(a)
To find: The values of
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem 12E
Explanation of Solution
Given information: The volume of the open tank is
Concept used: The minimum value of the function
Calculation:
Consider the dimensions of the square base as
From the given information, the volume (V) of the open tank will be as shown below.
Substitute 500 for
The total cost of the tank is given by the function,
So,
Differentiate the obtained function with respect to
Equate the obtained derivative to 0 and solve for
Now, differentiate the equation,
Now, substitute 15 for
Since at
Substitute
Therefore, for the given open tank,
(b)
To describe: The possible scenario for the given cost function.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 12E
Cost of the material for the open tank is
Excavation charge is
Explanation of Solution
Given information: The volume of the open tank is
The cost of the material for the open tank is calculated on the basis of the surface area of the tank, that is,
It is given that the excavation charge is the product of
Chapter 4 Solutions
Advanced Placement Calculus Graphical Numerical Algebraic Sixth Edition High School Binding Copyright 2020
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