capable of an E2elimination. R/S stereochemistry is graded.BrOCH2CH3H3CHBrHIH3COCH2CH3DrawingQIAtoms, Bondsand RingsChargesH3CCH2CH3OCH2CHHCH3OCH3Br3HHUndoReset語RemoveDoneRotate

Answered: Image /qna-images/answer/2149380d-dadf-4939-bda7-22af4d1b5e52.jpg

Answered: + Add substituents to draw the…

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter6: Alkanes & Alkenes

Section: Chapter Questions

Problem 4E: Consider the molecule 1-bromo-2-methylbutane. C3 and C4 should be drawn as Et as in theexample. This...

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[References) Draw the line-angle formula for the most stable carbocation with a molecular formula of: C3H,+ • You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. • If there are alternative structures, draw the most stable one. P opy aste ChemDoodle
Consider the structural/conformational isomers of isopropyldimethylcyclohexane shown below. Match each isomer to the statement that best describes its properties. VHas the least steric repulsion / steric strain. EVHas the most torsional and steric strain overall Me iPr, VHas a syn-pentane interaction between two (or more) non-hydrogen substituents Me VIs the lowest energy boat conformation shown В. H. Ме iPr Me C. Me iPr `Me H D. iPr Me Me E. Me Me H- iPr
Starting from the wedge-and-dash structure below (sighting down the indicated bond), rotate the back carbon to provide the structure in the conformation that will be capable of an E2 elimination. R/S stereochemistry is graded. # O H3C H Drawing > CI ||||| H Atoms, Bonds and Rings Tap a node to see s
translate the bond-line notation structure to the Newman projection by filling int the missing groups (A, B, C, D or E) on the lines in the Newman projection so they match the conformation given in the original structure. Circle if the conformation is a staggered or eclipsed.
Which chair conformation of cis- and trans-1,4-dimethylcyclohexane has the lowest potenital energy? Which is the most stabel? Why?
Choose either I, II, III, or IV
Draw chemical structure with appropiate stereochemistry ( cis or trans, E or Z)Name the structures
[References] The two alkenes below react with HI at different rates. CH3 CH3CH=CHCH3 and CH;ċ=CHCH3 Draw the structural formula of the MAJOR product formed by the alkene having the HIGHER reaction rate. You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. In cases where there is more than one answer, just draw one. C P opy aste Previous Next ChemDoodle®
Build a model of methylcyclohexane, and use the model to complete the following Newmanprojections of methylcyclohexane in the chair conformation: a. When the methyl group is in an axial or equatorial (circle one) position, the molecule is inits lowest potential energy conformation. b. Label one Newman projection above anti and the other gauche to describe the relationshipbetween the methyl group and C3 of the ring. c. In general, which is a lower PE conformation, anti or gauche? d. Explain how your answer to b and c provide an explanation for why it is more favorable fora large group to be in an equatorial than an axial position.
A trisubstituted cyclohexane with three substituents-red, green, and blue-undergoes a ring-flip to its alternate chair conformation. Identify each substituent as axial or equatorial, and show the positions occupied by the three substituents in the ring-flipped form.
The diaxial conformation of cis-1, 3-dimethylcyclohexane is approximately 23 kJ/mol (5.4 kcal/mol) less stable than the diequatorial conformation. Draw the two possible chair conformations, and suggest a reason for the large energy difference.
The a-values for substituted cyclohexanes aren’t the only factor whendetermining stability and conformational energy. Draw both chair conformations in a newman projection to explain why the difference in energy in the two conformation of trans-1-bromo-2-cyclohexane is 1.12 kcal/mol and not 2.08 kcal/mol (as calculated by A-value). What can account for this difference?

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