Give IUPAC names for the following compounds:

Question

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Answer 1

Textbook Question

Chapter 17.SE, Problem 20VC

Give IUPAC names for the following compounds:

Chapter 17.SE, Problem 20VC, Give IUPAC names for the following compounds:

Expert Solution

Interpretation Introduction

a)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 1

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix–ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending–e with–ol. The akane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

If the compound is chiral then there can be two types of arrangements of the four groups attached to the chiral carbon, R and S. The four groups are arranged in the order of priority as 1,2,3 and 4 following sequence rules. The molecule is viewed by orienting the group of lowest priority (4) points away from the observer. If the arrangement of highest to second highest to third highest is clockwise the R configuration is assigned. If the arrangement is anticlockwise then S configurationis assigned.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 2

Its IUPAC name is (R) - 5 methylhexan-3-ol.

Explanation of Solution

The name of the compound indicates the presence of a six carbon straight chain with –OH on C₃ and a methyl group on C₅. Further the molecule is chiral. The groups –OH (highest ranking), -CH₂CH(CH₃)₂(second highest ranking) and -CH₂CH₃(third highest ranking) are arranged around the chiral carbon in clockwise arrangement. Hence R configuration is assigned.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 3

Its IUPAC name is (R) - 5 methylhexan-3-ol.

Expert Solution

Interpretation Introduction

b)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 4

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing–e of the cycloalkene with–ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons with substituents.

A cis 1,3-disubstituted cycloalkane has the two substituent groups in a diequatorial arrangement.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 5

Its IUPAC name is cis-3-methylcyclohexanol.

Explanation of Solution

The structure shows that the compound contains a cyclohexane ring with a –OH and methyl groups in diequatorial positions on C₁ and C₃. Hence it is a cis-isomer.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 6

Its IUPAC name is cis-3-methylcyclohexanol.

Expert Solution

Interpretation Introduction

c)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 7

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix–ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending–e with–ol. He akane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

If the compound is chiral then there can be two types of arrangements of the four groups attached to the chiral carbon, R and S. The four groups are arranged in the order of priority as 1,2,3 and 4 following sequence rules. The molecule is viewed by orienting the group of lowest priority (4) points away from the observer. If the arrangement of highest to second highest to third highest is clockwise the R configuration is assigned. If the arrangement is anticlockwise then S configurationis assigned.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 8

Its IUPAC name is (S)-1-cyclopentylethanol.

Explanation of Solution

The structure shows that the compound contains a two carbon straight chain with –OH and a cyclopentyl groups on C₁.

The four groups, -OH(Highest priority), Cyclopentyl (second highest priority), methyl (third highest priority) attached to C₁ are arranged anticlockwise when viewed away from hydrogen (fourth priority). Hence S configuration is assigned.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 9

Its IUPAC name is (S)-1-cyclopentylethanol.

Expert Solution

Interpretation Introduction

d)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 10

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is.

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 11

Its IUPAC name is 4-methyl-3-nitrophenol.

Explanation of Solution

The structure of the compound shows a benzene ring with –OH on C₁, a nitro group on C₃ and a methyl group on C₄.

Conclusion

The compound given is.

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 12

Its IUPAC name is 4-methyl-3-nitrophenol.

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Answer 2

Textbook Question

Chapter 17.SE, Problem 20VC

Give IUPAC names for the following compounds:

Chapter 17.SE, Problem 20VC, Give IUPAC names for the following compounds:

Expert Solution

Interpretation Introduction

a)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 1

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix–ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending–e with–ol. The akane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

If the compound is chiral then there can be two types of arrangements of the four groups attached to the chiral carbon, R and S. The four groups are arranged in the order of priority as 1,2,3 and 4 following sequence rules. The molecule is viewed by orienting the group of lowest priority (4) points away from the observer. If the arrangement of highest to second highest to third highest is clockwise the R configuration is assigned. If the arrangement is anticlockwise then S configurationis assigned.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 2

Its IUPAC name is (R) - 5 methylhexan-3-ol.

Explanation of Solution

The name of the compound indicates the presence of a six carbon straight chain with –OH on C₃ and a methyl group on C₅. Further the molecule is chiral. The groups –OH (highest ranking), -CH₂CH(CH₃)₂(second highest ranking) and -CH₂CH₃(third highest ranking) are arranged around the chiral carbon in clockwise arrangement. Hence R configuration is assigned.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 3

Its IUPAC name is (R) - 5 methylhexan-3-ol.

Expert Solution

Interpretation Introduction

b)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 4

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing–e of the cycloalkene with–ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons with substituents.

A cis 1,3-disubstituted cycloalkane has the two substituent groups in a diequatorial arrangement.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 5

Its IUPAC name is cis-3-methylcyclohexanol.

Explanation of Solution

The structure shows that the compound contains a cyclohexane ring with a –OH and methyl groups in diequatorial positions on C₁ and C₃. Hence it is a cis-isomer.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 6

Its IUPAC name is cis-3-methylcyclohexanol.

Expert Solution

Interpretation Introduction

c)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 7

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix–ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending–e with–ol. He akane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

If the compound is chiral then there can be two types of arrangements of the four groups attached to the chiral carbon, R and S. The four groups are arranged in the order of priority as 1,2,3 and 4 following sequence rules. The molecule is viewed by orienting the group of lowest priority (4) points away from the observer. If the arrangement of highest to second highest to third highest is clockwise the R configuration is assigned. If the arrangement is anticlockwise then S configurationis assigned.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 8

Its IUPAC name is (S)-1-cyclopentylethanol.

Explanation of Solution

The structure shows that the compound contains a two carbon straight chain with –OH and a cyclopentyl groups on C₁.

The four groups, -OH(Highest priority), Cyclopentyl (second highest priority), methyl (third highest priority) attached to C₁ are arranged anticlockwise when viewed away from hydrogen (fourth priority). Hence S configuration is assigned.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 9

Its IUPAC name is (S)-1-cyclopentylethanol.

Expert Solution

Interpretation Introduction

d)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 10

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is.

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 11

Its IUPAC name is 4-methyl-3-nitrophenol.

Explanation of Solution

The structure of the compound shows a benzene ring with –OH on C₁, a nitro group on C₃ and a methyl group on C₄.

Conclusion

The compound given is.

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 12

Its IUPAC name is 4-methyl-3-nitrophenol.

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Answer 3

Textbook Question

Chapter 17.SE, Problem 20VC

Give IUPAC names for the following compounds:

Chapter 17.SE, Problem 20VC, Give IUPAC names for the following compounds:

Expert Solution

Interpretation Introduction

a)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 1

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix–ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending–e with–ol. The akane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

If the compound is chiral then there can be two types of arrangements of the four groups attached to the chiral carbon, R and S. The four groups are arranged in the order of priority as 1,2,3 and 4 following sequence rules. The molecule is viewed by orienting the group of lowest priority (4) points away from the observer. If the arrangement of highest to second highest to third highest is clockwise the R configuration is assigned. If the arrangement is anticlockwise then S configurationis assigned.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 2

Its IUPAC name is (R) - 5 methylhexan-3-ol.

Explanation of Solution

The name of the compound indicates the presence of a six carbon straight chain with –OH on C₃ and a methyl group on C₅. Further the molecule is chiral. The groups –OH (highest ranking), -CH₂CH(CH₃)₂(second highest ranking) and -CH₂CH₃(third highest ranking) are arranged around the chiral carbon in clockwise arrangement. Hence R configuration is assigned.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 3

Its IUPAC name is (R) - 5 methylhexan-3-ol.

Expert Solution

Interpretation Introduction

b)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 4

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing–e of the cycloalkene with–ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons with substituents.

A cis 1,3-disubstituted cycloalkane has the two substituent groups in a diequatorial arrangement.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 5

Its IUPAC name is cis-3-methylcyclohexanol.

Explanation of Solution

The structure shows that the compound contains a cyclohexane ring with a –OH and methyl groups in diequatorial positions on C₁ and C₃. Hence it is a cis-isomer.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 6

Its IUPAC name is cis-3-methylcyclohexanol.

Expert Solution

Interpretation Introduction

c)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 7

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix–ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending–e with–ol. He akane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

If the compound is chiral then there can be two types of arrangements of the four groups attached to the chiral carbon, R and S. The four groups are arranged in the order of priority as 1,2,3 and 4 following sequence rules. The molecule is viewed by orienting the group of lowest priority (4) points away from the observer. If the arrangement of highest to second highest to third highest is clockwise the R configuration is assigned. If the arrangement is anticlockwise then S configurationis assigned.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 8

Its IUPAC name is (S)-1-cyclopentylethanol.

Explanation of Solution

The structure shows that the compound contains a two carbon straight chain with –OH and a cyclopentyl groups on C₁.

The four groups, -OH(Highest priority), Cyclopentyl (second highest priority), methyl (third highest priority) attached to C₁ are arranged anticlockwise when viewed away from hydrogen (fourth priority). Hence S configuration is assigned.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 9

Its IUPAC name is (S)-1-cyclopentylethanol.

Expert Solution

Interpretation Introduction

d)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 10

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is.

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 11

Its IUPAC name is 4-methyl-3-nitrophenol.

Explanation of Solution

The structure of the compound shows a benzene ring with –OH on C₁, a nitro group on C₃ and a methyl group on C₄.

Conclusion

The compound given is.

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 12

Its IUPAC name is 4-methyl-3-nitrophenol.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 17.SE, Problem 20VC

Give IUPAC names for the following compounds:

Chapter 17.SE, Problem 20VC, Give IUPAC names for the following compounds:

Expert Solution

Interpretation Introduction

a)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 1

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix–ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending–e with–ol. The akane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

If the compound is chiral then there can be two types of arrangements of the four groups attached to the chiral carbon, R and S. The four groups are arranged in the order of priority as 1,2,3 and 4 following sequence rules. The molecule is viewed by orienting the group of lowest priority (4) points away from the observer. If the arrangement of highest to second highest to third highest is clockwise the R configuration is assigned. If the arrangement is anticlockwise then S configurationis assigned.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 2

Its IUPAC name is (R) - 5 methylhexan-3-ol.

Explanation of Solution

The name of the compound indicates the presence of a six carbon straight chain with –OH on C₃ and a methyl group on C₅. Further the molecule is chiral. The groups –OH (highest ranking), -CH₂CH(CH₃)₂(second highest ranking) and -CH₂CH₃(third highest ranking) are arranged around the chiral carbon in clockwise arrangement. Hence R configuration is assigned.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 3

Its IUPAC name is (R) - 5 methylhexan-3-ol.

Expert Solution

Interpretation Introduction

b)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 4

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing–e of the cycloalkene with–ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons with substituents.

A cis 1,3-disubstituted cycloalkane has the two substituent groups in a diequatorial arrangement.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 5

Its IUPAC name is cis-3-methylcyclohexanol.

Explanation of Solution

The structure shows that the compound contains a cyclohexane ring with a –OH and methyl groups in diequatorial positions on C₁ and C₃. Hence it is a cis-isomer.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 6

Its IUPAC name is cis-3-methylcyclohexanol.

Expert Solution

Interpretation Introduction

c)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 7

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix–ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending–e with–ol. He akane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

If the compound is chiral then there can be two types of arrangements of the four groups attached to the chiral carbon, R and S. The four groups are arranged in the order of priority as 1,2,3 and 4 following sequence rules. The molecule is viewed by orienting the group of lowest priority (4) points away from the observer. If the arrangement of highest to second highest to third highest is clockwise the R configuration is assigned. If the arrangement is anticlockwise then S configurationis assigned.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 8

Its IUPAC name is (S)-1-cyclopentylethanol.

Explanation of Solution

The structure shows that the compound contains a two carbon straight chain with –OH and a cyclopentyl groups on C₁.

The four groups, -OH(Highest priority), Cyclopentyl (second highest priority), methyl (third highest priority) attached to C₁ are arranged anticlockwise when viewed away from hydrogen (fourth priority). Hence S configuration is assigned.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 9

Its IUPAC name is (S)-1-cyclopentylethanol.

Expert Solution

Interpretation Introduction

d)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 10

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is.

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 11

Its IUPAC name is 4-methyl-3-nitrophenol.

Explanation of Solution

The structure of the compound shows a benzene ring with –OH on C₁, a nitro group on C₃ and a methyl group on C₄.

Conclusion

The compound given is.

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 12

Its IUPAC name is 4-methyl-3-nitrophenol.

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution

Interpretation Introduction

a)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 1

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix–ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending–e with–ol. The akane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

If the compound is chiral then there can be two types of arrangements of the four groups attached to the chiral carbon, R and S. The four groups are arranged in the order of priority as 1,2,3 and 4 following sequence rules. The molecule is viewed by orienting the group of lowest priority (4) points away from the observer. If the arrangement of highest to second highest to third highest is clockwise the R configuration is assigned. If the arrangement is anticlockwise then S configurationis assigned.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 2

Its IUPAC name is (R) - 5 methylhexan-3-ol.

Explanation of Solution

The name of the compound indicates the presence of a six carbon straight chain with –OH on C₃ and a methyl group on C₅. Further the molecule is chiral. The groups –OH (highest ranking), -CH₂CH(CH₃)₂(second highest ranking) and -CH₂CH₃(third highest ranking) are arranged around the chiral carbon in clockwise arrangement. Hence R configuration is assigned.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 3

Its IUPAC name is (R) - 5 methylhexan-3-ol.

Expert Solution

Interpretation Introduction

b)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 4

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing–e of the cycloalkene with–ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons with substituents.

A cis 1,3-disubstituted cycloalkane has the two substituent groups in a diequatorial arrangement.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 5

Its IUPAC name is cis-3-methylcyclohexanol.

Explanation of Solution

The structure shows that the compound contains a cyclohexane ring with a –OH and methyl groups in diequatorial positions on C₁ and C₃. Hence it is a cis-isomer.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 6

Its IUPAC name is cis-3-methylcyclohexanol.

Expert Solution

Interpretation Introduction

c)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 7

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix–ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending–e with–ol. He akane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

If the compound is chiral then there can be two types of arrangements of the four groups attached to the chiral carbon, R and S. The four groups are arranged in the order of priority as 1,2,3 and 4 following sequence rules. The molecule is viewed by orienting the group of lowest priority (4) points away from the observer. If the arrangement of highest to second highest to third highest is clockwise the R configuration is assigned. If the arrangement is anticlockwise then S configurationis assigned.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 8

Its IUPAC name is (S)-1-cyclopentylethanol.

Explanation of Solution

The structure shows that the compound contains a two carbon straight chain with –OH and a cyclopentyl groups on C₁.

The four groups, -OH(Highest priority), Cyclopentyl (second highest priority), methyl (third highest priority) attached to C₁ are arranged anticlockwise when viewed away from hydrogen (fourth priority). Hence S configuration is assigned.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 9

Its IUPAC name is (S)-1-cyclopentylethanol.

Expert Solution

Interpretation Introduction

d)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 10

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is.

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 11

Its IUPAC name is 4-methyl-3-nitrophenol.

Explanation of Solution

The structure of the compound shows a benzene ring with –OH on C₁, a nitro group on C₃ and a methyl group on C₄.

Conclusion

The compound given is.

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 12

Its IUPAC name is 4-methyl-3-nitrophenol.

Answer 8

Expert Solution

Interpretation Introduction

a)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 1

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix–ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending–e with–ol. The akane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

If the compound is chiral then there can be two types of arrangements of the four groups attached to the chiral carbon, R and S. The four groups are arranged in the order of priority as 1,2,3 and 4 following sequence rules. The molecule is viewed by orienting the group of lowest priority (4) points away from the observer. If the arrangement of highest to second highest to third highest is clockwise the R configuration is assigned. If the arrangement is anticlockwise then S configurationis assigned.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 2

Its IUPAC name is (R) - 5 methylhexan-3-ol.

Explanation of Solution

The name of the compound indicates the presence of a six carbon straight chain with –OH on C₃ and a methyl group on C₅. Further the molecule is chiral. The groups –OH (highest ranking), -CH₂CH(CH₃)₂(second highest ranking) and -CH₂CH₃(third highest ranking) are arranged around the chiral carbon in clockwise arrangement. Hence R configuration is assigned.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 3

Its IUPAC name is (R) - 5 methylhexan-3-ol.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Interpretation Introduction

a)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 1

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix–ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending–e with–ol. The akane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

If the compound is chiral then there can be two types of arrangements of the four groups attached to the chiral carbon, R and S. The four groups are arranged in the order of priority as 1,2,3 and 4 following sequence rules. The molecule is viewed by orienting the group of lowest priority (4) points away from the observer. If the arrangement of highest to second highest to third highest is clockwise the R configuration is assigned. If the arrangement is anticlockwise then S configurationis assigned.

To give:

The IUPAC name of the compound given.

Answer 13

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 2

Its IUPAC name is (R) - 5 methylhexan-3-ol.

Answer 14

Explanation of Solution

The name of the compound indicates the presence of a six carbon straight chain with –OH on C₃ and a methyl group on C₅. Further the molecule is chiral. The groups –OH (highest ranking), -CH₂CH(CH₃)₂(second highest ranking) and -CH₂CH₃(third highest ranking) are arranged around the chiral carbon in clockwise arrangement. Hence R configuration is assigned.

Answer 15

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 3

Its IUPAC name is (R) - 5 methylhexan-3-ol.

Answer 16

Expert Solution

Interpretation Introduction

b)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 4

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing–e of the cycloalkene with–ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons with substituents.

A cis 1,3-disubstituted cycloalkane has the two substituent groups in a diequatorial arrangement.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 5

Its IUPAC name is cis-3-methylcyclohexanol.

Explanation of Solution

The structure shows that the compound contains a cyclohexane ring with a –OH and methyl groups in diequatorial positions on C₁ and C₃. Hence it is a cis-isomer.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 6

Its IUPAC name is cis-3-methylcyclohexanol.

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Interpretation Introduction

b)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 4

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing–e of the cycloalkene with–ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons with substituents.

A cis 1,3-disubstituted cycloalkane has the two substituent groups in a diequatorial arrangement.

To give:

The IUPAC name of the compound given.

Answer 21

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 5

Its IUPAC name is cis-3-methylcyclohexanol.

Answer 22

Explanation of Solution

The structure shows that the compound contains a cyclohexane ring with a –OH and methyl groups in diequatorial positions on C₁ and C₃. Hence it is a cis-isomer.

Answer 23

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 6

Its IUPAC name is cis-3-methylcyclohexanol.

Answer 24

Expert Solution

Interpretation Introduction

c)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 7

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix–ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending–e with–ol. He akane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

If the compound is chiral then there can be two types of arrangements of the four groups attached to the chiral carbon, R and S. The four groups are arranged in the order of priority as 1,2,3 and 4 following sequence rules. The molecule is viewed by orienting the group of lowest priority (4) points away from the observer. If the arrangement of highest to second highest to third highest is clockwise the R configuration is assigned. If the arrangement is anticlockwise then S configurationis assigned.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 8

Its IUPAC name is (S)-1-cyclopentylethanol.

Explanation of Solution

The structure shows that the compound contains a two carbon straight chain with –OH and a cyclopentyl groups on C₁.

The four groups, -OH(Highest priority), Cyclopentyl (second highest priority), methyl (third highest priority) attached to C₁ are arranged anticlockwise when viewed away from hydrogen (fourth priority). Hence S configuration is assigned.

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 9

Its IUPAC name is (S)-1-cyclopentylethanol.

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Interpretation Introduction

c)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 7

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix–ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending–e with–ol. He akane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

If the compound is chiral then there can be two types of arrangements of the four groups attached to the chiral carbon, R and S. The four groups are arranged in the order of priority as 1,2,3 and 4 following sequence rules. The molecule is viewed by orienting the group of lowest priority (4) points away from the observer. If the arrangement of highest to second highest to third highest is clockwise the R configuration is assigned. If the arrangement is anticlockwise then S configurationis assigned.

To give:

The IUPAC name of the compound given.

Answer 29

Answer to Problem 20VC

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 8

Its IUPAC name is (S)-1-cyclopentylethanol.

Answer 30

Explanation of Solution

The structure shows that the compound contains a two carbon straight chain with –OH and a cyclopentyl groups on C₁.

The four groups, -OH(Highest priority), Cyclopentyl (second highest priority), methyl (third highest priority) attached to C₁ are arranged anticlockwise when viewed away from hydrogen (fourth priority). Hence S configuration is assigned.

Answer 31

Conclusion

The compound given is

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 9

Its IUPAC name is (S)-1-cyclopentylethanol.

Answer 32

Expert Solution

Interpretation Introduction

d)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 10

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To give:

The IUPAC name of the compound given.

Answer to Problem 20VC

The compound given is.

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 11

Its IUPAC name is 4-methyl-3-nitrophenol.

Explanation of Solution

The structure of the compound shows a benzene ring with –OH on C₁, a nitro group on C₃ and a methyl group on C₄.

Conclusion

The compound given is.

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 12

Its IUPAC name is 4-methyl-3-nitrophenol.

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

Interpretation Introduction

d)

Organic Chemistry, Chapter 17.SE, Problem 20VC , additional homework tip 10

Interpretation:

To give the IUPAC name of the compound given.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To give:

The IUPAC name of the compound given.