Concept explainers
(a)
Interpretation:
The citric acid cycle diacid intermediate counterpart for lipogenesis C4-ACP monoacid intermediate butyrate has to be determined.
Concept introduction:
Lipogenesis is the process employed for the synthesis of fatty acid. The starting precursor for the synthesis is acetyl CoA. The enzyme employed for the process is fatty acid synthase. It is a multienzyme complex that ties the reaction responsible for the synthesis of fatty acid. This process is the reverse of the degradation of fatty acid.
The Citric acid cycle is a series of biochemical reactions that use acetyl CoA (produced by oxidation of pyruvate) to produce carbon dioxide, NADH and FADH2 in a series of
(a)
Answer to Problem 25.105EP
The citric acid cycle diacid intermediate counterpart for lipogenesis C4-ACP monoacid butyrate intermediate is succinate.
Explanation of Solution
Intermediates involved in the lipogenesis are derivative of C4 molecule butyric acid. Butyric acid is a monocarboxylic acid and has 4 carbon atoms. Thus, each intermediate of the lipogenesis is a C4 derivative of monocarboxylic acid. The structure of butyric acid is,
Succinic acid is a dicarboxylic acid and has 4 carbon atoms. Thus, each intermediate of the citric acid cycle is a
The structure of butyrate is,
The structure of succinate is,
Butyrate and succinate are saturated acids with four carbon atoms in each molecule. Butyrate is a monoacid that is formed as an intermediate in lipogenesis while succinate is a diacid that is formed as an intermediate in the citric acid cycle. Therefore, the citric acid cycle diacid intermediate counterpart for lipogenesis C4-ACP monoacid butyrate intermediate is succinate.
(b)
Interpretation:
The citric acid cycle diacid intermediate counterpart for lipogenesis C4-ACP monoacid intermediate acetoacetate has to be determined.
Concept introduction:
Lipogenesis is the process employed for the synthesis of fatty acid. The starting precursor for the synthesis is acetyl CoA. The enzyme employed for the process is fatty acid synthase. It is a multienzyme complex that ties the reaction responsible for the synthesis of fatty acid. This process is the reverse of the degradation of fatty acid.
The Citric acid cycle is a series of biochemical reactions that use acetyl CoA (produced by oxidation of pyruvate) to produce carbon dioxide, NADH and FADH2 in a series of redox reactions.
Intermediates involved in the lipogenesis are derivatives of C4 molecule butyric acid. Butyric acid is a monocarboxylic acid and has 4 carbon atoms. Thus, each intermediate of the lipogenesis is a C4 derivative of monocarboxylic acid. The structure of butyric acid is,
Succinic acid is a dicarboxylic acid and has 4 carbon atoms. Thus, each intermediate of the citric acid cycle is a C4 derivative of dicarboxylic acid. The structure of succinic acid is,
(b)
Answer to Problem 25.105EP
The citric acid cycle diacid intermediate counterpart for lipogenesis C4-ACP monoacid acetoacetate intermediate is oxaloacetate.
Explanation of Solution
Acetoacetate is the intermediate in the lipogenesis. The structure of acetoacetate is,
Oxaloacetate is the intermediate in the citric acid cycle. The structure of oxaloacetate is,
Acetoacetate and oxaloacetate are the keto derivatives of saturated acid with four carbon atoms in each molecule. Acetoacetate is a keto derivative of monocarboxylic acid while oxaloacetate is a keto derivative of dicarboxylic acid. Therefore, the citric acid cycle diacid intermediate counterpart for lipogenesis C4-ACP monoacid acetoacetate intermediate is oxaloacetate.
(c)
Interpretation:
The citric acid cycle diacid intermediate counterpart for lipogenesis C4-ACP monoacid intermediate β-hydroxybutyrate has to be determined.
Concept introduction:
Lipogenesis is the process employed for the synthesis of fatty acid. The starting precursor for the synthesis is acetyl CoA. The enzyme employed for the process is fatty acid synthase. It is a multienzyme complex that ties the reaction responsible for the synthesis of fatty acid. This process is the reverse of the degradation of fatty acid.
The Citric acid cycle is a series of biochemical reactions that use acetyl CoA (produced by oxidation of pyruvate) to produce carbon dioxide, NADH and FADH2 in a series of redox reactions.
Intermediates involved in the lipogenesis are derivatives of C4 molecule butyric acid. Butyric acid is a monocarboxylic acid and has 4 carbon atoms. Thus, each intermediate of the lipogenesis is a C4 derivative of monocarboxylic acid. The structure of butyric acid is,
Succinic acid is a dicarboxylic acid and has 4 carbon atoms. Thus, each intermediate of the citric acid cycle is a C4 derivative of dicarboxylic acid. The structure of succinic acid is,
(c)
Answer to Problem 25.105EP
The citric acid cycle diacid intermediate counterpart for lipogenesis C4-ACP monoacid β-hydroxybutyrate intermediate is malate.
Explanation of Solution
β-Hydroxybutyrate is the intermediate in the lipogenesis. The structure of β-hydroxybutyrate is,
Malate is the intermediate in the citric acid cycle. The structure of Malate is,
β-Hydroxybutyrate and malate are the hydroxy derivatives of saturated acid with four carbon atoms in each molecule. β-Hydroxybutyrate is a hydroxy derivative of monocarboxylic acid while malate is a hydroxy derivative of dicarboxylic acid. Therefore, the citric acid cycle diacid intermediate counterpart for lipogenesis C4-ACP monoacid β-hydroxybutyrate intermediate is malate.
(d)
Interpretation:
The citric acid cycle diacid intermediate counterpart for lipogenesis C4-ACP monoacid intermediate crotonate has to be determined.
Concept introduction:
Lipogenesis is the process employed for the synthesis of fatty acid. The starting precursor for the synthesis is acetyl CoA. The enzyme employed for the process is fatty acid synthase. It is a multienzyme complex that ties the reaction responsible for the synthesis of fatty acid. This process is the reverse of the degradation of fatty acid.
The Citric acid cycle is a series of biochemical reactions that use acetyl CoA (produced by oxidation of pyruvate) to produce carbon dioxide, NADH and FADH2 in a series of redox reactions.
Intermediates involved in the lipogenesis are derivatives of C4 molecule butyric acid. Butyric acid is a monocarboxylic acid and has 4 carbon atoms. Thus, each intermediate of the lipogenesis is a C4 derivative of monocarboxylic acid. The structure of butyric acid is,
Succinic acid is a dicarboxylic acid and has 4 carbon atoms. Thus, each intermediate of the citric acid cycle is a C4 derivative of dicarboxylic acid. The structure of succinic acid is,
(d)
Answer to Problem 25.105EP
The citric acid cycle diacid intermediate counterpart for lipogenesis C4-ACP monoacid crotonate intermediate is fumarate.
Explanation of Solution
Crotonate is the intermediate in the lipogenesis. The structure of crotonate is,
Fumarate is the intermediate in the citric acid cycle. The structure of fumarate is,
Crotonate and fumarate are the unsaturated derivatives of a
Want to see more full solutions like this?
Chapter 25 Solutions
Study Guide with Selected Solutions for Stoker's General, Organic, and Biological Chemistry, 7th
- Write the systematic (IUPAC) name for each of the following organic molecules: F structure Br LL Br Br الحمد name ☐ ☐arrow_forwardDraw an appropriate reactant on the left-hand side of this organic reaction. Also, if any additional major products will be formed, add them to the right-hand side of the reaction. + + Х ง C 1. MCPBA Click and drag to start drawing a structure. 2. NaOH, H₂O Explanation Check OI... OH ol OH 18 Ar © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibilityarrow_forwardCalculate the atomic packing factor of quartz, knowing that the number of Si atoms per cm3 is 2.66·1022 and that the atomic radii of silicon and oxygen are, respectively, 0.038 and 0.117 nm.arrow_forward
- 3. a. Use the periodic table to add up the molecular weight of thionyl chloride (SOCl2) and show your work. b. The actual value obtained for the molecular ion on a high resolution mass spectrometer is 117.9041. Explain the discrepancy. c. Show the calculations that correctly result in the exact mass of 117.9041 for SOC₁₂. Use Table 11.2 or Appendix E in your calculations.arrow_forward6. Draw the molecular orbital diagram shown to determine which of the following is paramagnetic. B₂2+ B22+, B2, C22, B22- and N22+ Molecular Orbital Diagram B2 C22- B22- N22+ Which molecule is paramagnetic?arrow_forwardDon't used hand raitingarrow_forward
- EXERCISES: Complete the following exercises. You must show all work to receive full credit. 1. How many molecular orbitals can be built from the valence shell orbitals in O2? 2. Give the ground state electron configuration (e.g., 02s² 0*2s² П 2p²) for these molecules and deduce its bond order. Ground State Configuration Bond Order H2+ 02 N2arrow_forward7. Draw the Lewis structures and molecular orbital diagrams for CO and NO. What are their bond orders? Are the molecular orbital diagrams similar to their Lewis structures? Explain. CO Lewis Structure NO Lewis Structure CO Bond Order NO Bond Order CO Molecular Orbital Diagram NO Molecular Orbital Diagramarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,