
(a)
Interpretation: The number of moles of HCl required to neutralize 0.03 mol of KOH needs to be determined.
Concept Introduction: A reaction between an acid and a base is known as a neutralization reaction. Here, the acid reacts with the base to form salt and water. The general neutralization reaction is represented as follows:
Here, HA is an acid, BOH is a base and BA is salt.
(a)

Explanation of Solution
The given solution is 0.03 mol KOH. To neutralize the given base, the number of moles of HCl required can be calculated by determining the number of moles of hydroxide ions present in the solution.
In 0.03 mol of KOH, the number of moles of hydroxide ions or
The number of moles of hydrogen ions required to neutralize the hydroxide ion will be 0.03 moles.
Similarly, HCl is a strong acid; thus, the number of moles of hydrogen ion will be equal to the number of moles of acid. Thus, the number of moles of HCl required will be 0.03 moles.
(b)
Interpretation: The number of moles of HCl required to neutralize 2 mol of
Concept Introduction: A reaction between an acid and a base is known as a neutralization reaction. Here, the acid reacts with the base to form salt and water. The general neutralization reaction is represented as follows:
Here, HA is an acid, BOH is a base and BA is salt.
(b)

Explanation of Solution
The given solution is 2 mol of
The ICE table can be represented as follows:
The expression for the base dissociation constant will be:
Substitute the values,
Or,
Considering 1 L solution thus, the value of C will be 2 M.
Or,
The value of
The value of x cannot be negative; thus,
The hydroxide ion concentration will be:
For 1 L solution, the number of moles of hydroxide ion will be 0.006 mol.
The number of hydrogen ions required to neutralize will be 0.006 mol. Again, HCl is a strong acid thus, the number of moles of hydrogen ion is equal to the number of moles of HCl which is 0.006 mol.
(c)
Interpretation: The number of moles of HCl required to neutralize 0.1 mol of
Concept Introduction: A reaction between an acid and a base is known as a neutralization reaction. Here, the acid reacts with the base to form salt and water. The general neutralization reaction is represented as follows:
Here, HA is an acid, BOH is a base and BA is salt.
(c)

Explanation of Solution
The given solution is 0.1 mol of
Here, calcium hydroxide is a strong base and completely dissociates into calcium and hydroxide ions. The reaction is represented as follows:
Thus, the number of moles of hydroxide ions in the solution will be:
Now, the concentration of hydrogen ions required to neutralize it will be 0.2 mol. Since HCl is a strong acid it gets completely dissociate into hydrogen ion and conjugate base. The number of moles of HCl required will be 0.2 mol.
Chapter 19 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- Predicting edict the major products of this organic reaction. If there aren't any products, because nothing will happen, check the box under the drawing area instead. + No reaction. Explanation Check HO Na O H xs H₂O 2 Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Iarrow_forwardChoosing reagents and conditions for acetal formation or hydrolysis 0/5 A student proposes the transformation below in one step of an organic synthesis. There may be one or more products missing from the right-hand side, but there are no reagents missing from the left-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing from the arrow. • Is the student's transformation possible? If not, check the box under the drawing area. If the student's transformation is possible, then complete the reaction by adding any missing products to the right-hand side, and adding required catalysts, inorganic reagents, or other important reaction conditions above and below the arrow. • You do not need to balance the reaction, but be sure every important organic reactant or product is shown. + This transformation can't be done in one step. 5 I H Autumn alo 值 Ar Barrow_forwardA block of copper of mass 2.00kg(cp = 0.3851 .K) and g temperature 0°C is introduced into an insulated container in which there is 1.00molH, O(g) at 100°C and 1.00 2 atm. Note that C P = 4.184. K for liquid water, and g that A H = 2260 for water. vap g Assuming all the steam is condensed to water, and that the pressure remains constant: (a) What will be the final temperature of the system? (b) What is the heat transferred from the water to the copper? (c) What is the entropy change of the water, the copper, and the total system?arrow_forward
- Identify the missing organic reactants in the following reaction: H+ X + Y OH H+ O O Note: This chemical equation only focuses on the important organic molecules in the reaction. Additional inorganic or small-molecule reactants or products (like H₂O) are not shown. In the drawing area below, draw the skeletal ("line") structures of the missing organic reactants X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Explanation Check Click and drag to start drawing a structure. X G 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Cente ? Earrow_forwardCalculate the solubility of CaF2 in g/L (Kp = 4.0 x 10-8). sparrow_forwardFor the following reaction with excess reagent, predict the product. Be sure your answer accounts for stereochemistry. If multiple stereocenters are formed, be sure to draw all products using appropriate wedges and dashes. 1. EtLi, Et₂O CH₁ ? 2. H₂O*arrow_forward
- Write the systematic name of each organic molecule: structure 요 OH ہو۔ HO OH name X S ☐ ☐arrow_forwardPredict the major products of this organic reaction. If there aren't any products, because nothing will happen, check the box under the drawing area instead. D ㄖˋ ید H No reaction. + 5 H₂O.* Click and drag to start drawing a structure. OH H₂Oarrow_forwardDraw one product of an elimination reaction between the molecules below. Note: There may be several correct answers. You only need to draw one of them. You do not need to draw any of the side products of the reaction 'O 10 + x 也 HO + 义 Click and drag to start drawing a structure.arrow_forward
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