a.
To find: the local extrema of the given function.
a.
Answer to Problem 19E
The given function has no local extrema.
Explanation of Solution
Given:
Calculation:
Consider the given function,
Differentiating with respect to
Here, the derivative cannot be zero for any real value of
So there are no critical values for the given function.
Hence the given function has no local extrema.
b.
To find: the intervals in which the given function is increasing.
b.
Answer to Problem 19E
The given function increases in the interval
Explanation of Solution
Given:
Concept used:
The function increases in the interval at which the first derivative is positive.
Calculation:
Consider the given function,
Differentiating with respect to
Now the function increases in the interval for which,
It is true for all the real values of
Hence the given function increases in the interval
c.
To find: the intervals in which the given function is decreasing.
c.
Answer to Problem 19E
There is no interval in which the given function is decreasing.
Explanation of Solution
Given:
Concept used:
The function decreases in the interval at which the first derivative is negative.
Calculation:
Consider the given function,
Differentiating with respect to
Now the function decreases in the interval for which,
It is not possible for any real values of
Hence there is no interval in which the given function is decreasing.
Chapter 4 Solutions
Advanced Placement Calculus Graphical Numerical Algebraic Sixth Edition High School Binding Copyright 2020
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