a.
To find: the local extrema of the given function.
a.
![Check Mark](/static/check-mark.png)
Answer to Problem 15E
The
Explanation of Solution
Given:
Calculation:
Consider the given function,
Differentiating with respect to
Now to find the critical values, solve the first derivative by equating it to zero. That is,
Therefore
The graph of
Therefore
Now the local maximum value is,
b.
To find: the intervals in which the given function is increasing.
b.
![Check Mark](/static/check-mark.png)
Answer to Problem 15E
The given function increases in the interval
Explanation of Solution
Given:
Concept used:
The function increases in the interval at which the first derivative is positive.
Calculation:
Consider the given function,
Differentiating with respect to
Now the function increases in the interval for which,
Hence the given function increases in the interval
c.
To find: the intervals in which the given function is decreasing.
c.
![Check Mark](/static/check-mark.png)
Answer to Problem 15E
The given function decreases in the interval
Explanation of Solution
Given:
Concept used:
The function decreases in the interval at which the first derivative is negative.
Calculation:
Consider the given function,
Differentiating with respect to
Now the function decreases in the interval for which,
Hence the given function decreases in the interval
Chapter 4 Solutions
Advanced Placement Calculus Graphical Numerical Algebraic Sixth Edition High School Binding Copyright 2020
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