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a.
Interpretation : The concentration of hydrogen ion and hydroxide ion in a neutral solution is to be compared and explained.
Concept Introduction : A hydrogen ion added to a water molecule transforms it into a hydronium ion. A hydroxide ion is created when a water molecule loses one of its hydrogen ions.
a.
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Answer to Problem 83A
The concentration of hydrogen ions and hydroxide ions in a neutral solution is the same.
Explanation of Solution
A pH of 7.0 indicates a neutral solution.
In a neutral solution, the concentration of hydrogen ion and hydroxide ion is equal.
The values of hydrogen ion and hydroxide ion in a neutral solution are
b.
Interpretation : The concentration of hydrogen ion and hydroxide ion in a basic solution is to be compared and explained.
Concept Introduction : A hydrogen ion added to a water molecule transforms it into a hydronium ion. A hydroxide ion is created when a water molecule loses one of its hydrogen ions.
b.
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Answer to Problem 83A
The concentration of hydroxide ions is greater than the concentration of hydrogen ions in a basic solution.
Explanation of Solution
pH greater than 7.0 designates a basic solution.
In a basic solution, the concentration of hydroxide ions is higher than the concentration of hydrogen ions.
The values of hydrogen ions in a basic solution are less than
c.
Interpretation : The concentration of hydrogen ion and hydroxide ion in an acidic solution is to be compared and explained.
Concept Introduction : A hydrogen ion added to a water molecule transforms it into a hydronium ion. A hydroxide ion is created when a water molecule loses one of its hydrogen ions.
c.
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Answer to Problem 83A
The concentration of hydrogen ions is greater than the concentration of hydroxide ions in an acidic solution.
Explanation of Solution
Acidic solutions have pH values below 7.0.
In an acidic solution, the concentration of hydrogen ions is higher than the concentration of hydroxide ions.
The values of concentration of hydrogen ion in an acidic solution are greater than
Chapter 19 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- Deducing the reactants of a Diels-Alder reaction vn the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ O If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Click and drag to start drawing a structure. Product can't be made in one step. Explanation Checkarrow_forwardPredict the major products of the following organic reaction: Δ ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. Larrow_forward> Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ • If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. If your answer is no, check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. Х © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accesarrow_forward
- Predict the major products of the following organic reaction: O O + A ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. eserved. Terms of Use | Privacy Center >arrow_forward(EXM 2, PRBLM 3) Here is this problem, can you explain it to me and show how its done. Thank you I need to see the work for like prbl solving.arrow_forwardcan someone draw out the reaction mechanism for this reaction showing all bonds, intermediates and side products Comment on the general features of the 1H-NMR spectrum of isoamyl ester provided belowarrow_forward
- What would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 3 2. n-BuLi • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Click and drag to start drawing a structure.arrow_forwardIdentify the missing organic reactants in the following reaction: X + Y H+ two steps Note: This chemical equation only focuses on the important organic molecules in the reaction. Additional inorganic or small-molecule reactants or products (like H2O) are not shown. In the drawing area below, draw the skeletal ("line") structures of the missing organic reactants X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Click and drag to start drawing a structure. Х :arrow_forwardDraw the mechanism of friedel-crafts acylation using acetyl chloride of m-Xylenearrow_forward
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