
Concept explainers
Interpretation:
A structure for the alcohol with molecular formula C9H12O and the following spectral data is to be proposed.
1HNMR: 0.88 δ (triplet,Rel.area=3.00); 1.80 δ (quintet, Rel.area=2.00); 2.32 δ (Rel.area=1.00); 4.54 δ (triplet, Rel.area=1.00); 7.24 δ (Rel.area=5.00).
Concept introduction:
In 1HNMR spectrum, the alcoholic proton absorption occurs in the range 3.4 δ - 4.5 δ while that of phenolic proton occur in the range 3.0 to 8.0. The
The absorption due to 10 alkyl group (CH3) is seen around 0.7 δ - 1.3 δ, that due to a 20 alkyl group (CH2) is seen around 1.2 δ - 1.6 δ while that due to 30 alkyl group (CH) is seen around 1.4 δ - 1.8 δ The multiplicity of a signal gives an idea about the protons present in the adjacent carbons.
To propose:
A structure for the alcohol with molecular formula C9H12O and the following spectral data is to be proposed.
1HNMR: 0.88 δ (triplet,Rel.area=3.00); 1.80 δ (quintet, Rel.area=2.00); 2.32 δ (Rel.area=1.00); 4.54 δ (triplet, Rel.area=1.00); 7.24 δ (Rel.area=5.00).
b)
C8H10O2
Interpretation:
A structure for the alcohol with molecular formula C8H10O2 and the following spectral data is to be proposed.
IR: 3500 cm-1,
1HNMR: 2.60 δ (Rel.area=1.00); 3.76 δ (Rel.area=3.00); 4.53 δ (Rel.area=2.00); 6.85 δ (Rel.area=2.00); 7.23 δ (Rel.area=2.00).
Concept introduction:
In 1HNMR spectrum, the alcoholic proton absorption occurs in the range 3.4 δ - 4.5 δ while that of phenolic proton occur in the range 3.0 to 8.0. The aromatic protons give a broad peak in the range 6.5 δ - 8.0 δ, the benzylic protons normally absorb in the region 2.3 δ - 3.0 δ.
To propose:
A structure for the alcohol with molecular formula C8H10O2 and the following spectral data is to be proposed.
1HNMR: 2.60 δ (Rel.area=1.00); 3.76 δ (Rel.area=3.00); 4.53 δ (Rel.area=2.00); 6.85 δ (Rel.area=2.00); 7.23 δ (Rel.area=2.00).

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Chapter 17 Solutions
Organic Chemistry
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- 2) Draw the correct chemical structure (using line-angle drawings / "line structures") from their given IUPAC name: a. (E)-1-chloro-3,4,5-trimethylhex-2-ene b. (Z)-4,5,7-trimethyloct-4-en-2-ol C. (2E,6Z)-4-methylocta-2,6-dienearrow_forwardපිපිම Draw curved arrows to represent the flow of electrons in the reaction on the left Label the reactants on the left as either "Acid" or "Base" (iii) Decide which direction the equilibrium arrows will point in each reaction, based on the given pk, values (a) + H-O H 3-H + (c) H" H + H****H 000 44-00 NH₂ (e) i Дон OH Ө NHarrow_forward3) Label the configuration in each of the following alkenes as E, Z, or N/A (for non-stereogenic centers). 00 E 000 N/A E Br N/A N/A (g) E N/A OH E (b) Oz N/A Br (d) 00 E Z N/A E (f) Oz N/A E (h) Z N/Aarrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning

