Interpretation:
The hydrogen bonding exists in structure and the sequence of each strand of DNA has to be predicted.
Concept Introduction:
Composition of
Base pairing in DNA: The two strands of the DNA double helix run in the opposite directions- one in 5’ to 3’ direction and other from 3’ to 5’ direction. The hydrogen bonding between two strands enhances the stability of the DNA; where the alignment of hydrophobic nitrogenous bases in the interior and hydrophilic phosphate and sugar groups on the exterior also enhance the stability. Adenine and thymine gives a pair forming two hydrogen bonds and cytosine and guanine gives rise to another pair forming three hydrogen bonds.
Sugar: In both DNA and RNA, sugar portion is found. In DNA, the sugar is D-ribose, where at 2’hydroxyl group is absent and in RNA, the hydroxyl group is present at 2’.
Nucleotide: (Nucleoside + phosphate)
Nucleotides are the building blocks of nuclei acids; monomers of DNA and RNA
Nitrogenous bases: Five types of nitrogenous bases (has unique one-letter code A, G, T, U, and C) are derived from two parent compounds called purine and pyrimidine. The purine derivatives are Adenine and Guanine are two fused nitrogen containing rings. The pyrimidine derivatives are Thymine, Cytosine, and Uracil has a six-membered nitrogen ring. Adenine, Guanine, Thymine, and Cytosine are the nitrogenous bases present in DNA. Adenine, Guanine, Cytosine and Uracil are the nitrogenous bases present in RNA.
Numbering the atoms in sugar and base rings:
In order to distinguish the atoms in the sugar of a nucleoside and atoms of a base ring, numbers without prime is used for atoms in the base ring and numbers with prime used for the atoms in the sugar ring.
Want to see the full answer?
Check out a sample textbook solutionChapter 26 Solutions
FUND.OF GEN CHEM CHAP 1-13 W/ACCESS
- Draw the predominant form of glutamic acid at pH = 8.4. The pKa of the side chain is 4.1. Include proper stereochemistry. HO H2N OH pH = 8.4arrow_forwardHow would I draw this?arrow_forwardCalculate the standard change in Gibbs free energy, AGrxn, for the given reaction at 25.0 °C. Consult the table of thermodynamic properties for standard Gibbs free energy of formation values. NH,Cl(s) →NH; (aq) + C1 (aq) AGrxn -7.67 Correct Answer Determine the concentration of NH+ (aq) if the change in Gibbs free energy, AGrxn, for the reaction is -9.27 kJ/mol. 6.49 [NH+] Incorrect Answer kJ/mol Marrow_forward
- What are some topics of interest that neurotoxicologists study? For example, toxin-induced seizures, brain death, and such along those lines?arrow_forwardCould you help me with the explanation of the answer to exercise 15, chapter 1 of Lehinger Question Nombramiento de estereoisómeros con dos carbonos quirales utilizando el sistema RS(R,R)El isómero del metilfenidato (Ritalin) se utiliza para tratar el trastorno por déficit de atención con hiperactividad (TDAH).(S,S)El isómero es un antidepresivo. Identifique los dos carbonos quirales en la siguiente estructura. ¿Es este el(R,R)o el(S,S)¿isómero? Dibuja el otro isómero. Nombramiento de estereoisómeros con dos carbonos quirales utilizando el sistema RS(R,R)El isómero del metilfenidato (Ritalin) se utiliza para tratar el trastorno por déficit de atención con hiperactividad (TDAH).(S,S)El isómero es un antidepresivo.arrow_forwardThe reaction A+B → C + D AG°' = -7.3 kcal/mol can be coupled with which of the following unfavorable reactions to drive it forward? A. EFG+HAG° = 5.6 kcal/mol. B. J+KZ+A AG° = 2.3 kcal/mol. C. P+RY+DAG° = 8.2 kcal/mol. D. C + T → V + W AG°' = -5.9 kcal/mol. E. AN→ Q+KAG°' = 4.3 kcal/mol.arrow_forward
- What would be the toxicological endpoints for neurotoxicity?arrow_forwardWhat are "endpoints" in toxicology exactly? Please give an intuitive easy explanationarrow_forwardFura-2 Fluorescence (Arbitrary Unit) 4500 4000 3500 3000 2500 2000 1500 1000 500 [Ca2+]=2970nM, 25°C [Ca2+] 2970nM, 4°C [Ca2+]=0.9nM, 25°C [Ca2+] = 0.9nM, 4°C 0 260 280 300 340 360 380 400 420 440 Wavelength (nm) ← < The figure on the LHS shows the excitation spectra of Fura-2 (Em = 510 nm) in 2 solutions with two different Ca2+ ion concentration as indicated. Except for temperature, the setting for excitation & signal acquisition was identical.< ப a) The unit in Y-axis is arbitrary (unspecified). Why? < < b) Compare & contrast the excitation wavelength of the Isosbestic Point of Fura-2 at 25 °C & 4 °C. Give a possible reason for the discrepancy. < c) The fluorescence intensity at 25 °C & 4 °C are different. Explain why with the concept of electronic configuration. <arrow_forward
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage LearningBiology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage Learning
- Biology Today and Tomorrow without Physiology (Mi...BiologyISBN:9781305117396Author:Cecie Starr, Christine Evers, Lisa StarrPublisher:Cengage LearningBiology: The Unity and Diversity of Life (MindTap...BiologyISBN:9781337408332Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa StarrPublisher:Cengage LearningHuman Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage Learning