Mechanics of Materials (10th Edition)
10th Edition
ISBN: 9780134319650
Author: Russell C. Hibbeler
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Textbook Question
Chapter 3, Problem 3.7RP
The stress-strain diagram for polyethylene, which is used to sheath coaxial cables, is determined from testing a specimen that has a gage length of 10 in. If a load P on the specimen develops a strain of ε = 0.024 in./in., determine the approximate length of the specimen, measured between the gage points, when the load is removed. Assume the specimen recovers elastically.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
The stress–strain diagram for polyethylene, which is used to sheath coaxial cables, is determined from testing a specimen that has a gage length of 10 in. If a load P on the specimen develops a strain of P = 0.024 in.>in., determinethe approximate length of the specimen, measured between the gage points, when the load is removed. Assume the specimen recovers elastically
Determine the elastic tensile load "F" that acts
on mild steel specimen of Diameter 9 mm &
Modulus of Elasticity 201 GPa. It is found that
the specimen has undergone an extension of 1
mm due to the elastic load "F". Also, determine
the length "L" of the specimen, if the strain-
induced due to the load "F" on the specimen is
3.6 x 10-³.
Solution
Cross-sectional Area, A (in mm²) =
63.617
One possible correct answer is: 63.617251235193
Tensile Stress, (in N/mm²)
723.6
One possible correct answer is: 723.6
Tensile Load, (in N) =
=
46033.261
One possible correct answer is: 46033.442993786
Length of the Specimen (in mm)
4.366
X
One possible correct answer is: 277.77777777778
Determine the elastic tensile load "F" that acts on mild steel specimen of Diameter 5 mm & Modulus of Elasticity 207 GPa. It is found that the specimen has undergone an extension of
1.2 mm due to the elastic load "F". Also, determine the length "L" of the specimen, if the strain-induced due to the load "F" on the specimen is 3 x 10-³.
Solution
Cross-sectional Area, A (in mm²) =
Tensile Stress, (in N/mm²) =
Tensile Load, (in N) =
Length of the Specimen (in mm)
Chapter 3 Solutions
Mechanics of Materials (10th Edition)
Ch. 3.4 - Define a homogeneous material.Ch. 3.4 - Indicate the points on the stress-strain diagram...Ch. 3.4 - Define the modulus of elasticity E.Ch. 3.4 - At room temperature, mild steel is a ductile...Ch. 3.4 - Engineering stress and strain are calculated using...Ch. 3.4 - As the temperature increases the modulus of...Ch. 3.4 - A 100-mm-long rod has a diameter of 15 mm. If an...Ch. 3.4 - A bar has a length of 8 in. and cross-sectional...Ch. 3.4 - A 10-mm-diameter rod has a modulus of elasticity...Ch. 3.4 - The material for the 50-mm-long specimen has the...
Ch. 3.4 - The material for the 50-mm-long specimen has the...Ch. 3.4 - If the elongation of wire BC is 0.2 mm after the...Ch. 3.4 - A tension test was performed on a steel specimen...Ch. 3.4 - Data taken from a stress-strain test for a ceramic...Ch. 3.4 - Data taken from a stress-strain test for a ceramic...Ch. 3.4 - The stress-strain diagram for a steel alloy having...Ch. 3.4 - The stress-strain diagram for a steel alloy having...Ch. 3.4 - The stress-strain diagram for a steel alloy having...Ch. 3.4 - The rigid beam is supported by a pin at C and an...Ch. 3.4 - The rigid beam is supported by a pin at C and an...Ch. 3.4 - Acetal plastic has a stress-strain diagram as...Ch. 3.4 - The stress-strain diagram for an aluminum alloy...Ch. 3.4 - The stress-strain diagram for an aluminum alloy...Ch. 3.4 - The stress-strain diagram for an aluminum alloy...Ch. 3.4 - A bar having a length of 5 in. and cross-sectional...Ch. 3.4 - The rigid pipe is supported by a pin at A and an...Ch. 3.4 - The rigid pipe is supported by a pin at A and an...Ch. 3.4 - Direct tension indicators are sometimes used...Ch. 3.4 - The rigid beam is supported by a pin at C and an...Ch. 3.4 - The rigid beam is supported by a pin at C and an...Ch. 3.4 - The stress-strain diagram for a bone is shown, and...Ch. 3.4 - The stress-strain diagram for a bone is shown and...Ch. 3.4 - The two bars are made of a material that has the...Ch. 3.4 - The two bars are made of a material that has the...Ch. 3.4 - The pole is supported by a pin at C and an A-36...Ch. 3.4 - The bar DA is rigid and is originally held in the...Ch. 3.7 - A 100-mm-long rod has a diameter of 15 mm. If an...Ch. 3.7 - A solid circular rod that is 600 mm long and 20 mm...Ch. 3.7 - A 20-mm-wide block is firmly bonded to rigid...Ch. 3.7 - A 20-mm-wide block is bonded to rigid plates at...Ch. 3.7 - The acrylic plastic rod is 200 mm long and 15 mm...Ch. 3.7 - The plug has a diameter of 30 mm and fits within a...Ch. 3.7 - The elastic portion of the stress-strain diagram...Ch. 3.7 - The elastic portion of the stress-strain diagram...Ch. 3.7 - The brake pads for a bicycle tire are made of...Ch. 3.7 - The lap joint is connected together using a 1.25...Ch. 3.7 - The lap joint is connected together using a 1.25...Ch. 3.7 - The rubber block is subjected to an elongation of...Ch. 3.7 - The shear stress-strain diagram for an alloy is...Ch. 3.7 - A shear spring is made from two blocks of rubber,...Ch. 3 - The elastic portion of the tension stress-strain...Ch. 3 - The elastic portion of the tension stress-strain...Ch. 3 - The rigid beam rests in the horizontal position on...Ch. 3 - The wires each have a diameter of 12 in., length...Ch. 3 - The wires each have a diameter of 12 in., length...Ch. 3 - diameter steel bolts. If the clamping force in...Ch. 3 - The stress-strain diagram for polyethylene, which...Ch. 3 - The pipe with two rigid caps attached to its ends...Ch. 3 - The 8-mm-diameter bolt is made of an aluminum...Ch. 3 - An acetal polymer block is fixed to the rigid...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E wherey= 2.2 lb/in.³ is the specific weight of the material, y = 5.0 in. is the distance from the free (i.e., bottom) end of the bar, L = 25 in. is the length of the bar, and E = 23000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length of the bar (c) the maximum normal strain in the bar. Answer: (a) ō = i (b) Eave = i (c) Emax = i x10-in. με μεarrow_forwardThe normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression vy/3E where y = 2.3 lb/in.³ is the specific weight of the material, y = 0.8 in. is the distance from the free (i.e., bottom) end of the bar, L = 8 in. is the length of the bar, and E = 23000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar.arrow_forwardThe normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression vy/3E where y = 2.4 lb/in.³ is the specific weight of the material, y = 3.8 in. is the distance from the free (i.e., bottom) end of the bar, L = 19 in. is the length of the bar, and E= 24000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar. Part 1 Calculate the change in length of the bar due to its own weight. Answer: d = i x10-6 in.arrow_forward
- The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.9 lb/in.³ is the specific weight of the material, y = 0.5 in. is the distance from the free (i.e., bottom) end of the bar, L = 5 in. is the length of the bar, and E = 25000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar. Part 1 * Your answer is incorrect. Calculate the change in length of the bar due to its own weight. Answer: d= i 2.416 eTextbook and Media x10-6 in.arrow_forwardThe normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.8 lb/in.3 is the specific weight of the material, y = 2.0 in. is the distance from the free (i.e., bottom) end of the bar, L = 20 in. is the length of the bar, and E= 29000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar. Part 1 Your answer is correct. Calculate the change in length of the bar due to its own weight. Answer: 6 = 6.436 eTextbook and Media Part 2 * Your answer is incorrect. Calculate the average normal strain over the length of the bar. Answer: Eavi 3.22 x10-6 in. eTextbook and Media Save for Later με Attempts: 1 of 5 used Attempts: 2 of 5 used Part 3 The parts of this question must be completed in order. This part will be available when you complete the part above. Submit Answerarrow_forwardThe normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.8 lb/in.³ is the specific weight of the material, y = 2.0 in. is the distance from the free (i.e., bottom) end of the bar, L = 20 in. is the length of the bar, and E = 29000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar. Part 1 Calculate the change in length of the bar due to its own weight. Answer: ō= i eTextbook and Media Save for Later x10-6 in. Attempts: 0 of 5 used Submit Answer Part 2 The parts of this question must be completed in order. This part will be available when you complete the part above. Part 3 The parts of this question must be completed in order. This part will be available when you complete the part above.arrow_forward
- The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.1 lb/in.³ is the specific weight of the material, y = 2.0 in. is the distance from the free (i.e., bottom) end of the bar, L = 5 in. is the length of the bar, and E = 27000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar (c) the maximum normal strain in the bar. Answer: (a) 8 = i (b) avg (c) Emax = i x10 in. με μεarrow_forwardThe normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.4 lb/in.³ is the specific weight of the material, y = 1.8 in. is the distance from the free (i.e., bottom) end of the bar, L = 9 in. is the length of the bar, and E= 26000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar. Calculate the change in length of the bar due to its own weight. Answer: x10-6 in.arrow_forwardThe normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y=2.4 lb/in.³ is the specific weight of the material, y = 0.6 in. is the distance from the free (i.e., bottom) end of the bar, L = 6 in. is the length of the bar, and E=30000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar (c) the maximum normal strain in the bar. Answer: (a) 5 = 1 (b) Sa (c) Emax= i x10-6 in. με μεarrow_forward
- The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.3 lb/in.³ is the specific weight of the material, y = 2.4 in. is the distance from the free (i.e., bottom) end of the bar, L = 6 in. is the length of the bar, and E= 24000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar (c) the maximum normal strain in the bar. Answer: (a) d = i (b) avg (c) Emax || MI Mi x10-6 in. με μεarrow_forwardThe stress-strain diagram for polyethylene, which is used to sheath coaxial cables, is determined from testing a specimen that has a gage length of 11 in. A load P on the specimen develops a strain of € = 0.024 in. /in. (Figure 1) Figure σ (ksi) 5 4 3 2 1 O = 3,7 e O 0.008 0.016 0.024 0.032 0.040 0.048 0.004 1 of 1 P € (in./in.) Part A Determine the approximate length of the specimen, measured between the gage points, when the load is removed. Assume the specimen recovers elastically. Express your answer in inches to four significant figures. 15] ΑΣΦ | 11 | vec L = Submit Provide Feedback Request Answer www ? Review in. Next >arrow_forwardPlease answer only Handwritten.thank youarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
An Introduction to Stress and Strain; Author: The Efficient Engineer;https://www.youtube.com/watch?v=aQf6Q8t1FQE;License: Standard YouTube License, CC-BY